Pre-Algebra Examples

$\begin{array}{c} x & y \\ 3 & 2 \\ 5 & 2 \\ 7 & 4 \\ 11 & 2 \\ 13 & 4 \\ 17 & 2 \\ 19 & 4 \\ 23 & 6 \\ 29 & 2 \end{array}$

Step 1

Check if the function rule is linear.

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Step 1.1

To find if the table follows a function rule, check to see if the values follow the linear form $y = a x + b$ .

$y = a x + b$

Step 1.2

Build a set of equations from the table such that $y = a x + b$ .

$2 = a (3) + b 2 = a (5) + b 4 = a (7) + b 2 = a (11) + b 4 = a (13) + b 2 = a (17) + b 4 = a (19) + b 6 = a (23) + b 2 = a (29) + b$

Step 1.3

Calculate the values of $a$ and $b$ .

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Step 1.3.1

Solve for $b$ in $2 = a (3) + b$ .

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Step 1.3.1.1

Rewrite the equation as $a (3) + b = 2$ .

$a (3) + b = 2$

$2 = a (5) + b$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.1.2

Move $3$ to the left of $a$ .

$3 a + b = 2$

$2 = a (5) + b$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.1.3

Subtract $3 a$ from both sides of the equation.

$b = 2 - 3 a$

$2 = a (5) + b$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$b = 2 - 3 a$

$2 = a (5) + b$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2

Replace all occurrences of $b$ with $2 - 3 a$ in each equation.

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Step 1.3.2.1

Replace all occurrences of $b$ in $2 = a (5) + b$ with $2 - 3 a$ .

$2 = a (5) + 2 - 3 a$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.2

Simplify $2 = a (5) + 2 - 3 a$ .

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Step 1.3.2.2.1

Simplify the left side.

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Step 1.3.2.2.1.1

Remove parentheses.

$2 = a (5) + 2 - 3 a$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = a (5) + 2 - 3 a$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.2.2

Simplify the right side.

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Step 1.3.2.2.2.1

Simplify $a (5) + 2 - 3 a$ .

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Step 1.3.2.2.2.1.1

Move $5$ to the left of $a$ .

$2 = 5 a + 2 - 3 a$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.2.2.1.2

Subtract $3 a$ from $5 a$ .

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (7) + b$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.3

Replace all occurrences of $b$ in $4 = a (7) + b$ with $2 - 3 a$ .

$4 = a (7) + 2 - 3 a$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.4

Simplify $4 = a (7) + 2 - 3 a$ .

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Step 1.3.2.4.1

Simplify the left side.

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Step 1.3.2.4.1.1

Remove parentheses.

$4 = a (7) + 2 - 3 a$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = a (7) + 2 - 3 a$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.4.2

Simplify the right side.

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Step 1.3.2.4.2.1

Simplify $a (7) + 2 - 3 a$ .

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Step 1.3.2.4.2.1.1

Move $7$ to the left of $a$ .

$4 = 7 a + 2 - 3 a$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.4.2.1.2

Subtract $3 a$ from $7 a$ .

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (11) + b$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.5

Replace all occurrences of $b$ in $2 = a (11) + b$ with $2 - 3 a$ .

$2 = a (11) + 2 - 3 a$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.6

Simplify $2 = a (11) + 2 - 3 a$ .

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Step 1.3.2.6.1

Simplify the left side.

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Step 1.3.2.6.1.1

Remove parentheses.

$2 = a (11) + 2 - 3 a$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = a (11) + 2 - 3 a$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.6.2

Simplify the right side.

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Step 1.3.2.6.2.1

Simplify $a (11) + 2 - 3 a$ .

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Step 1.3.2.6.2.1.1

Move $11$ to the left of $a$ .

$2 = 11 a + 2 - 3 a$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.6.2.1.2

Subtract $3 a$ from $11 a$ .

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (13) + b$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.7

Replace all occurrences of $b$ in $4 = a (13) + b$ with $2 - 3 a$ .

$4 = a (13) + 2 - 3 a$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.8

Simplify $4 = a (13) + 2 - 3 a$ .

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Step 1.3.2.8.1

Simplify the left side.

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Step 1.3.2.8.1.1

Remove parentheses.

$4 = a (13) + 2 - 3 a$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = a (13) + 2 - 3 a$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.8.2

Simplify the right side.

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Step 1.3.2.8.2.1

Simplify $a (13) + 2 - 3 a$ .

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Step 1.3.2.8.2.1.1

Move $13$ to the left of $a$ .

$4 = 13 a + 2 - 3 a$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.8.2.1.2

Subtract $3 a$ from $13 a$ .

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (17) + b$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.9

Replace all occurrences of $b$ in $2 = a (17) + b$ with $2 - 3 a$ .

$2 = a (17) + 2 - 3 a$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.10

Simplify $2 = a (17) + 2 - 3 a$ .

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Step 1.3.2.10.1

Simplify the left side.

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Step 1.3.2.10.1.1

Remove parentheses.

$2 = a (17) + 2 - 3 a$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = a (17) + 2 - 3 a$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.10.2

Simplify the right side.

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Step 1.3.2.10.2.1

Simplify $a (17) + 2 - 3 a$ .

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Step 1.3.2.10.2.1.1

Move $17$ to the left of $a$ .

$2 = 17 a + 2 - 3 a$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.10.2.1.2

Subtract $3 a$ from $17 a$ .

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = a (19) + b$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.11

Replace all occurrences of $b$ in $4 = a (19) + b$ with $2 - 3 a$ .

$4 = a (19) + 2 - 3 a$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.12

Simplify $4 = a (19) + 2 - 3 a$ .

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Step 1.3.2.12.1

Simplify the left side.

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Step 1.3.2.12.1.1

Remove parentheses.

$4 = a (19) + 2 - 3 a$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = a (19) + 2 - 3 a$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.12.2

Simplify the right side.

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Step 1.3.2.12.2.1

Simplify $a (19) + 2 - 3 a$ .

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Step 1.3.2.12.2.1.1

Move $19$ to the left of $a$ .

$4 = 19 a + 2 - 3 a$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.12.2.1.2

Subtract $3 a$ from $19 a$ .

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = a (23) + b$

$2 = a (29) + b$

Step 1.3.2.13

Replace all occurrences of $b$ in $6 = a (23) + b$ with $2 - 3 a$ .

$6 = a (23) + 2 - 3 a$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

Step 1.3.2.14

Simplify $6 = a (23) + 2 - 3 a$ .

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Step 1.3.2.14.1

Simplify the left side.

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Step 1.3.2.14.1.1

Remove parentheses.

$6 = a (23) + 2 - 3 a$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

$6 = a (23) + 2 - 3 a$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

Step 1.3.2.14.2

Simplify the right side.

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Step 1.3.2.14.2.1

Simplify $a (23) + 2 - 3 a$ .

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Step 1.3.2.14.2.1.1

Move $23$ to the left of $a$ .

$6 = 23 a + 2 - 3 a$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

Step 1.3.2.14.2.1.2

Subtract $3 a$ from $23 a$ .

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + b$

Step 1.3.2.15

Replace all occurrences of $b$ in $2 = a (29) + b$ with $2 - 3 a$ .

$2 = a (29) + 2 - 3 a$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.2.16

Simplify $2 = a (29) + 2 - 3 a$ .

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Step 1.3.2.16.1

Simplify the left side.

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Step 1.3.2.16.1.1

Remove parentheses.

$2 = a (29) + 2 - 3 a$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = a (29) + 2 - 3 a$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.2.16.2

Simplify the right side.

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Step 1.3.2.16.2.1

Simplify $a (29) + 2 - 3 a$ .

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Step 1.3.2.16.2.1.1

Move $29$ to the left of $a$ .

$2 = 29 a + 2 - 3 a$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.2.16.2.1.2

Subtract $3 a$ from $29 a$ .

$2 = 26 a + 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 26 a + 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 26 a + 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 26 a + 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 26 a + 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3

Solve for $a$ in $2 = 26 a + 2$ .

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Step 1.3.3.1

Rewrite the equation as $26 a + 2 = 2$ .

$26 a + 2 = 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3.2

Move all terms not containing $a$ to the right side of the equation.

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Step 1.3.3.2.1

Subtract $2$ from both sides of the equation.

$26 a = 2 - 2$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3.2.2

Subtract $2$ from $2$ .

$26 a = 0$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$26 a = 0$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3.3

Divide each term in $26 a = 0$ by $26$ and simplify.

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Step 1.3.3.3.1

Divide each term in $26 a = 0$ by $26$ .

$\frac{26 a}{26} = \frac{0}{26}$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3.3.2

Simplify the left side.

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Step 1.3.3.3.2.1

Cancel the common factor of $26$ .

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Step 1.3.3.3.2.1.1

Cancel the common factor.

$\frac{26 a}{26} = \frac{0}{26}$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3.3.2.1.2

Divide $a$ by $1$ .

$a = \frac{0}{26}$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$a = \frac{0}{26}$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$a = \frac{0}{26}$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.3.3.3

Simplify the right side.

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Step 1.3.3.3.3.1

Divide $0$ by $26$ .

$a = 0$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$a = 0$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$a = 0$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$a = 0$

$6 = 20 a + 2$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4

Replace all occurrences of $a$ with $0$ in each equation.

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Step 1.3.4.1

Replace all occurrences of $a$ in $6 = 20 a + 2$ with $0$ .

$6 = 20 (0) + 2$

$a = 0$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.2

Simplify the right side.

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Step 1.3.4.2.1

Simplify $20 (0) + 2$ .

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Step 1.3.4.2.1.1

Multiply $20$ by $0$ .

$6 = 0 + 2$

$a = 0$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.2.1.2

Add $0$ and $2$ .

$6 = 2$

$a = 0$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = 2$

$a = 0$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$6 = 2$

$a = 0$

$4 = 16 a + 2$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.3

Replace all occurrences of $a$ in $4 = 16 a + 2$ with $0$ .

