Pre-Algebra Examples

$2 x - 2 y + 5 = 0$

Step 1

Solve for $y$ .

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Step 1.1

Move all terms not containing $y$ to the right side of the equation.

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Step 1.1.1

Subtract $2 x$ from both sides of the equation.

$- 2 y + 5 = - 2 x$

Step 1.1.2

Subtract $5$ from both sides of the equation.

$- 2 y = - 2 x - 5$

Step 1.2

Divide each term in $- 2 y = - 2 x - 5$ by $- 2$ and simplify.

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Step 1.2.1

Divide each term in $- 2 y = - 2 x - 5$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 2 x}{- 2} + \frac{- 5}{- 2}$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $- 2$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 2 x}{- 2} + \frac{- 5}{- 2}$

Step 1.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{- 2 x}{- 2} + \frac{- 5}{- 2}$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Cancel the common factor of $- 2$ .

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Step 1.2.3.1.1.1

Cancel the common factor.

$y = \frac{- 2 x}{- 2} + \frac{- 5}{- 2}$

Step 1.2.3.1.1.2

Divide $x$ by $1$ .

$y = x + \frac{- 5}{- 2}$

Step 1.2.3.1.2

Dividing two negative values results in a positive value.

$y = x + \frac{5}{2}$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

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Step 2.1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2.2

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = \frac{5}{2}$

Step 2.3

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, \frac{5}{2})$

Slope: $1$

y-intercept: $(0, \frac{5}{2})$

Step 3

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

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Step 3.1

Find the x-intercept.

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Step 3.1.1

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = x + \frac{5}{2}$

Step 3.1.2

Solve the equation.

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Step 3.1.2.1

Rewrite the equation as $x + \frac{5}{2} = 0$ .

$x + \frac{5}{2} = 0$

Step 3.1.2.2

Subtract $\frac{5}{2}$ from both sides of the equation.

$x = - \frac{5}{2}$

Step 3.1.3

x-intercept(s) in point form.

x-intercept(s): $(- \frac{5}{2}, 0)$

Step 3.2

Find the y-intercept.

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Step 3.2.1

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = (0) + \frac{5}{2}$

Step 3.2.2

Solve the equation.

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Step 3.2.2.1

Remove parentheses.

$y = 0 + \frac{5}{2}$

Step 3.2.2.2

Remove parentheses.

$y = (0) + \frac{5}{2}$

Step 3.2.2.3

Add $0$ and $\frac{5}{2}$ .

$y = \frac{5}{2}$

Step 3.2.3

y-intercept(s) in point form.

y-intercept(s): $(0, \frac{5}{2})$

Step 3.3

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ - \frac{5}{2} & 0 \\ 0 & \frac{5}{2} \end{array}$

Step 4

Graph the line using the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $(0, \frac{5}{2})$

$\begin{array}{c} x & y \\ - \frac{5}{2} & 0 \\ 0 & \frac{5}{2} \end{array}$

Step 5