Pre-Algebra Examples

$- 5 = 10 - 8 x$

Step 1

Solve for $y$ .

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Step 1.1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$10 - 8 x = - 5$

Step 1.2

Move all terms not containing $x$ to the right side of the equation.

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Step 1.2.1

Subtract $10$ from both sides of the equation.

$- 8 x = - 5 - 10$

Step 1.2.2

Subtract $10$ from $- 5$ .

$- 8 x = - 15$

Step 1.3

Divide each term in $- 8 x = - 15$ by $- 8$ and simplify.

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Step 1.3.1

Divide each term in $- 8 x = - 15$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{- 15}{- 8}$

Step 1.3.2

Simplify the left side.

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Step 1.3.2.1

Cancel the common factor of $- 8$ .

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Step 1.3.2.1.1

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{- 15}{- 8}$

Step 1.3.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 15}{- 8}$

Step 1.3.3

Simplify the right side.

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Step 1.3.3.1

Dividing two negative values results in a positive value.

$x = \frac{15}{8}$

Step 2

Since $x = \frac{15}{8}$ is a vertical line, there is no y-intercept and the slope is undefined.

Slope: Undefined

y-intercept: No y-intercept

Step 3

Find two points on the line.

$\begin{array}{c} x & y \\ \frac{15}{8} & 0 \\ \frac{15}{8} & 1 \end{array}$

Step 4

Graph the line using the slope, y-intercept, and two points.

Slope: Undefined

y-intercept: No y-intercept

$\begin{array}{c} x & y \\ \frac{15}{8} & 0 \\ \frac{15}{8} & 1 \end{array}$

Step 5