Pre-Algebra Examples

$(- 16, - 15)$ , $(16, - 15)$

Step 1

Use $y = m x + b$ to calculate the equation of the line, where $m$ represents the slope and $b$ represents the y-intercept.

To calculate the equation of the line, use the $y = m x + b$ format.

Step 2

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{(change in y)}{(change in x)}$

Step 3

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Step 4

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 15 - (- 15)}{16 - (- 16)}$

Step 5

Finding the slope $m$ .

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Step 5.1

Simplify the numerator.

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Step 5.1.1

Multiply $- 1$ by $- 15$ .

$m = \frac{- 15 + 15}{16 - (- 16)}$

Step 5.1.2

Add $- 15$ and $15$ .

$m = \frac{0}{16 - (- 16)}$

Step 5.2

Simplify the denominator.

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Step 5.2.1

Multiply $- 1$ by $- 16$ .

$m = \frac{0}{16 + 16}$

Step 5.2.2

Add $16$ and $16$ .

$m = \frac{0}{32}$

Step 5.3

Divide $0$ by $32$ .

$m = 0$

Step 6

Find the value of $b$ using the formula for the equation of a line.

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Step 6.1

Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Step 6.2

Substitute the value of $m$ into the equation.

$y = (0) \cdot x + b$

Step 6.3

Substitute the value of $x$ into the equation.

$y = (0) \cdot (- 16) + b$

Step 6.4

Substitute the value of $y$ into the equation.

$- 15 = (0) \cdot (- 16) + b$

Step 6.5

Find the value of $b$ .

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Step 6.5.1

Rewrite the equation as $(0) \cdot (- 16) + b = - 15$ .

$(0) \cdot (- 16) + b = - 15$

Step 6.5.2

Simplify $(0) \cdot (- 16) + b$ .

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Step 6.5.2.1

Multiply $0$ by $- 16$ .

$0 + b = - 15$

Step 6.5.2.2

Add $0$ and $b$ .

$b = - 15$

Step 7

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = - 15$

Step 8