Pre-Algebra Examples

$\begin{array}{c} x & y \\ 0 & \frac{2}{3} \\ 1 & 2 \\ 2 & 6 \\ 3 & 18 \\ 4 & 54 \\ 5 & 162 \end{array}$

Step 1

Check if the function rule is linear.

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Step 1.1

To find if the table follows a function rule, check to see if the values follow the linear form $y = a x + b$ .

$y = a x + b$

Step 1.2

Build a set of equations from the table such that $y = a x + b$ .

$\frac{2}{3} = a (0) + b 2 = a (1) + b 6 = a (2) + b 18 = a (3) + b 54 = a (4) + b 162 = a (5) + b$

Step 1.3

Calculate the values of $a$ and $b$ .

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Step 1.3.1

Rewrite the equation as $b = \frac{2}{3}$ .

$b = \frac{2}{3}$

$2 = a + b$

$6 = a (2) + b$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2

Replace all occurrences of $b$ with $\frac{2}{3}$ in each equation.

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Step 1.3.2.1

Replace all occurrences of $b$ in $2 = a + b$ with $\frac{2}{3}$ .

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = a (2) + b$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.2

Simplify the left side.

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Step 1.3.2.2.1

Remove parentheses.

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = a (2) + b$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = a (2) + b$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.3

Replace all occurrences of $b$ in $6 = a (2) + b$ with $\frac{2}{3}$ .

$6 = a (2) + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.4

Simplify $6 = a (2) + \frac{2}{3}$ .

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Step 1.3.2.4.1

Simplify the left side.

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Step 1.3.2.4.1.1

Remove parentheses.

$6 = a (2) + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

$6 = a (2) + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.4.2

Simplify the right side.

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Step 1.3.2.4.2.1

Move $2$ to the left of $a$ .

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = a (3) + b$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.5

Replace all occurrences of $b$ in $18 = a (3) + b$ with $\frac{2}{3}$ .

$18 = a (3) + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.6

Simplify $18 = a (3) + \frac{2}{3}$ .

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Step 1.3.2.6.1

Simplify the left side.

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Step 1.3.2.6.1.1

Remove parentheses.

$18 = a (3) + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = a (4) + b$

$162 = a (5) + b$

$18 = a (3) + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.6.2

Simplify the right side.

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Step 1.3.2.6.2.1

Move $3$ to the left of $a$ .

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = a (4) + b$

$162 = a (5) + b$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = a (4) + b$

$162 = a (5) + b$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = a (4) + b$

$162 = a (5) + b$

Step 1.3.2.7

Replace all occurrences of $b$ in $54 = a (4) + b$ with $\frac{2}{3}$ .

$54 = a (4) + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + b$

Step 1.3.2.8

Simplify $54 = a (4) + \frac{2}{3}$ .

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Step 1.3.2.8.1

Simplify the left side.

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Step 1.3.2.8.1.1

Remove parentheses.

$54 = a (4) + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + b$

$54 = a (4) + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + b$

Step 1.3.2.8.2

Simplify the right side.

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Step 1.3.2.8.2.1

Move $4$ to the left of $a$ .

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + b$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + b$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + b$

Step 1.3.2.9

Replace all occurrences of $b$ in $162 = a (5) + b$ with $\frac{2}{3}$ .

$162 = a (5) + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.2.10

Simplify $162 = a (5) + \frac{2}{3}$ .

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Step 1.3.2.10.1

Simplify the left side.

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Step 1.3.2.10.1.1

Remove parentheses.

$162 = a (5) + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = a (5) + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.2.10.2

Simplify the right side.

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Step 1.3.2.10.2.1

Move $5$ to the left of $a$ .

$162 = 5 a + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = 5 a + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = 5 a + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$162 = 5 a + \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3

Solve for $a$ in $162 = 5 a + \frac{2}{3}$ .

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Step 1.3.3.1

Rewrite the equation as $5 a + \frac{2}{3} = 162$ .

$5 a + \frac{2}{3} = 162$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.2

Move all terms not containing $a$ to the right side of the equation.

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Step 1.3.3.2.1

Subtract $\frac{2}{3}$ from both sides of the equation.

$5 a = 162 - \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.2.2

To write $162$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$5 a = 162 \cdot \frac{3}{3} - \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.2.3

Combine $162$ and $\frac{3}{3}$ .

$5 a = \frac{162 \cdot 3}{3} - \frac{2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.2.4

Combine the numerators over the common denominator.

$5 a = \frac{162 \cdot 3 - 2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.2.5

Simplify the numerator.

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Step 1.3.3.2.5.1

Multiply $162$ by $3$ .

$5 a = \frac{486 - 2}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.2.5.2

Subtract $2$ from $486$ .

$5 a = \frac{484}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$5 a = \frac{484}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$5 a = \frac{484}{3}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.3

Divide each term in $5 a = \frac{484}{3}$ by $5$ and simplify.

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Step 1.3.3.3.1

Divide each term in $5 a = \frac{484}{3}$ by $5$ .

$\frac{5 a}{5} = \frac{\frac{484}{3}}{5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.3.2

Simplify the left side.

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Step 1.3.3.3.2.1

Cancel the common factor of $5$ .

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Step 1.3.3.3.2.1.1

Cancel the common factor.

$\frac{5 a}{5} = \frac{\frac{484}{3}}{5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.3.2.1.2

Divide $a$ by $1$ .

$a = \frac{\frac{484}{3}}{5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$a = \frac{\frac{484}{3}}{5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$a = \frac{\frac{484}{3}}{5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.3.3

Simplify the right side.

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Step 1.3.3.3.3.1

Multiply the numerator by the reciprocal of the denominator.

