Pre-Algebra Examples

$\frac{1}{3 x - 3} + \frac{1}{4 x + 4} = \frac{1}{12 x - 12}$

Step 1

Simplify each term.

Tap for more steps...

Step 1.1

Factor $3$ out of $3 x - 3$ .

Tap for more steps...

Step 1.1.1

Factor $3$ out of $3 x$ .

$\frac{1}{3 (x) - 3} + \frac{1}{4 x + 4} = \frac{1}{12 x - 12}$

Step 1.1.2

Factor $3$ out of $- 3$ .

$\frac{1}{3 (x) + 3 (- 1)} + \frac{1}{4 x + 4} = \frac{1}{12 x - 12}$

Step 1.1.3

Factor $3$ out of $3 (x) + 3 (- 1)$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 x + 4} = \frac{1}{12 x - 12}$

Step 1.2

Factor $4$ out of $4 x + 4$ .

Tap for more steps...

Step 1.2.1

Factor $4$ out of $4 x$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 (x) + 4} = \frac{1}{12 x - 12}$

Step 1.2.2

Factor $4$ out of $4$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 (x) + 4 (1)} = \frac{1}{12 x - 12}$

Step 1.2.3

Factor $4$ out of $4 (x) + 4 (1)$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 (x + 1)} = \frac{1}{12 x - 12}$

Step 2

Factor $12$ out of $12 x - 12$ .

Tap for more steps...

Step 2.1

Factor $12$ out of $12 x$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 (x + 1)} = \frac{1}{12 (x) - 12}$

Step 2.2

Factor $12$ out of $- 12$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 (x + 1)} = \frac{1}{12 (x) + 12 (- 1)}$

Step 2.3

Factor $12$ out of $12 (x) + 12 (- 1)$ .

$\frac{1}{3 (x - 1)} + \frac{1}{4 (x + 1)} = \frac{1}{12 (x - 1)}$

Step 3

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x = 0$

Step 4