Pre-Algebra Examples

$\sqrt{16} - x + 7 = \sqrt{5 - x + 10}$

Step 1

Simplify $\sqrt{16} - x + 7$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Rewrite $16$ as $4^{2}$ .

$\sqrt{4^{2}} - x + 7 = \sqrt{5 - x + 10}$

Step 1.1.2

Pull terms out from under the radical, assuming positive real numbers.

$4 - x + 7 = \sqrt{5 - x + 10}$

Step 1.2

Add $4$ and $7$ .

$- x + 11 = \sqrt{5 - x + 10}$

Step 2

Add $5$ and $10$ .

$- x + 11 = \sqrt{- x + 15}$

Step 3

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx 8.43844718$

Step 4