$a = \frac{484}{3} \cdot \frac{1}{5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.3.3.2

Multiply $\frac{484}{3} \cdot \frac{1}{5}$ .

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Step 1.3.3.3.3.2.1

Multiply $\frac{484}{3}$ by $\frac{1}{5}$ .

$a = \frac{484}{3 \cdot 5}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.3.3.3.2.2

Multiply $3$ by $5$ .

$a = \frac{484}{15}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$a = \frac{484}{15}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$a = \frac{484}{15}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$a = \frac{484}{15}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$a = \frac{484}{15}$

$54 = 4 a + \frac{2}{3}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4

Replace all occurrences of $a$ with $\frac{484}{15}$ in each equation.

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Step 1.3.4.1

Replace all occurrences of $a$ in $54 = 4 a + \frac{2}{3}$ with $\frac{484}{15}$ .

$54 = 4 (\frac{484}{15}) + \frac{2}{3}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2

Simplify the right side.

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Step 1.3.4.2.1

Simplify $4 (\frac{484}{15}) + \frac{2}{3}$ .

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Step 1.3.4.2.1.1

Multiply $4 (\frac{484}{15})$ .

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Step 1.3.4.2.1.1.1

Combine $4$ and $\frac{484}{15}$ .

$54 = \frac{4 \cdot 484}{15} + \frac{2}{3}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.1.2

Multiply $4$ by $484$ .

$54 = \frac{1936}{15} + \frac{2}{3}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = \frac{1936}{15} + \frac{2}{3}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.2

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$54 = \frac{1936}{15} + \frac{2}{3} \cdot \frac{5}{5}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.3

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 1.3.4.2.1.3.1

Multiply $\frac{2}{3}$ by $\frac{5}{5}$ .

$54 = \frac{1936}{15} + \frac{2 \cdot 5}{3 \cdot 5}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.3.2

Multiply $3$ by $5$ .

$54 = \frac{1936}{15} + \frac{2 \cdot 5}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = \frac{1936}{15} + \frac{2 \cdot 5}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.4

Combine the numerators over the common denominator.

$54 = \frac{1936 + 2 \cdot 5}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.5

Simplify the numerator.

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Step 1.3.4.2.1.5.1

Multiply $2$ by $5$ .

$54 = \frac{1936 + 10}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.2.1.5.2

Add $1936$ and $10$ .

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$18 = 3 a + \frac{2}{3}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.3

Replace all occurrences of $a$ in $18 = 3 a + \frac{2}{3}$ with $\frac{484}{15}$ .

$18 = 3 (\frac{484}{15}) + \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4

Simplify the right side.

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Step 1.3.4.4.1

Simplify $3 (\frac{484}{15}) + \frac{2}{3}$ .

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Step 1.3.4.4.1.1

Cancel the common factor of $3$ .

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Step 1.3.4.4.1.1.1

Factor $3$ out of $15$ .

$18 = 3 (\frac{484}{3 (5)}) + \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.1.2

Cancel the common factor.

$18 = 3 (\frac{484}{3 \cdot 5}) + \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.1.3

Rewrite the expression.

$18 = \frac{484}{5} + \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = \frac{484}{5} + \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.2

To write $\frac{484}{5}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$18 = \frac{484}{5} \cdot \frac{3}{3} + \frac{2}{3}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.3

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$18 = \frac{484}{5} \cdot \frac{3}{3} + \frac{2}{3} \cdot \frac{5}{5}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.4

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 1.3.4.4.1.4.1

Multiply $\frac{484}{5}$ by $\frac{3}{3}$ .

$18 = \frac{484 \cdot 3}{5 \cdot 3} + \frac{2}{3} \cdot \frac{5}{5}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.4.2

Multiply $5$ by $3$ .

$18 = \frac{484 \cdot 3}{15} + \frac{2}{3} \cdot \frac{5}{5}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.4.3

Multiply $\frac{2}{3}$ by $\frac{5}{5}$ .

$18 = \frac{484 \cdot 3}{15} + \frac{2 \cdot 5}{3 \cdot 5}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.4.4

Multiply $3$ by $5$ .

$18 = \frac{484 \cdot 3}{15} + \frac{2 \cdot 5}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = \frac{484 \cdot 3}{15} + \frac{2 \cdot 5}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.5

Combine the numerators over the common denominator.

$18 = \frac{484 \cdot 3 + 2 \cdot 5}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.6

Simplify the numerator.

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Step 1.3.4.4.1.6.1

Multiply $484$ by $3$ .

$18 = \frac{1452 + 2 \cdot 5}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.6.2

Multiply $2$ by $5$ .

$18 = \frac{1452 + 10}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.4.1.6.3

Add $1452$ and $10$ .

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$6 = 2 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.5

Replace all occurrences of $a$ in $6 = 2 a + \frac{2}{3}$ with $\frac{484}{15}$ .

$6 = 2 (\frac{484}{15}) + \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6

Simplify the right side.

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Step 1.3.4.6.1

Simplify $2 (\frac{484}{15}) + \frac{2}{3}$ .

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Step 1.3.4.6.1.1

Multiply $2 (\frac{484}{15})$ .

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Step 1.3.4.6.1.1.1

Combine $2$ and $\frac{484}{15}$ .

$6 = \frac{2 \cdot 484}{15} + \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.1.2

Multiply $2$ by $484$ .

$6 = \frac{968}{15} + \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{968}{15} + \frac{2}{3}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.2

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$6 = \frac{968}{15} + \frac{2}{3} \cdot \frac{5}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.3

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 1.3.4.6.1.3.1

Multiply $\frac{2}{3}$ by $\frac{5}{5}$ .

