Pre-Algebra Examples

$8 d - 3 (2 d - 4) = 3 (2 d - 4) - 4 d$

Step 1

Simplify $8 d - 3 (2 d - 4)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$8 d - 3 (2 d) - 3 \cdot - 4 = 3 (2 d - 4) - 4 d$

Step 1.1.2

Multiply $2$ by $- 3$ .

$8 d - 6 d - 3 \cdot - 4 = 3 (2 d - 4) - 4 d$

Step 1.1.3

Multiply $- 3$ by $- 4$ .

$8 d - 6 d + 12 = 3 (2 d - 4) - 4 d$

Step 1.2

Subtract $6 d$ from $8 d$ .

$2 d + 12 = 3 (2 d - 4) - 4 d$

Step 2

Simplify $3 (2 d - 4) - 4 d$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$2 d + 12 = 3 (2 d) + 3 \cdot - 4 - 4 d$

Step 2.1.2

Multiply $2$ by $3$ .

$2 d + 12 = 6 d + 3 \cdot - 4 - 4 d$

Step 2.1.3

Multiply $3$ by $- 4$ .

$2 d + 12 = 6 d - 12 - 4 d$

Step 2.2

Subtract $4 d$ from $6 d$ .

$2 d + 12 = 2 d - 12$

Step 3

Graph each side of the equation. The solution is the x-value of the point of intersection.

No solution

Step 4