$4 = 16 (0) + 2$

$6 = 2$

$a = 0$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.4

Simplify the right side.

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Step 1.3.4.4.1

Simplify $16 (0) + 2$ .

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Step 1.3.4.4.1.1

Multiply $16$ by $0$ .

$4 = 0 + 2$

$6 = 2$

$a = 0$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.4.1.2

Add $0$ and $2$ .

$4 = 2$

$6 = 2$

$a = 0$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 14 a + 2$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.5

Replace all occurrences of $a$ in $2 = 14 a + 2$ with $0$ .

$2 = 14 (0) + 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.6

Simplify the right side.

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Step 1.3.4.6.1

Simplify $14 (0) + 2$ .

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Step 1.3.4.6.1.1

Multiply $14$ by $0$ .

$2 = 0 + 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.6.1.2

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 10 a + 2$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.7

Replace all occurrences of $a$ in $4 = 10 a + 2$ with $0$ .

$4 = 10 (0) + 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.8

Simplify the right side.

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Step 1.3.4.8.1

Simplify $10 (0) + 2$ .

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Step 1.3.4.8.1.1

Multiply $10$ by $0$ .

$4 = 0 + 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.8.1.2

Add $0$ and $2$ .

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 8 a + 2$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.9

Replace all occurrences of $a$ in $2 = 8 a + 2$ with $0$ .

$2 = 8 (0) + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.10

Simplify the right side.

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Step 1.3.4.10.1

Simplify $8 (0) + 2$ .

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Step 1.3.4.10.1.1

Multiply $8$ by $0$ .

$2 = 0 + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.10.1.2

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 4 a + 2$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.11

Replace all occurrences of $a$ in $4 = 4 a + 2$ with $0$ .

$4 = 4 (0) + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.12

Simplify the right side.

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Step 1.3.4.12.1

Simplify $4 (0) + 2$ .

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Step 1.3.4.12.1.1

Multiply $4$ by $0$ .

$4 = 0 + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.12.1.2

Add $0$ and $2$ .

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 2 a + 2$

$b = 2 - 3 a$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 2 a + 2$

$b = 2 - 3 a$

Step 1.3.4.13

Replace all occurrences of $a$ in $2 = 2 a + 2$ with $0$ .

$2 = 2 (0) + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2 - 3 a$

Step 1.3.4.14

Simplify the right side.

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Step 1.3.4.14.1

Simplify $2 (0) + 2$ .

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Step 1.3.4.14.1.1

Multiply $2$ by $0$ .

$2 = 0 + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2 - 3 a$

Step 1.3.4.14.1.2

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2 - 3 a$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2 - 3 a$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2 - 3 a$

Step 1.3.4.15

Replace all occurrences of $a$ in $b = 2 - 3 a$ with $0$ .

$b = 2 - 3 \cdot 0$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

Step 1.3.4.16

Simplify the right side.

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Step 1.3.4.16.1

Simplify $2 - 3 \cdot 0$ .

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Step 1.3.4.16.1.1

Multiply $- 3$ by $0$ .

$b = 2 + 0$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

Step 1.3.4.16.1.2

Add $2$ and $0$ .

$b = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$b = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

Step 1.3.5

Since $4 = 2$ is not true, there is no solution.

No solution

Step 1.4

Since $y \neq y$ for the corresponding $x$ values, the function is not linear.

The function is not linear

Step 2

Check if the function rule is quadratic.

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Step 2.1

To find if the table follows a function rule, check whether the function rule could follow the form $y = a x^{2} + b x + c$ .

$y = a x^{2} + b x + c$

Step 2.2

Build a set of $3$ equations from the table such that $y = a x^{2} + b x + c$ .

Step 2.3

Calculate the values of $a$ , $b$ , and $c$ .

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Step 2.3.1

Solve for $c$ in $2 = a \cdot 3^{2} + b (3) + c$ .

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Step 2.3.1.1

Rewrite the equation as $a \cdot 3^{2} + b (3) + c = 2$ .

$a \cdot 3^{2} + b (3) + c = 2$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.1.2

Simplify each term.

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Step 2.3.1.2.1

Raise $3$ to the power of $2$ .

$a \cdot 9 + b (3) + c = 2$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.1.2.2

Move $9$ to the left of $a$ .

$9 \cdot a + b (3) + c = 2$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.1.2.3

Move $3$ to the left of $b$ .

$9 a + 3 b + c = 2$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$9 a + 3 b + c = 2$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.1.3

Move all terms not containing $c$ to the right side of the equation.

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Step 2.3.1.3.1

Subtract $9 a$ from both sides of the equation.

$3 b + c = 2 - 9 a$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.1.3.2

Subtract $3 b$ from both sides of the equation.

$c = 2 - 9 a - 3 b$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 5^{2} + b (5) + c$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2

Replace all occurrences of $c$ with $2 - 9 a - 3 b$ in each equation.

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Step 2.3.2.1

Replace all occurrences of $c$ in $2 = a \cdot 5^{2} + b (5) + c$ with $2 - 9 a - 3 b$ .

$2 = a \cdot 5^{2} + b (5) + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.2

Simplify $2 = a \cdot 5^{2} + b (5) + 2 - 9 a - 3 b$ .

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Step 2.3.2.2.1

Simplify the left side.

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Step 2.3.2.2.1.1

Remove parentheses.

$2 = a \cdot 5^{2} + b (5) + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = a \cdot 5^{2} + b (5) + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.2.2

Simplify the right side.

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Step 2.3.2.2.2.1

Simplify $a \cdot 5^{2} + b (5) + 2 - 9 a - 3 b$ .

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Step 2.3.2.2.2.1.1

Simplify each term.

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Step 2.3.2.2.2.1.1.1

Raise $5$ to the power of $2$ .

$2 = a \cdot 25 + b (5) + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.2.2.1.1.2

Move $25$ to the left of $a$ .

$2 = 25 \cdot a + b (5) + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.2.2.1.1.3

Move $5$ to the left of $b$ .

$2 = 25 a + 5 b + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 25 a + 5 b + 2 - 9 a - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.2.2.1.2

Simplify by adding terms.

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Step 2.3.2.2.2.1.2.1

Subtract $9 a$ from $25 a$ .

$2 = 16 a + 5 b + 2 - 3 b$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.2.2.1.2.2

Subtract $3 b$ from $5 b$ .

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 7^{2} + b (7) + c$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.3

Replace all occurrences of $c$ in $4 = a \cdot 7^{2} + b (7) + c$ with $2 - 9 a - 3 b$ .

$4 = a \cdot 7^{2} + b (7) + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.4

Simplify $4 = a \cdot 7^{2} + b (7) + 2 - 9 a - 3 b$ .

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Step 2.3.2.4.1

Simplify the left side.

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Step 2.3.2.4.1.1

Remove parentheses.

$4 = a \cdot 7^{2} + b (7) + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = a \cdot 7^{2} + b (7) + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.4.2

Simplify the right side.

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Step 2.3.2.4.2.1

Simplify $a \cdot 7^{2} + b (7) + 2 - 9 a - 3 b$ .

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Step 2.3.2.4.2.1.1

Simplify each term.

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Step 2.3.2.4.2.1.1.1

Raise $7$ to the power of $2$ .

$4 = a \cdot 49 + b (7) + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.4.2.1.1.2

Move $49$ to the left of $a$ .

$4 = 49 \cdot a + b (7) + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.4.2.1.1.3

Move $7$ to the left of $b$ .

$4 = 49 a + 7 b + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 49 a + 7 b + 2 - 9 a - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.4.2.1.2

Simplify by adding terms.

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Step 2.3.2.4.2.1.2.1

Subtract $9 a$ from $49 a$ .

$4 = 40 a + 7 b + 2 - 3 b$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.4.2.1.2.2

Subtract $3 b$ from $7 b$ .

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 11^{2} + b (11) + c$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.5

Replace all occurrences of $c$ in $2 = a \cdot 11^{2} + b (11) + c$ with $2 - 9 a - 3 b$ .

$2 = a \cdot 11^{2} + b (11) + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.6

Simplify $2 = a \cdot 11^{2} + b (11) + 2 - 9 a - 3 b$ .

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Step 2.3.2.6.1

Simplify the left side.

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Step 2.3.2.6.1.1

Remove parentheses.

$2 = a \cdot 11^{2} + b (11) + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = a \cdot 11^{2} + b (11) + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.6.2

Simplify the right side.

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Step 2.3.2.6.2.1

Simplify $a \cdot 11^{2} + b (11) + 2 - 9 a - 3 b$ .

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Step 2.3.2.6.2.1.1

Simplify each term.

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Step 2.3.2.6.2.1.1.1

Raise $11$ to the power of $2$ .

$2 = a \cdot 121 + b (11) + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.6.2.1.1.2

Move $121$ to the left of $a$ .

$2 = 121 \cdot a + b (11) + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.6.2.1.1.3

Move $11$ to the left of $b$ .

$2 = 121 a + 11 b + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 121 a + 11 b + 2 - 9 a - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.6.2.1.2

Simplify by adding terms.

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Step 2.3.2.6.2.1.2.1

Subtract $9 a$ from $121 a$ .

$2 = 112 a + 11 b + 2 - 3 b$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.6.2.1.2.2

Subtract $3 b$ from $11 b$ .

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 13^{2} + b (13) + c$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.7

Replace all occurrences of $c$ in $4 = a \cdot 13^{2} + b (13) + c$ with $2 - 9 a - 3 b$ .

$4 = a \cdot 13^{2} + b (13) + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.8

Simplify $4 = a \cdot 13^{2} + b (13) + 2 - 9 a - 3 b$ .

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Step 2.3.2.8.1

Simplify the left side.

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Step 2.3.2.8.1.1

Remove parentheses.

$4 = a \cdot 13^{2} + b (13) + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = a \cdot 13^{2} + b (13) + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.8.2

Simplify the right side.