$6 = \frac{968}{15} + \frac{2 \cdot 5}{3 \cdot 5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.3.2

Multiply $3$ by $5$ .

$6 = \frac{968}{15} + \frac{2 \cdot 5}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{968}{15} + \frac{2 \cdot 5}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.4

Combine the numerators over the common denominator.

$6 = \frac{968 + 2 \cdot 5}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.5

Simplify the numerator.

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Step 1.3.4.6.1.5.1

Multiply $2$ by $5$ .

$6 = \frac{968 + 10}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.5.2

Add $968$ and $10$ .

$6 = \frac{978}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{978}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.6

Cancel the common factor of $978$ and $15$ .

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Step 1.3.4.6.1.6.1

Factor $3$ out of $978$ .

$6 = \frac{3 (326)}{15}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.6.2

Cancel the common factors.

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Step 1.3.4.6.1.6.2.1

Factor $3$ out of $15$ .

$6 = \frac{3 \cdot 326}{3 \cdot 5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.6.2.2

Cancel the common factor.

$6 = \frac{3 \cdot 326}{3 \cdot 5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.6.1.6.2.3

Rewrite the expression.

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$2 = a + \frac{2}{3}$

$b = \frac{2}{3}$

Step 1.3.4.7

Replace all occurrences of $a$ in $2 = a + \frac{2}{3}$ with $\frac{484}{15}$ .

$2 = (\frac{484}{15}) + \frac{2}{3}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.4.8

Simplify the right side.

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Step 1.3.4.8.1

Simplify $(\frac{484}{15}) + \frac{2}{3}$ .

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Step 1.3.4.8.1.1

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$2 = \frac{484}{15} + \frac{2}{3} \cdot \frac{5}{5}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.4.8.1.2

Write each expression with a common denominator of $15$ , by multiplying each by an appropriate factor of $1$ .

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Step 1.3.4.8.1.2.1

Multiply $\frac{2}{3}$ by $\frac{5}{5}$ .

$2 = \frac{484}{15} + \frac{2 \cdot 5}{3 \cdot 5}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.4.8.1.2.2

Multiply $3$ by $5$ .

$2 = \frac{484}{15} + \frac{2 \cdot 5}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

$2 = \frac{484}{15} + \frac{2 \cdot 5}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.4.8.1.3

Combine the numerators over the common denominator.

$2 = \frac{484 + 2 \cdot 5}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.4.8.1.4

Simplify the numerator.

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Step 1.3.4.8.1.4.1

Multiply $2$ by $5$ .

$2 = \frac{484 + 10}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.4.8.1.4.2

Add $484$ and $10$ .

$2 = \frac{494}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

$2 = \frac{494}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

$2 = \frac{494}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

$2 = \frac{494}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

$2 = \frac{494}{15}$

$6 = \frac{326}{5}$

$18 = \frac{1462}{15}$

$54 = \frac{1946}{15}$

$a = \frac{484}{15}$

$b = \frac{2}{3}$

Step 1.3.5

Since $2 = \frac{494}{15}$ is not true, there is no solution.

No solution

Step 1.4

Since $y \neq y$ for the corresponding $x$ values, the function is not linear.

The function is not linear

Step 2

Check if the function rule is quadratic.

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Step 2.1

To find if the table follows a function rule, check whether the function rule could follow the form $y = a x^{2} + b x + c$ .

$y = a x^{2} + b x + c$

Step 2.2

Build a set of $3$ equations from the table such that $y = a x^{2} + b x + c$ .

Step 2.3

Calculate the values of $a$ , $b$ , and $c$ .

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Step 2.3.1

Solve for $c$ in $\frac{2}{3} = a \cdot 0^{2} + c$ .

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Step 2.3.1.1

Rewrite the equation as $a \cdot 0^{2} + c = \frac{2}{3}$ .

$a \cdot 0^{2} + c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.1.2

Simplify $a \cdot 0^{2} + c$ .

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Step 2.3.1.2.1

Simplify each term.

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Step 2.3.1.2.1.1

Raising $0$ to any positive power yields $0$ .

$a \cdot 0 + c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.1.2.1.2

Multiply $a$ by $0$ .

$0 + c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$0 + c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.1.2.2

Add $0$ and $c$ .

$c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$c = \frac{2}{3}$

$2 = a + b + c$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2

Replace all occurrences of $c$ with $\frac{2}{3}$ in each equation.

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Step 2.3.2.1

Replace all occurrences of $c$ in $2 = a + b + c$ with $\frac{2}{3}$ .

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.2

Simplify the left side.

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Step 2.3.2.2.1

Remove parentheses.

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$6 = a \cdot 2^{2} + b (2) + c$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.3

Replace all occurrences of $c$ in $6 = a \cdot 2^{2} + b (2) + c$ with $\frac{2}{3}$ .

$6 = a \cdot 2^{2} + b (2) + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.4

Simplify $6 = a \cdot 2^{2} + b (2) + \frac{2}{3}$ .

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Step 2.3.2.4.1

Simplify the left side.

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Step 2.3.2.4.1.1

Remove parentheses.

$6 = a \cdot 2^{2} + b (2) + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$6 = a \cdot 2^{2} + b (2) + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.4.2

Simplify the right side.

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Step 2.3.2.4.2.1

Simplify each term.

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Step 2.3.2.4.2.1.1

Raise $2$ to the power of $2$ .

$6 = a \cdot 4 + b (2) + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.4.2.1.2

Move $4$ to the left of $a$ .

$6 = 4 \cdot a + b (2) + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.4.2.1.3

Move $2$ to the left of $b$ .

