Pre-Algebra Examples

$y = - 2 x^{2 + 1}$

Step 1

Find the point at $x = - 2$ .

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Step 1.1

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = - 2 {(- 2)}^{3}$

Step 1.2

Simplify the result.

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Step 1.2.1

Multiply $- 2$ by ${(- 2)}^{3}$ by adding the exponents.

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Step 1.2.1.1

Multiply $- 2$ by ${(- 2)}^{3}$ .

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Step 1.2.1.1.1

Raise $- 2$ to the power of $1$ .

$f (- 2) = (- 2) {(- 2)}^{3}$

Step 1.2.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (- 2) = {(- 2)}^{1 + 3}$

Step 1.2.1.2

Add $1$ and $3$ .

$f (- 2) = {(- 2)}^{4}$

Step 1.2.2

Raise $- 2$ to the power of $4$ .

$f (- 2) = 16$

Step 1.2.3

The final answer is $16$ .

$16$

Step 1.3

Convert $16$ to decimal.

$y = 16$

Step 2

Find the point at $x = - 1$ .

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Step 2.1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - 2 {(- 1)}^{3}$

Step 2.2

Simplify the result.

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Step 2.2.1

Raise $- 1$ to the power of $3$ .

$f (- 1) = - 2 \cdot - 1$

Step 2.2.2

Multiply $- 2$ by $- 1$ .

$f (- 1) = 2$

Step 2.2.3

The final answer is $2$ .

$2$

Step 2.3

Convert $2$ to decimal.

$y = 2$

Step 3

Find the point at $x = 0$ .

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Step 3.1

Replace the variable $x$ with $0$ in the expression.

$f (0) = - 2 {(0)}^{3}$

Step 3.2

Simplify the result.

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Step 3.2.1

Raising $0$ to any positive power yields $0$ .

$f (0) = - 2 \cdot 0$

Step 3.2.2

Multiply $- 2$ by $0$ .

$f (0) = 0$

Step 3.2.3

The final answer is $0$ .

$0$

Step 3.3

Convert $0$ to decimal.

$y = 0$

Step 4

Find the point at $x = 1$ .

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Step 4.1

Replace the variable $x$ with $1$ in the expression.

$f (1) = - 2 {(1)}^{3}$

Step 4.2

Simplify the result.

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Step 4.2.1

One to any power is one.

$f (1) = - 2 \cdot 1$

Step 4.2.2

Multiply $- 2$ by $1$ .

$f (1) = - 2$

Step 4.2.3

The final answer is $- 2$ .

$- 2$

Step 4.3

Convert $- 2$ to decimal.

$y = - 2$

Step 5

Find the point at $x = 2$ .

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Step 5.1

Replace the variable $x$ with $2$ in the expression.

$f (2) = - 2 {(2)}^{3}$

Step 5.2

Simplify the result.

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Step 5.2.1

Raise $2$ to the power of $3$ .

$f (2) = - 2 \cdot 8$

Step 5.2.2

Multiply $- 2$ by $8$ .

$f (2) = - 16$

Step 5.2.3

The final answer is $- 16$ .

$- 16$

Step 5.3

Convert $- 16$ to decimal.

$y = - 16$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & 16 \\ - 1 & 2 \\ 0 & 0 \\ 1 & - 2 \\ 2 & - 16 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Rises to the left and falls to the right

$\begin{array}{c} x & y \\ - 2 & 16 \\ - 1 & 2 \\ 0 & 0 \\ 1 & - 2 \\ 2 & - 16 \end{array}$

Step 8