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Step 2.3.2.8.2.1

Simplify $a \cdot 13^{2} + b (13) + 2 - 9 a - 3 b$ .

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Step 2.3.2.8.2.1.1

Simplify each term.

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Step 2.3.2.8.2.1.1.1

Raise $13$ to the power of $2$ .

$4 = a \cdot 169 + b (13) + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.8.2.1.1.2

Move $169$ to the left of $a$ .

$4 = 169 \cdot a + b (13) + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.8.2.1.1.3

Move $13$ to the left of $b$ .

$4 = 169 a + 13 b + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 169 a + 13 b + 2 - 9 a - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.8.2.1.2

Simplify by adding terms.

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Step 2.3.2.8.2.1.2.1

Subtract $9 a$ from $169 a$ .

$4 = 160 a + 13 b + 2 - 3 b$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.8.2.1.2.2

Subtract $3 b$ from $13 b$ .

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 17^{2} + b (17) + c$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.9

Replace all occurrences of $c$ in $2 = a \cdot 17^{2} + b (17) + c$ with $2 - 9 a - 3 b$ .

$2 = a \cdot 17^{2} + b (17) + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.10

Simplify $2 = a \cdot 17^{2} + b (17) + 2 - 9 a - 3 b$ .

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Step 2.3.2.10.1

Simplify the left side.

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Step 2.3.2.10.1.1

Remove parentheses.

$2 = a \cdot 17^{2} + b (17) + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = a \cdot 17^{2} + b (17) + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.10.2

Simplify the right side.

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Step 2.3.2.10.2.1

Simplify $a \cdot 17^{2} + b (17) + 2 - 9 a - 3 b$ .

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Step 2.3.2.10.2.1.1

Simplify each term.

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Step 2.3.2.10.2.1.1.1

Raise $17$ to the power of $2$ .

$2 = a \cdot 289 + b (17) + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.10.2.1.1.2

Move $289$ to the left of $a$ .

$2 = 289 \cdot a + b (17) + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.10.2.1.1.3

Move $17$ to the left of $b$ .

$2 = 289 a + 17 b + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 289 a + 17 b + 2 - 9 a - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.10.2.1.2

Simplify by adding terms.

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Step 2.3.2.10.2.1.2.1

Subtract $9 a$ from $289 a$ .

$2 = 280 a + 17 b + 2 - 3 b$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.10.2.1.2.2

Subtract $3 b$ from $17 b$ .

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = a \cdot 19^{2} + b (19) + c$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.11

Replace all occurrences of $c$ in $4 = a \cdot 19^{2} + b (19) + c$ with $2 - 9 a - 3 b$ .

$4 = a \cdot 19^{2} + b (19) + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.12

Simplify $4 = a \cdot 19^{2} + b (19) + 2 - 9 a - 3 b$ .

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Step 2.3.2.12.1

Simplify the left side.

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Step 2.3.2.12.1.1

Remove parentheses.

$4 = a \cdot 19^{2} + b (19) + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = a \cdot 19^{2} + b (19) + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.12.2

Simplify the right side.

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Step 2.3.2.12.2.1

Simplify $a \cdot 19^{2} + b (19) + 2 - 9 a - 3 b$ .

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Step 2.3.2.12.2.1.1

Simplify each term.

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Step 2.3.2.12.2.1.1.1

Raise $19$ to the power of $2$ .

$4 = a \cdot 361 + b (19) + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.12.2.1.1.2

Move $361$ to the left of $a$ .

$4 = 361 \cdot a + b (19) + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.12.2.1.1.3

Move $19$ to the left of $b$ .

$4 = 361 a + 19 b + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 361 a + 19 b + 2 - 9 a - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.12.2.1.2

Simplify by adding terms.

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Step 2.3.2.12.2.1.2.1

Subtract $9 a$ from $361 a$ .

$4 = 352 a + 19 b + 2 - 3 b$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.12.2.1.2.2

Subtract $3 b$ from $19 b$ .

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = a \cdot 23^{2} + b (23) + c$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.13

Replace all occurrences of $c$ in $6 = a \cdot 23^{2} + b (23) + c$ with $2 - 9 a - 3 b$ .

$6 = a \cdot 23^{2} + b (23) + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.14

Simplify $6 = a \cdot 23^{2} + b (23) + 2 - 9 a - 3 b$ .

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Step 2.3.2.14.1

Simplify the left side.

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Step 2.3.2.14.1.1

Remove parentheses.

$6 = a \cdot 23^{2} + b (23) + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

$6 = a \cdot 23^{2} + b (23) + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.14.2

Simplify the right side.

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Step 2.3.2.14.2.1

Simplify $a \cdot 23^{2} + b (23) + 2 - 9 a - 3 b$ .

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Step 2.3.2.14.2.1.1

Simplify each term.

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Step 2.3.2.14.2.1.1.1

Raise $23$ to the power of $2$ .

$6 = a \cdot 529 + b (23) + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.14.2.1.1.2

Move $529$ to the left of $a$ .

$6 = 529 \cdot a + b (23) + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.14.2.1.1.3

Move $23$ to the left of $b$ .

$6 = 529 a + 23 b + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

$6 = 529 a + 23 b + 2 - 9 a - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.14.2.1.2

Simplify by adding terms.

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Step 2.3.2.14.2.1.2.1

Subtract $9 a$ from $529 a$ .

$6 = 520 a + 23 b + 2 - 3 b$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.14.2.1.2.2

Subtract $3 b$ from $23 b$ .

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + c$

Step 2.3.2.15

Replace all occurrences of $c$ in $2 = a \cdot 29^{2} + b (29) + c$ with $2 - 9 a - 3 b$ .

$2 = a \cdot 29^{2} + b (29) + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.2.16

Simplify $2 = a \cdot 29^{2} + b (29) + 2 - 9 a - 3 b$ .

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Step 2.3.2.16.1

Simplify the left side.

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Step 2.3.2.16.1.1

Remove parentheses.

$2 = a \cdot 29^{2} + b (29) + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = a \cdot 29^{2} + b (29) + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.2.16.2

Simplify the right side.

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Step 2.3.2.16.2.1

Simplify $a \cdot 29^{2} + b (29) + 2 - 9 a - 3 b$ .

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Step 2.3.2.16.2.1.1

Simplify each term.

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Step 2.3.2.16.2.1.1.1

Raise $29$ to the power of $2$ .

$2 = a \cdot 841 + b (29) + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.2.16.2.1.1.2

Move $841$ to the left of $a$ .

$2 = 841 \cdot a + b (29) + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.2.16.2.1.1.3

Move $29$ to the left of $b$ .

$2 = 841 a + 29 b + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 841 a + 29 b + 2 - 9 a - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.2.16.2.1.2

Simplify by adding terms.

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Step 2.3.2.16.2.1.2.1

Subtract $9 a$ from $841 a$ .

$2 = 832 a + 29 b + 2 - 3 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.2.16.2.1.2.2

Subtract $3 b$ from $29 b$ .

$2 = 832 a + 26 b + 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 832 a + 26 b + 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 832 a + 26 b + 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 832 a + 26 b + 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 832 a + 26 b + 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 832 a + 26 b + 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3

Solve for $a$ in $2 = 832 a + 26 b + 2$ .

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Step 2.3.3.1

Rewrite the equation as $832 a + 26 b + 2 = 2$ .

$832 a + 26 b + 2 = 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.2

Move all terms not containing $a$ to the right side of the equation.

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Step 2.3.3.2.1

Subtract $26 b$ from both sides of the equation.

$832 a + 2 = 2 - 26 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.2.2

Subtract $2$ from both sides of the equation.

$832 a = 2 - 26 b - 2$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.2.3

Combine the opposite terms in $2 - 26 b - 2$ .

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Step 2.3.3.2.3.1

Subtract $2$ from $2$ .

$832 a = - 26 b + 0$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.2.3.2

Add $- 26 b$ and $0$ .

$832 a = - 26 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$832 a = - 26 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$832 a = - 26 b$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3

Divide each term in $832 a = - 26 b$ by $832$ and simplify.

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Step 2.3.3.3.1

Divide each term in $832 a = - 26 b$ by $832$ .

$\frac{832 a}{832} = \frac{- 26 b}{832}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.2

Simplify the left side.

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Step 2.3.3.3.2.1

Cancel the common factor of $832$ .

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Step 2.3.3.3.2.1.1

Cancel the common factor.

$\frac{832 a}{832} = \frac{- 26 b}{832}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.2.1.2

Divide $a$ by $1$ .

$a = \frac{- 26 b}{832}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = \frac{- 26 b}{832}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = \frac{- 26 b}{832}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.3

Simplify the right side.

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Step 2.3.3.3.3.1

Cancel the common factor of $- 26$ and $832$ .

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Step 2.3.3.3.3.1.1

Factor $26$ out of $- 26 b$ .

$a = \frac{26 (- b)}{832}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.3.1.2

Cancel the common factors.

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Step 2.3.3.3.3.1.2.1

Factor $26$ out of $832$ .

$a = \frac{26 (- b)}{26 (32)}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.3.1.2.2

Cancel the common factor.

$a = \frac{26 (- b)}{26 \cdot 32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.3.1.2.3

Rewrite the expression.

$a = \frac{- b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = \frac{- b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = \frac{- b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.3.3.3.2

Move the negative in front of the fraction.

$a = - \frac{b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = - \frac{b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = - \frac{b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$a = - \frac{b}{32}$

$6 = 520 a + 20 b + 2$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4

Replace all occurrences of $a$ with $- \frac{b}{32}$ in each equation.

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Step 2.3.4.1

Replace all occurrences of $a$ in $6 = 520 a + 20 b + 2$ with $- \frac{b}{32}$ .

$6 = 520 (- \frac{b}{32}) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2

Simplify the right side.

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Step 2.3.4.2.1

Simplify $520 (- \frac{b}{32}) + 20 b + 2$ .