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = a \cdot 3^{2} + b (3) + c$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.5

Replace all occurrences of $c$ in $18 = a \cdot 3^{2} + b (3) + c$ with $\frac{2}{3}$ .

$18 = a \cdot 3^{2} + b (3) + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.6

Simplify $18 = a \cdot 3^{2} + b (3) + \frac{2}{3}$ .

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Step 2.3.2.6.1

Simplify the left side.

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Step 2.3.2.6.1.1

Remove parentheses.

$18 = a \cdot 3^{2} + b (3) + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$18 = a \cdot 3^{2} + b (3) + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.6.2

Simplify the right side.

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Step 2.3.2.6.2.1

Simplify each term.

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Step 2.3.2.6.2.1.1

Raise $3$ to the power of $2$ .

$18 = a \cdot 9 + b (3) + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.6.2.1.2

Move $9$ to the left of $a$ .

$18 = 9 \cdot a + b (3) + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.6.2.1.3

Move $3$ to the left of $b$ .

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = a \cdot 4^{2} + b (4) + c$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.7

Replace all occurrences of $c$ in $54 = a \cdot 4^{2} + b (4) + c$ with $\frac{2}{3}$ .

$54 = a \cdot 4^{2} + b (4) + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.8

Simplify $54 = a \cdot 4^{2} + b (4) + \frac{2}{3}$ .

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Step 2.3.2.8.1

Simplify the left side.

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Step 2.3.2.8.1.1

Remove parentheses.

$54 = a \cdot 4^{2} + b (4) + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

$54 = a \cdot 4^{2} + b (4) + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.8.2

Simplify the right side.

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Step 2.3.2.8.2.1

Simplify each term.

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Step 2.3.2.8.2.1.1

Raise $4$ to the power of $2$ .

$54 = a \cdot 16 + b (4) + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.8.2.1.2

Move $16$ to the left of $a$ .

$54 = 16 \cdot a + b (4) + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.8.2.1.3

Move $4$ to the left of $b$ .

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + c$

Step 2.3.2.9

Replace all occurrences of $c$ in $162 = a \cdot 5^{2} + b (5) + c$ with $\frac{2}{3}$ .

$162 = a \cdot 5^{2} + b (5) + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.2.10

Simplify $162 = a \cdot 5^{2} + b (5) + \frac{2}{3}$ .

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Step 2.3.2.10.1

Simplify the left side.

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Step 2.3.2.10.1.1

Remove parentheses.

$162 = a \cdot 5^{2} + b (5) + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = a \cdot 5^{2} + b (5) + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.2.10.2

Simplify the right side.

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Step 2.3.2.10.2.1

Simplify each term.

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Step 2.3.2.10.2.1.1

Raise $5$ to the power of $2$ .

$162 = a \cdot 25 + b (5) + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.2.10.2.1.2

Move $25$ to the left of $a$ .

$162 = 25 \cdot a + b (5) + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.2.10.2.1.3

Move $5$ to the left of $b$ .

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$2 = a + b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3

Solve for $a$ in $2 = a + b + \frac{2}{3}$ .

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Step 2.3.3.1

Rewrite the equation as $a + b + \frac{2}{3} = 2$ .

$a + b + \frac{2}{3} = 2$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2

Move all terms not containing $a$ to the right side of the equation.

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Step 2.3.3.2.1

Subtract $b$ from both sides of the equation.

$a + \frac{2}{3} = 2 - b$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2.2

Subtract $\frac{2}{3}$ from both sides of the equation.

$a = 2 - b - \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2.3

To write $2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$a = - b + 2 \cdot \frac{3}{3} - \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2.4

Combine $2$ and $\frac{3}{3}$ .

$a = - b + \frac{2 \cdot 3}{3} - \frac{2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2.5

Combine the numerators over the common denominator.

$a = - b + \frac{2 \cdot 3 - 2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2.6

Simplify the numerator.

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Step 2.3.3.2.6.1

Multiply $2$ by $3$ .

$a = - b + \frac{6 - 2}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.3.2.6.2

Subtract $2$ from $6$ .

$a = - b + \frac{4}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$a = - b + \frac{4}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$a = - b + \frac{4}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$a = - b + \frac{4}{3}$

$162 = 25 a + 5 b + \frac{2}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4

Replace all occurrences of $a$ with $- b + \frac{4}{3}$ in each equation.

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Step 2.3.4.1

Replace all occurrences of $a$ in $162 = 25 a + 5 b + \frac{2}{3}$ with $- b + \frac{4}{3}$ .

$162 = 25 (- b + \frac{4}{3}) + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2

Simplify the right side.

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Step 2.3.4.2.1

Simplify $25 (- b + \frac{4}{3}) + 5 b + \frac{2}{3}$ .

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Step 2.3.4.2.1.1

Simplify each term.

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Step 2.3.4.2.1.1.1

Apply the distributive property.

$162 = 25 (- b) + 25 (\frac{4}{3}) + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.1.2

Multiply $- 1$ by $25$ .

$162 = - 25 b + 25 (\frac{4}{3}) + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.1.3

Multiply $25 (\frac{4}{3})$ .

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Step 2.3.4.2.1.1.3.1

Combine $25$ and $\frac{4}{3}$ .

$162 = - 25 b + \frac{25 \cdot 4}{3} + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.1.3.2

Multiply $25$ by $4$ .

$162 = - 25 b + \frac{100}{3} + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = - 25 b + \frac{100}{3} + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = - 25 b + \frac{100}{3} + 5 b + \frac{2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.2

Simplify terms.

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Step 2.3.4.2.1.2.1

Combine the numerators over the common denominator.

