Pre-Algebra Examples

$4 x - 3 y = 12$ , $x + y = 3$ , $x = 0$ , $y = - 7$

Step 1

Replace all occurrences of $x$ with $0$ in each equation.

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Step 1.1

Replace all occurrences of $x$ in $4 x - 3 y = 12$ with $0$ .

$4 (0) - 3 y = 12$

$x = 0$

$x + y = 3$

$y = - 7$

Step 1.2

Simplify the left side.

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Step 1.2.1

Simplify $4 (0) - 3 y$ .

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Step 1.2.1.1

Multiply $4$ by $0$ .

$0 - 3 y = 12$

$x = 0$

$x + y = 3$

$y = - 7$

Step 1.2.1.2

Subtract $3 y$ from $0$ .

$- 3 y = 12$

$x = 0$

$x + y = 3$

$y = - 7$

$- 3 y = 12$

$x = 0$

$x + y = 3$

$y = - 7$

$- 3 y = 12$

$x = 0$

$x + y = 3$

$y = - 7$

Step 1.3

Replace all occurrences of $x$ in $x + y = 3$ with $0$ .

$(0) + y = 3$

$- 3 y = 12$

$x = 0$

$y = - 7$

Step 1.4

Simplify the left side.

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Step 1.4.1

Add $0$ and $y$ .

$y = 3$

$- 3 y = 12$

$x = 0$

$y = - 7$

$y = 3$

$- 3 y = 12$

$x = 0$

$y = - 7$

$y = 3$

$- 3 y = 12$

$x = 0$

$y = - 7$

Step 2

Replace all occurrences of $y$ with $3$ in each equation.

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Step 2.1

Replace all occurrences of $y$ in $- 3 y = 12$ with $3$ .

$- 3 \cdot 3 = 12$

$y = 3$

$x = 0$

$y = - 7$

Step 2.2

Simplify the left side.

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Step 2.2.1

Multiply $- 3$ by $3$ .

$- 9 = 12$

$y = 3$

$x = 0$

$y = - 7$

$- 9 = 12$

$y = 3$

$x = 0$

$y = - 7$

$- 9 = 12$

$y = 3$

$x = 0$

$y = - 7$

Step 3

Since $- 9 = 12$ is not true, there is no solution.

No solution

Step 4