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Step 2.3.4.2.1.1

Simplify each term.

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Step 2.3.4.2.1.1.1

Cancel the common factor of $8$ .

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Step 2.3.4.2.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$6 = 520 (\frac{- b}{32}) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.1.2

Factor $8$ out of $520$ .

$6 = 8 (65) (\frac{- b}{32}) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.1.3

Factor $8$ out of $32$ .

$6 = 8 \cdot (65 (\frac{- b}{8 \cdot 4})) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.1.4

Cancel the common factor.

$6 = 8 \cdot (65 (\frac{- b}{8 \cdot 4})) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.1.5

Rewrite the expression.

$6 = 65 (\frac{- b}{4}) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = 65 (\frac{- b}{4}) + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.2

Combine $65$ and $\frac{- b}{4}$ .

$6 = \frac{65 (- b)}{4} + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.3

Multiply $- 1$ by $65$ .

$6 = \frac{- 65 b}{4} + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.1.4

Move the negative in front of the fraction.

$6 = - \frac{65 b}{4} + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = - \frac{65 b}{4} + 20 b + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.2

To write $20 b$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$6 = - \frac{65 b}{4} + 20 b \cdot \frac{4}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.3

Simplify terms.

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Step 2.3.4.2.1.3.1

Combine $20 b$ and $\frac{4}{4}$ .

$6 = - \frac{65 b}{4} + \frac{20 b \cdot 4}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.3.2

Combine the numerators over the common denominator.

$6 = \frac{- 65 b + 20 b \cdot 4}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = \frac{- 65 b + 20 b \cdot 4}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.4

Simplify the numerator.

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Step 2.3.4.2.1.4.1

Factor $5 b$ out of $- 65 b + 20 b \cdot 4$ .

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Step 2.3.4.2.1.4.1.1

Factor $5 b$ out of $- 65 b$ .

$6 = \frac{5 b (- 13) + 20 b \cdot 4}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.4.1.2

Factor $5 b$ out of $20 b \cdot 4$ .

$6 = \frac{5 b (- 13) + 5 b (4 \cdot 4)}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.4.1.3

Factor $5 b$ out of $5 b (- 13) + 5 b (4 \cdot 4)$ .

$6 = \frac{5 b (- 13 + 4 \cdot 4)}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = \frac{5 b (- 13 + 4 \cdot 4)}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.4.2

Multiply $4$ by $4$ .

$6 = \frac{5 b (- 13 + 16)}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.4.3

Add $- 13$ and $16$ .

$6 = \frac{5 b \cdot 3}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.2.1.4.4

Multiply $3$ by $5$ .

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 352 a + 16 b + 2$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.3

Replace all occurrences of $a$ in $4 = 352 a + 16 b + 2$ with $- \frac{b}{32}$ .

$4 = 352 (- \frac{b}{32}) + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.4

Simplify the right side.

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Step 2.3.4.4.1

Simplify $352 (- \frac{b}{32}) + 16 b + 2$ .

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Step 2.3.4.4.1.1

Simplify each term.

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Step 2.3.4.4.1.1.1

Cancel the common factor of $32$ .

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Step 2.3.4.4.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$4 = 352 (\frac{- b}{32}) + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.4.1.1.1.2

Factor $32$ out of $352$ .

$4 = 32 (11) (\frac{- b}{32}) + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.4.1.1.1.3

Cancel the common factor.

$4 = 32 \cdot (11 (\frac{- b}{32})) + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.4.1.1.1.4

Rewrite the expression.

$4 = 11 (- b) + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 11 (- b) + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.4.1.1.2

Multiply $- 1$ by $11$ .

$4 = - 11 b + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = - 11 b + 16 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.4.1.2

Add $- 11 b$ and $16 b$ .

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 280 a + 14 b + 2$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.5

Replace all occurrences of $a$ in $2 = 280 a + 14 b + 2$ with $- \frac{b}{32}$ .

$2 = 280 (- \frac{b}{32}) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6

Simplify the right side.

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Step 2.3.4.6.1

Simplify $280 (- \frac{b}{32}) + 14 b + 2$ .

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Step 2.3.4.6.1.1

Simplify each term.

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Step 2.3.4.6.1.1.1

Cancel the common factor of $8$ .

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Step 2.3.4.6.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$2 = 280 (\frac{- b}{32}) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.1.2

Factor $8$ out of $280$ .

$2 = 8 (35) (\frac{- b}{32}) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.1.3

Factor $8$ out of $32$ .

$2 = 8 \cdot (35 (\frac{- b}{8 \cdot 4})) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.1.4

Cancel the common factor.

$2 = 8 \cdot (35 (\frac{- b}{8 \cdot 4})) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.1.5

Rewrite the expression.

$2 = 35 (\frac{- b}{4}) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 35 (\frac{- b}{4}) + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.2

Combine $35$ and $\frac{- b}{4}$ .

$2 = \frac{35 (- b)}{4} + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.3

Multiply $- 1$ by $35$ .

$2 = \frac{- 35 b}{4} + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.1.4

Move the negative in front of the fraction.

$2 = - \frac{35 b}{4} + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = - \frac{35 b}{4} + 14 b + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.2

To write $14 b$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$2 = - \frac{35 b}{4} + 14 b \cdot \frac{4}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.3

Simplify terms.

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Step 2.3.4.6.1.3.1

Combine $14 b$ and $\frac{4}{4}$ .

$2 = - \frac{35 b}{4} + \frac{14 b \cdot 4}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.3.2

Combine the numerators over the common denominator.

$2 = \frac{- 35 b + 14 b \cdot 4}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{- 35 b + 14 b \cdot 4}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.4

Simplify the numerator.

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Step 2.3.4.6.1.4.1

Factor $7 b$ out of $- 35 b + 14 b \cdot 4$ .

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Step 2.3.4.6.1.4.1.1

Factor $7 b$ out of $- 35 b$ .

$2 = \frac{7 b (- 5) + 14 b \cdot 4}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.4.1.2

Factor $7 b$ out of $14 b \cdot 4$ .

$2 = \frac{7 b (- 5) + 7 b (2 \cdot 4)}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.4.1.3

Factor $7 b$ out of $7 b (- 5) + 7 b (2 \cdot 4)$ .

$2 = \frac{7 b (- 5 + 2 \cdot 4)}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{7 b (- 5 + 2 \cdot 4)}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.4.2

Multiply $2$ by $4$ .

$2 = \frac{7 b (- 5 + 8)}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.4.3

Add $- 5$ and $8$ .

$2 = \frac{7 b \cdot 3}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.6.1.4.4

Multiply $3$ by $7$ .

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 160 a + 10 b + 2$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.7

Replace all occurrences of $a$ in $4 = 160 a + 10 b + 2$ with $- \frac{b}{32}$ .

$4 = 160 (- \frac{b}{32}) + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.8

Simplify the right side.

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Step 2.3.4.8.1

Simplify $160 (- \frac{b}{32}) + 10 b + 2$ .

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Step 2.3.4.8.1.1

Simplify each term.

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Step 2.3.4.8.1.1.1

Cancel the common factor of $32$ .

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Step 2.3.4.8.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$4 = 160 (\frac{- b}{32}) + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.8.1.1.1.2

Factor $32$ out of $160$ .

$4 = 32 (5) (\frac{- b}{32}) + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.8.1.1.1.3

Cancel the common factor.

$4 = 32 \cdot (5 (\frac{- b}{32})) + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.8.1.1.1.4

Rewrite the expression.

$4 = 5 (- b) + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 5 (- b) + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.8.1.1.2

Multiply $- 1$ by $5$ .

$4 = - 5 b + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = - 5 b + 10 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.8.1.2

Add $- 5 b$ and $10 b$ .

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 112 a + 8 b + 2$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.9

Replace all occurrences of $a$ in $2 = 112 a + 8 b + 2$ with $- \frac{b}{32}$ .

$2 = 112 (- \frac{b}{32}) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10

Simplify the right side.

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Step 2.3.4.10.1

Simplify $112 (- \frac{b}{32}) + 8 b + 2$ .

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Step 2.3.4.10.1.1

Simplify each term.

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Step 2.3.4.10.1.1.1

Cancel the common factor of $16$ .

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Step 2.3.4.10.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$2 = 112 (\frac{- b}{32}) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.1.2

Factor $16$ out of $112$ .

$2 = 16 (7) (\frac{- b}{32}) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.1.3

Factor $16$ out of $32$ .

$2 = 16 \cdot (7 (\frac{- b}{16 \cdot 2})) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.1.4

Cancel the common factor.

$2 = 16 \cdot (7 (\frac{- b}{16 \cdot 2})) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.1.5

Rewrite the expression.

$2 = 7 (\frac{- b}{2}) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = 7 (\frac{- b}{2}) + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.2

Combine $7$ and $\frac{- b}{2}$ .

$2 = \frac{7 (- b)}{2} + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.3

Multiply $- 1$ by $7$ .

$2 = \frac{- 7 b}{2} + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.1.4

Move the negative in front of the fraction.

$2 = - \frac{7 b}{2} + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = - \frac{7 b}{2} + 8 b + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.2

To write $8 b$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$2 = - \frac{7 b}{2} + 8 b \cdot \frac{2}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.3

Simplify terms.

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Step 2.3.4.10.1.3.1

Combine $8 b$ and $\frac{2}{2}$ .

$2 = - \frac{7 b}{2} + \frac{8 b \cdot 2}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.3.2

Combine the numerators over the common denominator.

$2 = \frac{- 7 b + 8 b \cdot 2}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{- 7 b + 8 b \cdot 2}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.4

Simplify each term.

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Step 2.3.4.10.1.4.1

Simplify the numerator.

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Step 2.3.4.10.1.4.1.1

Factor $b$ out of $- 7 b + 8 b \cdot 2$ .

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Step 2.3.4.10.1.4.1.1.1

Factor $b$ out of $- 7 b$ .