$162 = - 25 b + 5 b + \frac{100 + 2}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.2.2

Simplify the expression.

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Step 2.3.4.2.1.2.2.1

Add $100$ and $2$ .

$162 = - 25 b + 5 b + \frac{102}{3}$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.2.2.2

Divide $102$ by $3$ .

$162 = - 25 b + 5 b + 34$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = - 25 b + 5 b + 34$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.2.1.2.3

Add $- 25 b$ and $5 b$ .

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$54 = 16 a + 4 b + \frac{2}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.3

Replace all occurrences of $a$ in $54 = 16 a + 4 b + \frac{2}{3}$ with $- b + \frac{4}{3}$ .

$54 = 16 (- b + \frac{4}{3}) + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4

Simplify the right side.

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Step 2.3.4.4.1

Simplify $16 (- b + \frac{4}{3}) + 4 b + \frac{2}{3}$ .

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Step 2.3.4.4.1.1

Simplify each term.

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Step 2.3.4.4.1.1.1

Apply the distributive property.

$54 = 16 (- b) + 16 (\frac{4}{3}) + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.1.2

Multiply $- 1$ by $16$ .

$54 = - 16 b + 16 (\frac{4}{3}) + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.1.3

Multiply $16 (\frac{4}{3})$ .

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Step 2.3.4.4.1.1.3.1

Combine $16$ and $\frac{4}{3}$ .

$54 = - 16 b + \frac{16 \cdot 4}{3} + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.1.3.2

Multiply $16$ by $4$ .

$54 = - 16 b + \frac{64}{3} + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = - 16 b + \frac{64}{3} + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = - 16 b + \frac{64}{3} + 4 b + \frac{2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.2

Simplify terms.

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Step 2.3.4.4.1.2.1

Combine the numerators over the common denominator.

$54 = - 16 b + 4 b + \frac{64 + 2}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.2.2

Simplify the expression.

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Step 2.3.4.4.1.2.2.1

Add $64$ and $2$ .

$54 = - 16 b + 4 b + \frac{66}{3}$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.2.2.2

Divide $66$ by $3$ .

$54 = - 16 b + 4 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = - 16 b + 4 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.4.1.2.3

Add $- 16 b$ and $4 b$ .

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$18 = 9 a + 3 b + \frac{2}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.5

Replace all occurrences of $a$ in $18 = 9 a + 3 b + \frac{2}{3}$ with $- b + \frac{4}{3}$ .

$18 = 9 (- b + \frac{4}{3}) + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6

Simplify the right side.

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Step 2.3.4.6.1

Simplify $9 (- b + \frac{4}{3}) + 3 b + \frac{2}{3}$ .

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Step 2.3.4.6.1.1

Simplify each term.

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Step 2.3.4.6.1.1.1

Apply the distributive property.

$18 = 9 (- b) + 9 (\frac{4}{3}) + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.1.2

Multiply $- 1$ by $9$ .

$18 = - 9 b + 9 (\frac{4}{3}) + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.1.3

Cancel the common factor of $3$ .

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Step 2.3.4.6.1.1.3.1

Factor $3$ out of $9$ .

$18 = - 9 b + 3 (3) (\frac{4}{3}) + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.1.3.2

Cancel the common factor.

$18 = - 9 b + 3 \cdot (3 (\frac{4}{3})) + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.1.3.3

Rewrite the expression.

$18 = - 9 b + 3 \cdot 4 + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = - 9 b + 3 \cdot 4 + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.1.4

Multiply $3$ by $4$ .

$18 = - 9 b + 12 + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = - 9 b + 12 + 3 b + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.2

Add $- 9 b$ and $3 b$ .

$18 = - 6 b + 12 + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.3

To write $12$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$18 = - 6 b + 12 \cdot \frac{3}{3} + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.4

Combine $12$ and $\frac{3}{3}$ .

$18 = - 6 b + \frac{12 \cdot 3}{3} + \frac{2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.5

Combine the numerators over the common denominator.

$18 = - 6 b + \frac{12 \cdot 3 + 2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.6

Simplify the numerator.

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Step 2.3.4.6.1.6.1

Multiply $12$ by $3$ .

$18 = - 6 b + \frac{36 + 2}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.6.1.6.2

Add $36$ and $2$ .

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$6 = 4 a + 2 b + \frac{2}{3}$

$c = \frac{2}{3}$

Step 2.3.4.7

Replace all occurrences of $a$ in $6 = 4 a + 2 b + \frac{2}{3}$ with $- b + \frac{4}{3}$ .

$6 = 4 (- b + \frac{4}{3}) + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8

Simplify the right side.

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Step 2.3.4.8.1

Simplify $4 (- b + \frac{4}{3}) + 2 b + \frac{2}{3}$ .

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Step 2.3.4.8.1.1

Simplify each term.

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Step 2.3.4.8.1.1.1

Apply the distributive property.

$6 = 4 (- b) + 4 (\frac{4}{3}) + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.1.2

Multiply $- 1$ by $4$ .

$6 = - 4 b + 4 (\frac{4}{3}) + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.1.3

Multiply $4 (\frac{4}{3})$ .

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Step 2.3.4.8.1.1.3.1

Combine $4$ and $\frac{4}{3}$ .

$6 = - 4 b + \frac{4 \cdot 4}{3} + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.1.3.2

Multiply $4$ by $4$ .

$6 = - 4 b + \frac{16}{3} + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 4 b + \frac{16}{3} + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 4 b + \frac{16}{3} + 2 b + \frac{2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.2

Simplify terms.

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Step 2.3.4.8.1.2.1

Combine the numerators over the common denominator.

