Pre-Algebra Examples

$2 (x + 8) = 2 \cdot x + 2 \cdot 8$

Step 1

Simplify $2 (x + 8)$ .

Tap for more steps...

Step 1.1

Apply the distributive property.

$2 x + 2 \cdot 8 = 2 \cdot x + 2 \cdot 8$

Step 1.2

Multiply $2$ by $8$ .

$2 x + 16 = 2 \cdot x + 2 \cdot 8$

Step 2

Multiply $2$ by $8$ .

$2 x + 16 = 2 x + 16$

Step 3

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx 0.3, \frac{2}{5}, \frac{1}{2}, \frac{4}{5}, 0.9, 1, \frac{6}{5}, 1.3, \frac{7}{5}, \frac{8}{5}, 1.7, 2.1, \frac{11}{5}, \frac{13}{5}, 2.7, 2.9, 3, \frac{17}{5}, \frac{7}{2}, 3.7, \frac{19}{5}, 8.1, \frac{41}{5}, 8.3, \frac{42}{5}, \frac{17}{2}, \frac{43}{5}, 8.7, \frac{44}{5}, 8.9, 9, 9.1, \frac{46}{5}, \frac{47}{5}, \frac{48}{5}, 9.7, \frac{49}{5}, 9.9, 10.1, \frac{51}{5}, 10.3, \frac{52}{5}, \frac{21}{2}, 10.7, \frac{54}{5}, 10.9, 11, 11.1, 11.3, \frac{57}{5}, \frac{23}{2}, \frac{58}{5}, \frac{59}{5}, 11.9, 12, 12.1, 12.3, \frac{62}{5}, \frac{25}{2}, 12.6, 12.8, 12.9, 13, 13.1, 13.3, \frac{27}{2}, 13.6, 13.7, 13.8, 14, 14.1, 14.2, 14.3, \frac{29}{2}, 14.7, 14.8, 15, 15.2, 15.3, 15.4, \frac{31}{2}, 15.7, 15.9, 16, 24, 24.1, 24.4, 24.5, 24.6, 24.7, 24.8, 24.9, 25, 25.1, 25.2, 25.3, 25.4, 25.5, 25.6, 25.7, 25.8, 25.9, 26, 26.1, 26.2, 26.3, 26.4, 26.5, 26.6, 26.7, 26.8, 26.9, 27, 27.1, 27.2, 27.3, 27.4, 27.5, 27.6, 27.7, 27.8, 27.9, 28, 28.1, 28.2, 28.3, 28.4, 28.5, 28.6, 28.7, 28.8, 28.9, 29, 29.1, 29.2, 29.3, 29.4, 29.5, 29.6, 29.7, 29.8, 29.9, 30, 30.1, 30.2, 30.3, 30.6, 30.7, 30.8, 30.9, 31, 31.1, 31.2, 31.3, 31.4, 31.5, 31.6, 31.7, 31.8, 31.9, 32$

Step 4