$2 = \frac{b \cdot - 7 + 8 b \cdot 2}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.4.1.1.2

Factor $b$ out of $8 b \cdot 2$ .

$2 = \frac{b \cdot - 7 + b (8 \cdot 2)}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.4.1.1.3

Factor $b$ out of $b \cdot - 7 + b (8 \cdot 2)$ .

$2 = \frac{b (- 7 + 8 \cdot 2)}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{b (- 7 + 8 \cdot 2)}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.4.1.2

Multiply $8$ by $2$ .

$2 = \frac{b (- 7 + 16)}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.4.1.3

Add $- 7$ and $16$ .

$2 = \frac{b \cdot 9}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{b \cdot 9}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.10.1.4.2

Move $9$ to the left of $b$ .

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 40 a + 4 b + 2$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.11

Replace all occurrences of $a$ in $4 = 40 a + 4 b + 2$ with $- \frac{b}{32}$ .

$4 = 40 (- \frac{b}{32}) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12

Simplify the right side.

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Step 2.3.4.12.1

Simplify $40 (- \frac{b}{32}) + 4 b + 2$ .

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Step 2.3.4.12.1.1

Simplify each term.

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Step 2.3.4.12.1.1.1

Cancel the common factor of $8$ .

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Step 2.3.4.12.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$4 = 40 (\frac{- b}{32}) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.1.2

Factor $8$ out of $40$ .

$4 = 8 (5) (\frac{- b}{32}) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.1.3

Factor $8$ out of $32$ .

$4 = 8 \cdot (5 (\frac{- b}{8 \cdot 4})) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.1.4

Cancel the common factor.

$4 = 8 \cdot (5 (\frac{- b}{8 \cdot 4})) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.1.5

Rewrite the expression.

$4 = 5 (\frac{- b}{4}) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = 5 (\frac{- b}{4}) + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.2

Combine $5$ and $\frac{- b}{4}$ .

$4 = \frac{5 (- b)}{4} + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.3

Multiply $- 1$ by $5$ .

$4 = \frac{- 5 b}{4} + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.1.4

Move the negative in front of the fraction.

$4 = - \frac{5 b}{4} + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = - \frac{5 b}{4} + 4 b + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.2

To write $4 b$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$4 = - \frac{5 b}{4} + 4 b \cdot \frac{4}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.3

Simplify terms.

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Step 2.3.4.12.1.3.1

Combine $4 b$ and $\frac{4}{4}$ .

$4 = - \frac{5 b}{4} + \frac{4 b \cdot 4}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.3.2

Combine the numerators over the common denominator.

$4 = \frac{- 5 b + 4 b \cdot 4}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = \frac{- 5 b + 4 b \cdot 4}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.4

Simplify each term.

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Step 2.3.4.12.1.4.1

Simplify the numerator.

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Step 2.3.4.12.1.4.1.1

Factor $b$ out of $- 5 b + 4 b \cdot 4$ .

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Step 2.3.4.12.1.4.1.1.1

Factor $b$ out of $- 5 b$ .

$4 = \frac{b \cdot - 5 + 4 b \cdot 4}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.4.1.1.2

Factor $b$ out of $4 b \cdot 4$ .

$4 = \frac{b \cdot - 5 + b (4 \cdot 4)}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.4.1.1.3

Factor $b$ out of $b \cdot - 5 + b (4 \cdot 4)$ .

$4 = \frac{b (- 5 + 4 \cdot 4)}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = \frac{b (- 5 + 4 \cdot 4)}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.4.1.2

Multiply $4$ by $4$ .

$4 = \frac{b (- 5 + 16)}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.4.1.3

Add $- 5$ and $16$ .

$4 = \frac{b \cdot 11}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = \frac{b \cdot 11}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.12.1.4.2

Move $11$ to the left of $b$ .

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 16 a + 2 b + 2$

$c = 2 - 9 a - 3 b$

Step 2.3.4.13

Replace all occurrences of $a$ in $2 = 16 a + 2 b + 2$ with $- \frac{b}{32}$ .

$2 = 16 (- \frac{b}{32}) + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14

Simplify the right side.

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Step 2.3.4.14.1

Simplify $16 (- \frac{b}{32}) + 2 b + 2$ .

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Step 2.3.4.14.1.1

Simplify each term.

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Step 2.3.4.14.1.1.1

Cancel the common factor of $16$ .

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Step 2.3.4.14.1.1.1.1

Move the leading negative in $- \frac{b}{32}$ into the numerator.

$2 = 16 (\frac{- b}{32}) + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.1.1.2

Factor $16$ out of $32$ .

$2 = 16 (\frac{- b}{16 (2)}) + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.1.1.3

Cancel the common factor.

$2 = 16 (\frac{- b}{16 \cdot 2}) + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.1.1.4

Rewrite the expression.

$2 = \frac{- b}{2} + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{- b}{2} + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.1.2

Move the negative in front of the fraction.

$2 = - \frac{b}{2} + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = - \frac{b}{2} + 2 b + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.2

To write $2 b$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$2 = - \frac{b}{2} + 2 b \cdot \frac{2}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.3

Simplify terms.

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Step 2.3.4.14.1.3.1

Combine $2 b$ and $\frac{2}{2}$ .

$2 = - \frac{b}{2} + \frac{2 b \cdot 2}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.3.2

Combine the numerators over the common denominator.

$2 = \frac{- b + 2 b \cdot 2}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{- b + 2 b \cdot 2}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.4

Simplify each term.

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Step 2.3.4.14.1.4.1

Simplify the numerator.

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Step 2.3.4.14.1.4.1.1

Factor $b$ out of $- b + 2 b \cdot 2$ .

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Step 2.3.4.14.1.4.1.1.1

Factor $b$ out of $- b$ .

$2 = \frac{b \cdot - 1 + 2 b \cdot 2}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.4.1.1.2

Factor $b$ out of $2 b \cdot 2$ .

$2 = \frac{b \cdot - 1 + b (2 \cdot 2)}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.4.1.1.3

Factor $b$ out of $b \cdot - 1 + b (2 \cdot 2)$ .

$2 = \frac{b (- 1 + 2 \cdot 2)}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{b (- 1 + 2 \cdot 2)}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.4.1.2

Multiply $2$ by $2$ .

$2 = \frac{b (- 1 + 4)}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.4.1.3

Add $- 1$ and $4$ .

$2 = \frac{b \cdot 3}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{b \cdot 3}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.14.1.4.2

Move $3$ to the left of $b$ .

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - 9 a - 3 b$

Step 2.3.4.15

Replace all occurrences of $a$ in $c = 2 - 9 a - 3 b$ with $- \frac{b}{32}$ .

$c = 2 - 9 (- \frac{b}{32}) - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16

Simplify the right side.

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Step 2.3.4.16.1

Simplify $2 - 9 (- \frac{b}{32}) - 3 b$ .

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Step 2.3.4.16.1.1

Multiply $- 9 (- \frac{b}{32})$ .

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Step 2.3.4.16.1.1.1

Multiply $- 1$ by $- 9$ .

$c = 2 + 9 (\frac{b}{32}) - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.1.2

Combine $9$ and $\frac{b}{32}$ .

$c = 2 + \frac{9 b}{32} - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 + \frac{9 b}{32} - 3 b$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.2

To write $- 3 b$ as a fraction with a common denominator, multiply by $\frac{32}{32}$ .

$c = 2 + \frac{9 b}{32} - 3 b \cdot \frac{32}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.3

Simplify terms.

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Step 2.3.4.16.1.3.1

Combine $- 3 b$ and $\frac{32}{32}$ .

$c = 2 + \frac{9 b}{32} + \frac{- 3 b \cdot 32}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.3.2

Combine the numerators over the common denominator.

$c = 2 + \frac{9 b - 3 b \cdot 32}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 + \frac{9 b - 3 b \cdot 32}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4

Simplify each term.

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Step 2.3.4.16.1.4.1

Simplify the numerator.

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Step 2.3.4.16.1.4.1.1

Factor $3 b$ out of $9 b - 3 b \cdot 32$ .

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Step 2.3.4.16.1.4.1.1.1

Factor $3 b$ out of $9 b$ .

$c = 2 + \frac{3 b (3) - 3 b \cdot 32}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4.1.1.2

Factor $3 b$ out of $- 3 b \cdot 32$ .

$c = 2 + \frac{3 b (3) + 3 b (- 1 \cdot 32)}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4.1.1.3

Factor $3 b$ out of $3 b (3) + 3 b (- 1 \cdot 32)$ .

$c = 2 + \frac{3 b (3 - 1 \cdot 32)}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 + \frac{3 b (3 - 1 \cdot 32)}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4.1.2

Multiply $- 1$ by $32$ .

$c = 2 + \frac{3 b (3 - 32)}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4.1.3

Subtract $32$ from $3$ .

$c = 2 + \frac{3 b \cdot - 29}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4.1.4

Multiply $- 29$ by $3$ .

$c = 2 + \frac{- 87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 + \frac{- 87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.4.16.1.4.2

Move the negative in front of the fraction.

$c = 2 - \frac{87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - \frac{87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - \frac{87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - \frac{87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - \frac{87 b}{32}$

$2 = \frac{3 b}{2} + 2$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$4 = 5 b + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5

Solve for $b$ in $2 = \frac{3 b}{2} + 2$ .

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Step 2.3.5.1

Rewrite the equation as $\frac{3 b}{2} + 2 = 2$ .

$\frac{3 b}{2} + 2 = 2$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.2

Move all terms not containing $b$ to the right side of the equation.

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Step 2.3.5.2.1

Subtract $2$ from both sides of the equation.

$\frac{3 b}{2} = 2 - 2$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.2.2

Subtract $2$ from $2$ .

$\frac{3 b}{2} = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$\frac{3 b}{2} = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.3

Set the numerator equal to zero.

$3 b = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.4

Divide each term in $3 b = 0$ by $3$ and simplify.

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Step 2.3.5.4.1

Divide each term in $3 b = 0$ by $3$ .