$6 = - 4 b + 2 b + \frac{16 + 2}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.2.2

Simplify the expression.

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Step 2.3.4.8.1.2.2.1

Add $16$ and $2$ .

$6 = - 4 b + 2 b + \frac{18}{3}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.2.2.2

Divide $18$ by $3$ .

$6 = - 4 b + 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 4 b + 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.4.8.1.2.3

Add $- 4 b$ and $2 b$ .

$6 = - 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$6 = - 2 b + 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5

Solve for $b$ in $6 = - 2 b + 6$ .

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Step 2.3.5.1

Rewrite the equation as $- 2 b + 6 = 6$ .

$- 2 b + 6 = 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5.2

Move all terms not containing $b$ to the right side of the equation.

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Step 2.3.5.2.1

Subtract $6$ from both sides of the equation.

$- 2 b = 6 - 6$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5.2.2

Subtract $6$ from $6$ .

$- 2 b = 0$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$- 2 b = 0$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5.3

Divide each term in $- 2 b = 0$ by $- 2$ and simplify.

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Step 2.3.5.3.1

Divide each term in $- 2 b = 0$ by $- 2$ .

$\frac{- 2 b}{- 2} = \frac{0}{- 2}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5.3.2

Simplify the left side.

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Step 2.3.5.3.2.1

Cancel the common factor of $- 2$ .

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Step 2.3.5.3.2.1.1

Cancel the common factor.

$\frac{- 2 b}{- 2} = \frac{0}{- 2}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5.3.2.1.2

Divide $b$ by $1$ .

$b = \frac{0}{- 2}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$b = \frac{0}{- 2}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$b = \frac{0}{- 2}$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.5.3.3

Simplify the right side.

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Step 2.3.5.3.3.1

Divide $0$ by $- 2$ .

$b = 0$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$b = 0$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$b = 0$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$b = 0$

$18 = - 6 b + \frac{38}{3}$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6

Replace all occurrences of $b$ with $0$ in each equation.

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Step 2.3.6.1

Replace all occurrences of $b$ in $18 = - 6 b + \frac{38}{3}$ with $0$ .

$18 = - 6 \cdot 0 + \frac{38}{3}$

$b = 0$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.2

Simplify the right side.

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Step 2.3.6.2.1

Simplify $- 6 \cdot 0 + \frac{38}{3}$ .

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Step 2.3.6.2.1.1

Multiply $- 6$ by $0$ .

$18 = 0 + \frac{38}{3}$

$b = 0$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.2.1.2

Add $0$ and $\frac{38}{3}$ .

$18 = \frac{38}{3}$

$b = 0$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$18 = \frac{38}{3}$

$b = 0$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$18 = \frac{38}{3}$

$b = 0$

$54 = - 12 b + 22$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.3

Replace all occurrences of $b$ in $54 = - 12 b + 22$ with $0$ .

$54 = - 12 \cdot 0 + 22$

$18 = \frac{38}{3}$

$b = 0$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.4

Simplify the right side.

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Step 2.3.6.4.1

Simplify $- 12 \cdot 0 + 22$ .

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Step 2.3.6.4.1.1

Multiply $- 12$ by $0$ .

$54 = 0 + 22$

$18 = \frac{38}{3}$

$b = 0$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.4.1.2

Add $0$ and $22$ .

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$162 = - 20 b + 34$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.5

Replace all occurrences of $b$ in $162 = - 20 b + 34$ with $0$ .

$162 = - 20 \cdot 0 + 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.6

Simplify the right side.

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Step 2.3.6.6.1

Simplify $- 20 \cdot 0 + 34$ .

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Step 2.3.6.6.1.1

Multiply $- 20$ by $0$ .

$162 = 0 + 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.6.1.2

Add $0$ and $34$ .

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$a = - b + \frac{4}{3}$

$c = \frac{2}{3}$

Step 2.3.6.7

Replace all occurrences of $b$ in $a = - b + \frac{4}{3}$ with $0$ .

$a = - (0) + \frac{4}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$c = \frac{2}{3}$

Step 2.3.6.8

Simplify the right side.

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Step 2.3.6.8.1

Simplify $- (0) + \frac{4}{3}$ .

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Step 2.3.6.8.1.1

Multiply $- 1$ by $0$ .

$a = 0 + \frac{4}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$c = \frac{2}{3}$

Step 2.3.6.8.1.2

Add $0$ and $\frac{4}{3}$ .

$a = \frac{4}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$c = \frac{2}{3}$

$a = \frac{4}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$c = \frac{2}{3}$

$a = \frac{4}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$c = \frac{2}{3}$

$a = \frac{4}{3}$

$162 = 34$

$54 = 22$

$18 = \frac{38}{3}$

$b = 0$

$c = \frac{2}{3}$

Step 2.3.7

Since $162 = 34$ is not true, there is no solution.

No solution

Step 2.4

Calculate the value of $y$ using each $x$ value in the table and compare this value to the given $y$ value in the table.

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Step 2.4.1

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 0$ , $b = 0$ , $c = 0$ , and $x = 0$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Multiply $0$ by ${(0)}^{2}$ by adding the exponents.

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Step 2.4.1.1.1.1

Multiply $0$ by ${(0)}^{2}$ .

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Step 2.4.1.1.1.1.1

Raise $0$ to the power of $1$ .

$y = 0 \cdot {(0)}^{2} + (0) \cdot (0) + 0$

Step 2.4.1.1.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = 0^{1 + 2} + (0) \cdot (0) + 0$

Step 2.4.1.1.1.2

Add $1$ and $2$ .

$y = 0^{3} + (0) \cdot (0) + 0$

Step 2.4.1.1.2

Raising $0$ to any positive power yields $0$ .

$y = 0 + (0) \cdot (0) + 0$

Step 2.4.1.1.3

Multiply $0$ by $0$ .

$y = 0 + 0 + 0$

Step 2.4.1.2

Simplify by adding numbers.

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Step 2.4.1.2.1

Add $0$ and $0$ .

$y = 0 + 0$

Step 2.4.1.2.2

Add $0$ and $0$ .

$y = 0$

Step 2.4.2

If the table has a quadratic function rule, $y = y$ for the corresponding $x$ value, $x = 0$ . This check does not pass, since $y = 0$ and $y = \frac{2}{3}$ . The function rule can't be quadratic.

$0 \neq \frac{2}{3}$

Step 2.4.3

Since $y \neq y$ for the corresponding $x$ values, the function is not quadratic.

The function is not quadratic

Step 3

Check if the function rule is cubic.

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Step 3.1

To find if the table follows a function rule, check whether the function rule could follow the form $y = a x^{3} + b x^{2} + c x + d$ .

$y = a x^{3} + b x^{2} + c x + d$

Step 3.2

Build a set of $4$ equations from the table such that $y = a x^{3} + b x^{2} + c x + d$ .

Step 3.3

Calculate the values of $a$ , $b$ , $c$ , and $d$ .

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Step 3.3.1

Solve for $d$ in $\frac{2}{3} = a \cdot 0^{3} + b \cdot 0^{2} + d$ .

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Step 3.3.1.1

Rewrite the equation as $a \cdot 0^{3} + b \cdot 0^{2} + d = \frac{2}{3}$ .

$a \cdot 0^{3} + b \cdot 0^{2} + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.1.2

Simplify $a \cdot 0^{3} + b \cdot 0^{2} + d$ .

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Step 3.3.1.2.1

Simplify each term.

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Step 3.3.1.2.1.1

Raising $0$ to any positive power yields $0$ .

$a \cdot 0 + b \cdot 0^{2} + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.1.2.1.2

Multiply $a$ by $0$ .

$0 + b \cdot 0^{2} + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.1.2.1.3

Raising $0$ to any positive power yields $0$ .

$0 + b \cdot 0 + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.1.2.1.4

Multiply $b$ by $0$ .

$0 + 0 + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$0 + 0 + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.1.2.2

Combine the opposite terms in $0 + 0 + d$ .

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Step 3.3.1.2.2.1

Add $0$ and $0$ .

$0 + d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.1.2.2.2

Add $0$ and $d$ .

$d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$d = \frac{2}{3}$

$2 = a + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2

Replace all occurrences of $d$ with $\frac{2}{3}$ in each equation.

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Step 3.3.2.1

Replace all occurrences of $d$ in $2 = a + b \cdot 0^{2} + d$ with $\frac{2}{3}$ .

$2 = a + b \cdot 0^{2} + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.2

Simplify $2 = a + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.2.1

Simplify the left side.

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Step 3.3.2.2.1.1

Remove parentheses.

$2 = a + b \cdot 0^{2} + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$2 = a + b \cdot 0^{2} + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.2.2

Simplify the right side.

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Step 3.3.2.2.2.1

Simplify $a + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.2.2.1.1

Simplify each term.

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Step 3.3.2.2.2.1.1.1

Raising $0$ to any positive power yields $0$ .

$2 = a + b \cdot 0 + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.2.2.1.1.2

Multiply $b$ by $0$ .

$2 = a + 0 + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$2 = a + 0 + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.2.2.1.2

Add $a$ and $0$ .

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.3

Replace all occurrences of $d$ in $6 = a \cdot 2^{3} + b \cdot 0^{2} + d$ with $\frac{2}{3}$ .

$6 = a \cdot 2^{3} + b \cdot 0^{2} + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.4

Simplify $6 = a \cdot 2^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.4.1

Simplify the left side.

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Step 3.3.2.4.1.1

Remove parentheses.

$6 = a \cdot 2^{3} + b \cdot 0^{2} + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$6 = a \cdot 2^{3} + b \cdot 0^{2} + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.4.2

Simplify the right side.

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Step 3.3.2.4.2.1

Simplify $a \cdot 2^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.4.2.1.1

Simplify each term.

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Step 3.3.2.4.2.1.1.1

Raise $2$ to the power of $3$ .

$6 = a \cdot 8 + b \cdot 0^{2} + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.4.2.1.1.2

Move $8$ to the left of $a$ .

$6 = 8 \cdot a + b \cdot 0^{2} + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.4.2.1.1.3

Raising $0$ to any positive power yields $0$ .

$6 = 8 a + b \cdot 0 + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.4.2.1.1.4

Multiply $b$ by $0$ .

$6 = 8 a + 0 + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$6 = 8 a + 0 + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.4.2.1.2

Add $8 a$ and $0$ .

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.5

Replace all occurrences of $d$ in $18 = a \cdot 3^{3} + b \cdot 0^{2} + d$ with $\frac{2}{3}$ .

$18 = a \cdot 3^{3} + b \cdot 0^{2} + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.6

Simplify $18 = a \cdot 3^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.6.1

Simplify the left side.

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Step 3.3.2.6.1.1

Remove parentheses.

$18 = a \cdot 3^{3} + b \cdot 0^{2} + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$18 = a \cdot 3^{3} + b \cdot 0^{2} + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.6.2

Simplify the right side.

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Step 3.3.2.6.2.1

Simplify $a \cdot 3^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.6.2.1.1

Simplify each term.

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Step 3.3.2.6.2.1.1.1

Raise $3$ to the power of $3$ .