$\frac{3 b}{3} = \frac{0}{3}$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.4.2

Simplify the left side.

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Step 2.3.5.4.2.1

Cancel the common factor of $3$ .

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Step 2.3.5.4.2.1.1

Cancel the common factor.

$\frac{3 b}{3} = \frac{0}{3}$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.4.2.1.2

Divide $b$ by $1$ .

$b = \frac{0}{3}$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$b = \frac{0}{3}$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$b = \frac{0}{3}$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.5.4.3

Simplify the right side.

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Step 2.3.5.4.3.1

Divide $0$ by $3$ .

$b = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$b = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$b = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$b = 0$

$c = 2 - \frac{87 b}{32}$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6

Replace all occurrences of $b$ with $0$ in each equation.

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Step 2.3.6.1

Replace all occurrences of $b$ in $c = 2 - \frac{87 b}{32}$ with $0$ .

$c = 2 - \frac{87 (0)}{32}$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2

Simplify the right side.

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Step 2.3.6.2.1

Simplify $2 - \frac{87 (0)}{32}$ .

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Step 2.3.6.2.1.1

Simplify each term.

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Step 2.3.6.2.1.1.1

Cancel the common factor of $0$ and $32$ .

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Step 2.3.6.2.1.1.1.1

Factor $32$ out of $87 (0)$ .

$c = 2 - \frac{32 (87 \cdot (0))}{32}$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.1.1.2

Cancel the common factors.

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Step 2.3.6.2.1.1.1.2.1

Factor $32$ out of $32$ .

$c = 2 - \frac{32 (87 \cdot (0))}{32 (1)}$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.1.1.2.2

Cancel the common factor.

$c = 2 - \frac{32 (87 \cdot (0))}{32 \cdot 1}$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.1.1.2.3

Rewrite the expression.

$c = 2 - \frac{87 \cdot (0)}{1}$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.1.1.2.4

Divide $87 \cdot (0)$ by $1$ .

$c = 2 - (87 \cdot (0))$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - (87 \cdot (0))$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 - (87 \cdot (0))$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.1.2

Multiply $- (87 \cdot (0))$ .

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Step 2.3.6.2.1.1.2.1

Multiply $87$ by $0$ .

$c = 2 - 0$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.1.2.2

Multiply $- 1$ by $0$ .

$c = 2 + 0$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 + 0$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2 + 0$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.2.1.2

Add $2$ and $0$ .

$c = 2$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$c = 2$

$b = 0$

$4 = \frac{11 b}{4} + 2$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.3

Replace all occurrences of $b$ in $4 = \frac{11 b}{4} + 2$ with $0$ .

$4 = \frac{11 (0)}{4} + 2$

$c = 2$

$b = 0$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.4

Simplify the right side.

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Step 2.3.6.4.1

Simplify $\frac{11 (0)}{4} + 2$ .

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Step 2.3.6.4.1.1

Multiply $11$ by $0$ .

$4 = \frac{0}{4} + 2$

$c = 2$

$b = 0$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.4.1.2

Divide $0$ by $4$ .

$4 = 0 + 2$

$c = 2$

$b = 0$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.4.1.3

Add $0$ and $2$ .

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{9 b}{2} + 2$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.5

Replace all occurrences of $b$ in $2 = \frac{9 b}{2} + 2$ with $0$ .

$2 = \frac{9 (0)}{2} + 2$

$4 = 2$

$c = 2$

$b = 0$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.6

Simplify the right side.

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Step 2.3.6.6.1

Simplify $\frac{9 (0)}{2} + 2$ .

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Step 2.3.6.6.1.1

Multiply $9$ by $0$ .

$2 = \frac{0}{2} + 2$

$4 = 2$

$c = 2$

$b = 0$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.6.1.2

Divide $0$ by $2$ .

$2 = 0 + 2$

$4 = 2$

$c = 2$

$b = 0$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.6.1.3

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$4 = 5 b + 2$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.7

Replace all occurrences of $b$ in $4 = 5 b + 2$ with $0$ .

$4 = 5 (0) + 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.8

Simplify the right side.

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Step 2.3.6.8.1

Simplify $5 (0) + 2$ .

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Step 2.3.6.8.1.1

Multiply $5$ by $0$ .

$4 = 0 + 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.8.1.2

Add $0$ and $2$ .

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$2 = \frac{21 b}{4} + 2$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.9

Replace all occurrences of $b$ in $2 = \frac{21 b}{4} + 2$ with $0$ .

$2 = \frac{21 (0)}{4} + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.10

Simplify the right side.

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Step 2.3.6.10.1

Simplify $\frac{21 (0)}{4} + 2$ .

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Step 2.3.6.10.1.1

Multiply $21$ by $0$ .

$2 = \frac{0}{4} + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.10.1.2

Divide $0$ by $4$ .

$2 = 0 + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.10.1.3

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$6 = \frac{15 b}{4} + 2$

$a = - \frac{b}{32}$

Step 2.3.6.11

Replace all occurrences of $b$ in $6 = \frac{15 b}{4} + 2$ with $0$ .

$6 = \frac{15 (0)}{4} + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = - \frac{b}{32}$

Step 2.3.6.12

Simplify the right side.

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Step 2.3.6.12.1

Simplify $\frac{15 (0)}{4} + 2$ .

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Step 2.3.6.12.1.1

Multiply $15$ by $0$ .

$6 = \frac{0}{4} + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = - \frac{b}{32}$

Step 2.3.6.12.1.2

Divide $0$ by $4$ .

$6 = 0 + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = - \frac{b}{32}$

Step 2.3.6.12.1.3

Add $0$ and $2$ .

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = - \frac{b}{32}$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = - \frac{b}{32}$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = - \frac{b}{32}$

Step 2.3.6.13

Replace all occurrences of $b$ in $a = - \frac{b}{32}$ with $0$ .

$a = - \frac{0}{32}$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

Step 2.3.6.14

Simplify the right side.

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Step 2.3.6.14.1

Simplify $- \frac{0}{32}$ .

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Step 2.3.6.14.1.1

Divide $0$ by $32$ .

$a = - 0$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

Step 2.3.6.14.1.2

Multiply $- 1$ by $0$ .

$a = 0$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = 0$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = 0$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

$a = 0$

$6 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$c = 2$

$b = 0$

Step 2.3.7

Since $6 = 2$ is not true, there is no solution.

No solution

Step 2.4

Calculate the value of $y$ using each $x$ value in the table and compare this value to the given $y$ value in the table.

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Step 2.4.1

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 0$ , $b = 0$ , $c = 0$ , and $x = 3$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Raise $3$ to the power of $2$ .

$y = 0 \cdot 9 + (0) \cdot (3) + 0$

Step 2.4.1.1.2

Multiply $0$ by $9$ .

$y = 0 + (0) \cdot (3) + 0$

Step 2.4.1.1.3

Multiply $0$ by $3$ .

$y = 0 + 0 + 0$

Step 2.4.1.2

Simplify by adding numbers.

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Step 2.4.1.2.1

Add $0$ and $0$ .

$y = 0 + 0$

Step 2.4.1.2.2

Add $0$ and $0$ .

$y = 0$

Step 2.4.2

If the table has a quadratic function rule, $y = y$ for the corresponding $x$ value, $x = 3$ . This check does not pass, since $y = 0$ and $y = 2$ . The function rule can't be quadratic.

$0 \neq 2$

Step 2.4.3

Since $y \neq y$ for the corresponding $x$ values, the function is not quadratic.

The function is not quadratic

Step 3

Check if the function rule is cubic.

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Step 3.1

To find if the table follows a function rule, check whether the function rule could follow the form $y = a x^{3} + b x^{2} + c x + d$ .

$y = a x^{3} + b x^{2} + c x + d$

Step 3.2

Build a set of $4$ equations from the table such that $y = a x^{3} + b x^{2} + c x + d$ .

Step 3.3

Calculate the values of $a$ , $b$ , $c$ , and $d$ .

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Step 3.3.1

Solve for $d$ in $2 = a \cdot 3^{3} + b \cdot 3^{2} + c (3) + d$ .

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Step 3.3.1.1

Rewrite the equation as $a \cdot 3^{3} + b \cdot 3^{2} + c (3) + d = 2$ .

$a \cdot 3^{3} + b \cdot 3^{2} + c (3) + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.2

Simplify each term.

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Step 3.3.1.2.1

Raise $3$ to the power of $3$ .

$a \cdot 27 + b \cdot 3^{2} + c (3) + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.2.2

Move $27$ to the left of $a$ .

$27 \cdot a + b \cdot 3^{2} + c (3) + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.2.3

Raise $3$ to the power of $2$ .

$27 a + b \cdot 9 + c (3) + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.2.4

Move $9$ to the left of $b$ .

$27 a + 9 \cdot b + c (3) + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.2.5

Move $3$ to the left of $c$ .

$27 a + 9 b + 3 c + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$27 a + 9 b + 3 c + d = 2$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.3

Move all terms not containing $d$ to the right side of the equation.

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Step 3.3.1.3.1

Subtract $27 a$ from both sides of the equation.

$9 b + 3 c + d = 2 - 27 a$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.3.2

Subtract $9 b$ from both sides of the equation.

$3 c + d = 2 - 27 a - 9 b$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.1.3.3

Subtract $3 c$ from both sides of the equation.

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2

Replace all occurrences of $d$ with $2 - 27 a - 9 b - 3 c$ in each equation.

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Step 3.3.2.1

Replace all occurrences of $d$ in $2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2

Simplify $2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.2.1

Simplify the left side.

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Step 3.3.2.2.1.1

Remove parentheses.

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2

Simplify the right side.

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Step 3.3.2.2.2.1

Simplify $a \cdot 5^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.2.2.1.1

Combine the opposite terms in $a \cdot 5^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.2.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$2 = a \cdot 5^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.1.2

Subtract $3 c$ from $3 c$ .

$2 = a \cdot 5^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.1.3

Add $a \cdot 5^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$2 = a \cdot 5^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 5^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.2

Simplify each term.

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Step 3.3.2.2.2.1.2.1

Raise $5$ to the power of $3$ .

$2 = a \cdot 125 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.2.2

Move $125$ to the left of $a$ .

$2 = 125 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.2.3

Raise $3$ to the power of $2$ .

$2 = 125 a + b \cdot 9 + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.2.4

Move $9$ to the left of $b$ .

$2 = 125 a + 9 b + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 125 a + 9 b + 2 - 27 a - 9 b$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.3

Simplify by adding terms.

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Step 3.3.2.2.2.1.3.1

Combine the opposite terms in $125 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.2.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$2 = 125 a + 2 - 27 a + 0$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.3.1.2

Add $125 a + 2 - 27 a$ and $0$ .

$2 = 125 a + 2 - 27 a$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 125 a + 2 - 27 a$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.2.2.1.3.2

Subtract $27 a$ from $125 a$ .

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.3

Replace all occurrences of $d$ in $4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4

Simplify $4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.4.1

Simplify the left side.

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Step 3.3.2.4.1.1

Remove parentheses.

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2

Simplify the right side.

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Step 3.3.2.4.2.1

Simplify $a \cdot 7^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.4.2.1.1

Combine the opposite terms in $a \cdot 7^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.4.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$4 = a \cdot 7^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.1.2

Subtract $3 c$ from $3 c$ .

$4 = a \cdot 7^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.1.3

Add $a \cdot 7^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$4 = a \cdot 7^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 7^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.2

Simplify each term.

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Step 3.3.2.4.2.1.2.1

Raise $7$ to the power of $3$ .

$4 = a \cdot 343 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.2.2

Move $343$ to the left of $a$ .

$4 = 343 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.2.3

Raise $3$ to the power of $2$ .

$4 = 343 a + b \cdot 9 + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.2.4

Move $9$ to the left of $b$ .

$4 = 343 a + 9 b + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 343 a + 9 b + 2 - 27 a - 9 b$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.3

Simplify by adding terms.

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Step 3.3.2.4.2.1.3.1

Combine the opposite terms in $343 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.4.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$4 = 343 a + 2 - 27 a + 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.3.1.2

Add $343 a + 2 - 27 a$ and $0$ .

$4 = 343 a + 2 - 27 a$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 343 a + 2 - 27 a$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.4.2.1.3.2

Subtract $27 a$ from $343 a$ .

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.5

Replace all occurrences of $d$ in $2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6

Simplify $2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.6.1

Simplify the left side.

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Step 3.3.2.6.1.1

Remove parentheses.

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2

Simplify the right side.

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Step 3.3.2.6.2.1

Simplify $a \cdot 11^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.6.2.1.1

Combine the opposite terms in $a \cdot 11^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.6.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$2 = a \cdot 11^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.1.2

Subtract $3 c$ from $3 c$ .

$2 = a \cdot 11^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.1.3

Add $a \cdot 11^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$2 = a \cdot 11^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 11^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.2

Simplify each term.

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Step 3.3.2.6.2.1.2.1

Raise $11$ to the power of $3$ .

$2 = a \cdot 1331 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.2.2

Move $1331$ to the left of $a$ .

$2 = 1331 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.2.3

Raise $3$ to the power of $2$ .

$2 = 1331 a + b \cdot 9 + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.2.4

Move $9$ to the left of $b$ .

$2 = 1331 a + 9 b + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 1331 a + 9 b + 2 - 27 a - 9 b$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.3

Simplify by adding terms.

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Step 3.3.2.6.2.1.3.1

Combine the opposite terms in $1331 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.6.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$2 = 1331 a + 2 - 27 a + 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.3.1.2

Add $1331 a + 2 - 27 a$ and $0$ .

$2 = 1331 a + 2 - 27 a$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 1331 a + 2 - 27 a$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.6.2.1.3.2

Subtract $27 a$ from $1331 a$ .

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.7

Replace all occurrences of $d$ in $4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8

Simplify $4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.8.1

Simplify the left side.

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Step 3.3.2.8.1.1

Remove parentheses.

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2

Simplify the right side.

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Step 3.3.2.8.2.1

Simplify $a \cdot 13^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.8.2.1.1

Combine the opposite terms in $a \cdot 13^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.8.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$4 = a \cdot 13^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.1.2

Subtract $3 c$ from $3 c$ .

$4 = a \cdot 13^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.1.3

Add $a \cdot 13^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$4 = a \cdot 13^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 13^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.2

Simplify each term.

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Step 3.3.2.8.2.1.2.1

Raise $13$ to the power of $3$ .

$4 = a \cdot 2197 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.2.2

Move $2197$ to the left of $a$ .

$4 = 2197 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.2.3

Raise $3$ to the power of $2$ .

$4 = 2197 a + b \cdot 9 + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.2.4

Move $9$ to the left of $b$ .

$4 = 2197 a + 9 b + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 2197 a + 9 b + 2 - 27 a - 9 b$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.3

Simplify by adding terms.

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Step 3.3.2.8.2.1.3.1

Combine the opposite terms in $2197 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.8.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$4 = 2197 a + 2 - 27 a + 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.3.1.2

Add $2197 a + 2 - 27 a$ and $0$ .

$4 = 2197 a + 2 - 27 a$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 2197 a + 2 - 27 a$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.8.2.1.3.2

Subtract $27 a$ from $2197 a$ .

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.9

Replace all occurrences of $d$ in $2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10

Simplify $2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.10.1

Simplify the left side.

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Step 3.3.2.10.1.1

Remove parentheses.

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2

Simplify the right side.

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Step 3.3.2.10.2.1

Simplify $a \cdot 17^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.10.2.1.1

Combine the opposite terms in $a \cdot 17^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.10.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$2 = a \cdot 17^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.1.2

Subtract $3 c$ from $3 c$ .

$2 = a \cdot 17^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.1.3

Add $a \cdot 17^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$2 = a \cdot 17^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 17^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.2

Simplify each term.

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Step 3.3.2.10.2.1.2.1

Raise $17$ to the power of $3$ .

$2 = a \cdot 4913 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.2.2

Move $4913$ to the left of $a$ .

$2 = 4913 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.2.3

Raise $3$ to the power of $2$ .

$2 = 4913 a + b \cdot 9 + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.2.4

Move $9$ to the left of $b$ .

$2 = 4913 a + 9 b + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 4913 a + 9 b + 2 - 27 a - 9 b$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.3

Simplify by adding terms.

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Step 3.3.2.10.2.1.3.1

Combine the opposite terms in $4913 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.10.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$2 = 4913 a + 2 - 27 a + 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.3.1.2

Add $4913 a + 2 - 27 a$ and $0$ .

$2 = 4913 a + 2 - 27 a$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 4913 a + 2 - 27 a$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.10.2.1.3.2

Subtract $27 a$ from $4913 a$ .

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.11

Replace all occurrences of $d$ in $4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12

Simplify $4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.12.1

Simplify the left side.

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Step 3.3.2.12.1.1

Remove parentheses.

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2

Simplify the right side.

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Step 3.3.2.12.2.1

Simplify $a \cdot 19^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.12.2.1.1

Combine the opposite terms in $a \cdot 19^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.12.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$4 = a \cdot 19^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.1.2

Subtract $3 c$ from $3 c$ .

$4 = a \cdot 19^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.1.3

Add $a \cdot 19^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$4 = a \cdot 19^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = a \cdot 19^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.2

Simplify each term.

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Step 3.3.2.12.2.1.2.1

Raise $19$ to the power of $3$ .

$4 = a \cdot 6859 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.2.2

Move $6859$ to the left of $a$ .

$4 = 6859 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.2.3

Raise $3$ to the power of $2$ .

$4 = 6859 a + b \cdot 9 + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.2.4

Move $9$ to the left of $b$ .

$4 = 6859 a + 9 b + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 6859 a + 9 b + 2 - 27 a - 9 b$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.3

Simplify by adding terms.

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Step 3.3.2.12.2.1.3.1

Combine the opposite terms in $6859 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.12.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$4 = 6859 a + 2 - 27 a + 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.3.1.2

Add $6859 a + 2 - 27 a$ and $0$ .

$4 = 6859 a + 2 - 27 a$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 6859 a + 2 - 27 a$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.12.2.1.3.2

Subtract $27 a$ from $6859 a$ .

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.13

Replace all occurrences of $d$ in $6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14

Simplify $6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.14.1

Simplify the left side.

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Step 3.3.2.14.1.1

Remove parentheses.

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2

Simplify the right side.

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Step 3.3.2.14.2.1

Simplify $a \cdot 23^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.14.2.1.1

Combine the opposite terms in $a \cdot 23^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.14.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$6 = a \cdot 23^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.1.2

Subtract $3 c$ from $3 c$ .

$6 = a \cdot 23^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.1.3

Add $a \cdot 23^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$6 = a \cdot 23^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = a \cdot 23^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.2

Simplify each term.

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Step 3.3.2.14.2.1.2.1

Raise $23$ to the power of $3$ .

$6 = a \cdot 12167 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.2.2

Move $12167$ to the left of $a$ .

$6 = 12167 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.2.3

Raise $3$ to the power of $2$ .

$6 = 12167 a + b \cdot 9 + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.2.4

Move $9$ to the left of $b$ .

$6 = 12167 a + 9 b + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = 12167 a + 9 b + 2 - 27 a - 9 b$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.3

Simplify by adding terms.

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Step 3.3.2.14.2.1.3.1

Combine the opposite terms in $12167 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.14.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$6 = 12167 a + 2 - 27 a + 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.3.1.2

Add $12167 a + 2 - 27 a$ and $0$ .

$6 = 12167 a + 2 - 27 a$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = 12167 a + 2 - 27 a$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.14.2.1.3.2

Subtract $27 a$ from $12167 a$ .

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$

Step 3.3.2.15

Replace all occurrences of $d$ in $2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + d$ with $2 - 27 a - 9 b - 3 c$ .

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16

Simplify $2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.16.1

Simplify the left side.

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Step 3.3.2.16.1.1

Remove parentheses.

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2

Simplify the right side.

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Step 3.3.2.16.2.1

Simplify $a \cdot 29^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.16.2.1.1

Combine the opposite terms in $a \cdot 29^{3} + b \cdot 3^{2} + c (3) + 2 - 27 a - 9 b - 3 c$ .

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Step 3.3.2.16.2.1.1.1

Reorder the factors in the terms $c (3)$ and $- 3 c$ .

$2 = a \cdot 29^{3} + b \cdot 3^{2} + 3 c + 2 - 27 a - 9 b - 3 c$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.1.2

Subtract $3 c$ from $3 c$ .

$2 = a \cdot 29^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b + 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.1.3

Add $a \cdot 29^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$ and $0$ .

$2 = a \cdot 29^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = a \cdot 29^{3} + b \cdot 3^{2} + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.2

Simplify each term.

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Step 3.3.2.16.2.1.2.1

Raise $29$ to the power of $3$ .

$2 = a \cdot 24389 + b \cdot 3^{2} + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.2.2

Move $24389$ to the left of $a$ .

$2 = 24389 \cdot a + b \cdot 3^{2} + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.2.3

Raise $3$ to the power of $2$ .

$2 = 24389 a + b \cdot 9 + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.2.4

Move $9$ to the left of $b$ .

$2 = 24389 a + 9 b + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24389 a + 9 b + 2 - 27 a - 9 b$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.3

Simplify by adding terms.

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Step 3.3.2.16.2.1.3.1

Combine the opposite terms in $24389 a + 9 b + 2 - 27 a - 9 b$ .

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Step 3.3.2.16.2.1.3.1.1

Subtract $9 b$ from $9 b$ .

$2 = 24389 a + 2 - 27 a + 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.3.1.2

Add $24389 a + 2 - 27 a$ and $0$ .

$2 = 24389 a + 2 - 27 a$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24389 a + 2 - 27 a$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.2.16.2.1.3.2

Subtract $27 a$ from $24389 a$ .

$2 = 24362 a + 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24362 a + 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24362 a + 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24362 a + 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24362 a + 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 24362 a + 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3

Solve for $a$ in $2 = 24362 a + 2$ .

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Step 3.3.3.1

Rewrite the equation as $24362 a + 2 = 2$ .

$24362 a + 2 = 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3.2

Move all terms not containing $a$ to the right side of the equation.

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Step 3.3.3.2.1

Subtract $2$ from both sides of the equation.

$24362 a = 2 - 2$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3.2.2

Subtract $2$ from $2$ .

$24362 a = 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$24362 a = 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3.3

Divide each term in $24362 a = 0$ by $24362$ and simplify.

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Step 3.3.3.3.1

Divide each term in $24362 a = 0$ by $24362$ .

$\frac{24362 a}{24362} = \frac{0}{24362}$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3.3.2

Simplify the left side.

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Step 3.3.3.3.2.1

Cancel the common factor of $24362$ .

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Step 3.3.3.3.2.1.1

Cancel the common factor.

$\frac{24362 a}{24362} = \frac{0}{24362}$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3.3.2.1.2

Divide $a$ by $1$ .

$a = \frac{0}{24362}$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$a = \frac{0}{24362}$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$a = \frac{0}{24362}$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.3.3.3

Simplify the right side.

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Step 3.3.3.3.3.1

Divide $0$ by $24362$ .

$a = 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$a = 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$a = 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$a = 0$

$6 = 12140 a + 2$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4

Replace all occurrences of $a$ with $0$ in each equation.

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Step 3.3.4.1

Replace all occurrences of $a$ in $6 = 12140 a + 2$ with $0$ .

$6 = 12140 (0) + 2$

$a = 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.2

Simplify the right side.

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Step 3.3.4.2.1

Simplify $12140 (0) + 2$ .

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Step 3.3.4.2.1.1

Multiply $12140$ by $0$ .

$6 = 0 + 2$

$a = 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.2.1.2

Add $0$ and $2$ .

$6 = 2$

$a = 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = 2$

$a = 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$6 = 2$

$a = 0$

$4 = 6832 a + 2$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.3

Replace all occurrences of $a$ in $4 = 6832 a + 2$ with $0$ .

$4 = 6832 (0) + 2$

$6 = 2$

$a = 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.4

Simplify the right side.

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Step 3.3.4.4.1

Simplify $6832 (0) + 2$ .

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Step 3.3.4.4.1.1

Multiply $6832$ by $0$ .

$4 = 0 + 2$

$6 = 2$

$a = 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.4.1.2

Add $0$ and $2$ .

$4 = 2$

$6 = 2$

$a = 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 4886 a + 2$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.5

Replace all occurrences of $a$ in $2 = 4886 a + 2$ with $0$ .

$2 = 4886 (0) + 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.6

Simplify the right side.

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Step 3.3.4.6.1

Simplify $4886 (0) + 2$ .

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Step 3.3.4.6.1.1

Multiply $4886$ by $0$ .

$2 = 0 + 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.6.1.2

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 2170 a + 2$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.7

Replace all occurrences of $a$ in $4 = 2170 a + 2$ with $0$ .

$4 = 2170 (0) + 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.8

Simplify the right side.

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Step 3.3.4.8.1

Simplify $2170 (0) + 2$ .

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Step 3.3.4.8.1.1

Multiply $2170$ by $0$ .

$4 = 0 + 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.8.1.2

Add $0$ and $2$ .

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 1304 a + 2$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.9

Replace all occurrences of $a$ in $2 = 1304 a + 2$ with $0$ .

$2 = 1304 (0) + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.10

Simplify the right side.

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Step 3.3.4.10.1

Simplify $1304 (0) + 2$ .

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Step 3.3.4.10.1.1

Multiply $1304$ by $0$ .

$2 = 0 + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.10.1.2

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$4 = 316 a + 2$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.11

Replace all occurrences of $a$ in $4 = 316 a + 2$ with $0$ .

$4 = 316 (0) + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.12

Simplify the right side.

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Step 3.3.4.12.1

Simplify $316 (0) + 2$ .

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Step 3.3.4.12.1.1

Multiply $316$ by $0$ .

$4 = 0 + 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.12.1.2

Add $0$ and $2$ .

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$2 = 98 a + 2$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.13

Replace all occurrences of $a$ in $2 = 98 a + 2$ with $0$ .

$2 = 98 (0) + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.14

Simplify the right side.

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Step 3.3.4.14.1

Simplify $98 (0) + 2$ .

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Step 3.3.4.14.1.1

Multiply $98$ by $0$ .

$2 = 0 + 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.14.1.2

Add $0$ and $2$ .

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 27 a - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 27 a - 9 b - 3 c$

Step 3.3.4.15

Replace all occurrences of $a$ in $d = 2 - 27 a - 9 b - 3 c$ with $0$ .

$d = 2 - 27 \cdot 0 - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

Step 3.3.4.16

Simplify the right side.

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Step 3.3.4.16.1

Simplify $2 - 27 \cdot 0 - 9 b - 3 c$ .

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Step 3.3.4.16.1.1

Multiply $- 27$ by $0$ .

$d = 2 + 0 - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

Step 3.3.4.16.1.2

Add $2$ and $0$ .

$d = 2 - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

$d = 2 - 9 b - 3 c$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$2 = 2$

$4 = 2$

$6 = 2$

$a = 0$

Step 3.3.5

Since $4 = 2$ is not true, there is no solution.

No solution

Step 3.4

Calculate the value of $y$ using each $x$ value in the table and compare this value to the given $y$ value in the table.

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Step 3.4.1

Calculate the value of $y$ such that $y = a x^{3} + b$ when $a = 0$ , $b = 0$ , $c = 0$ , $d = 0$ , and $x = 3$ .

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Step 3.4.1.1

Simplify each term.

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Step 3.4.1.1.1

Raise $3$ to the power of $3$ .

$y = 0 \cdot 27 + (0) \cdot (3^{2}) + (0) \cdot ((3) \cdot 0)$

Step 3.4.1.1.2

Multiply $0$ by $27$ .

$y = 0 + (0) \cdot (3^{2}) + (0) \cdot ((3) \cdot 0)$

Step 3.4.1.1.3

Raise $3$ to the power of $2$ .

$y = 0 + 0 \cdot 9 + (0) \cdot ((3) \cdot 0)$

Step 3.4.1.1.4

Multiply $0$ by $9$ .

$y = 0 + 0 + (0) \cdot ((3) \cdot 0)$

Step 3.4.1.1.5

Multiply $(0) ((3) \cdot 0)$ .

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Step 3.4.1.1.5.1

Multiply $3$ by $0$ .

$y = 0 + 0 + 0 \cdot 0$

Step 3.4.1.1.5.2

Multiply $0$ by $0$ .

$y = 0 + 0 + 0$

Step 3.4.1.2

Simplify by adding numbers.

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Step 3.4.1.2.1

Add $0$ and $0$ .

$y = 0 + 0$

Step 3.4.1.2.2

Add $0$ and $0$ .

$y = 0$

Step 3.4.2

If the table has a cubic function rule, $y = y$ for the corresponding $x$ value, $x = 3$ . This check does not pass, since $y = 0$ and $y = 2$ . The function rule can't be cubic.

$0 \neq 2$

Step 3.4.3

Since $y \neq y$ for the corresponding $x$ values, the function is not cubic.

The function is not cubic

Step 4

There are no values for $a$ , $b$ , $c$ , and $d$ in the equations $y = a x + b$ , $y = a x^{2} + b x + c$ , and $y = a x^{3} + b x^{2} + c x + d$ that work for every pair of $x$ and $y$ .

The table does not have a function rule that is linear, quadratic, or cubic.