$18 = a \cdot 27 + b \cdot 0^{2} + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.6.2.1.1.2

Move $27$ to the left of $a$ .

$18 = 27 \cdot a + b \cdot 0^{2} + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.6.2.1.1.3

Raising $0$ to any positive power yields $0$ .

$18 = 27 a + b \cdot 0 + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.6.2.1.1.4

Multiply $b$ by $0$ .

$18 = 27 a + 0 + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$18 = 27 a + 0 + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.6.2.1.2

Add $27 a$ and $0$ .

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + d$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.7

Replace all occurrences of $d$ in $54 = a \cdot 4^{3} + b \cdot 0^{2} + d$ with $\frac{2}{3}$ .

$54 = a \cdot 4^{3} + b \cdot 0^{2} + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.8

Simplify $54 = a \cdot 4^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.8.1

Simplify the left side.

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Step 3.3.2.8.1.1

Remove parentheses.

$54 = a \cdot 4^{3} + b \cdot 0^{2} + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$54 = a \cdot 4^{3} + b \cdot 0^{2} + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.8.2

Simplify the right side.

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Step 3.3.2.8.2.1

Simplify $a \cdot 4^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.8.2.1.1

Simplify each term.

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Step 3.3.2.8.2.1.1.1

Raise $4$ to the power of $3$ .

$54 = a \cdot 64 + b \cdot 0^{2} + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.8.2.1.1.2

Move $64$ to the left of $a$ .

$54 = 64 \cdot a + b \cdot 0^{2} + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.8.2.1.1.3

Raising $0$ to any positive power yields $0$ .

$54 = 64 a + b \cdot 0 + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.8.2.1.1.4

Multiply $b$ by $0$ .

$54 = 64 a + 0 + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$54 = 64 a + 0 + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.8.2.1.2

Add $64 a$ and $0$ .

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + d$

Step 3.3.2.9

Replace all occurrences of $d$ in $162 = a \cdot 5^{3} + b \cdot 0^{2} + d$ with $\frac{2}{3}$ .

$162 = a \cdot 5^{3} + b \cdot 0^{2} + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.2.10

Simplify $162 = a \cdot 5^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.10.1

Simplify the left side.

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Step 3.3.2.10.1.1

Remove parentheses.

$162 = a \cdot 5^{3} + b \cdot 0^{2} + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = a \cdot 5^{3} + b \cdot 0^{2} + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.2.10.2

Simplify the right side.

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Step 3.3.2.10.2.1

Simplify $a \cdot 5^{3} + b \cdot 0^{2} + \frac{2}{3}$ .

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Step 3.3.2.10.2.1.1

Simplify each term.

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Step 3.3.2.10.2.1.1.1

Raise $5$ to the power of $3$ .

$162 = a \cdot 125 + b \cdot 0^{2} + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.2.10.2.1.1.2

Move $125$ to the left of $a$ .

$162 = 125 \cdot a + b \cdot 0^{2} + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.2.10.2.1.1.3

Raising $0$ to any positive power yields $0$ .

$162 = 125 a + b \cdot 0 + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.2.10.2.1.1.4

Multiply $b$ by $0$ .

$162 = 125 a + 0 + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = 125 a + 0 + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.2.10.2.1.2

Add $125 a$ and $0$ .

$162 = 125 a + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = 125 a + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = 125 a + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = 125 a + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$162 = 125 a + \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3

Solve for $a$ in $162 = 125 a + \frac{2}{3}$ .

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Step 3.3.3.1

Rewrite the equation as $125 a + \frac{2}{3} = 162$ .

$125 a + \frac{2}{3} = 162$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.2

Move all terms not containing $a$ to the right side of the equation.

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Step 3.3.3.2.1

Subtract $\frac{2}{3}$ from both sides of the equation.

$125 a = 162 - \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.2.2

To write $162$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$125 a = 162 \cdot \frac{3}{3} - \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.2.3

Combine $162$ and $\frac{3}{3}$ .

$125 a = \frac{162 \cdot 3}{3} - \frac{2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.2.4

Combine the numerators over the common denominator.

$125 a = \frac{162 \cdot 3 - 2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.2.5

Simplify the numerator.

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Step 3.3.3.2.5.1

Multiply $162$ by $3$ .

$125 a = \frac{486 - 2}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.2.5.2

Subtract $2$ from $486$ .

$125 a = \frac{484}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$125 a = \frac{484}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$125 a = \frac{484}{3}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.3

Divide each term in $125 a = \frac{484}{3}$ by $125$ and simplify.

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Step 3.3.3.3.1

Divide each term in $125 a = \frac{484}{3}$ by $125$ .

$\frac{125 a}{125} = \frac{\frac{484}{3}}{125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.3.2

Simplify the left side.

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Step 3.3.3.3.2.1

Cancel the common factor of $125$ .

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Step 3.3.3.3.2.1.1

Cancel the common factor.

$\frac{125 a}{125} = \frac{\frac{484}{3}}{125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.3.2.1.2

Divide $a$ by $1$ .

$a = \frac{\frac{484}{3}}{125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$a = \frac{\frac{484}{3}}{125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$a = \frac{\frac{484}{3}}{125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.3.3

Simplify the right side.

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Step 3.3.3.3.3.1

Multiply the numerator by the reciprocal of the denominator.

$a = \frac{484}{3} \cdot \frac{1}{125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.3.3.2

Multiply $\frac{484}{3} \cdot \frac{1}{125}$ .

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Step 3.3.3.3.3.2.1

Multiply $\frac{484}{3}$ by $\frac{1}{125}$ .

$a = \frac{484}{3 \cdot 125}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.3.3.3.2.2

Multiply $3$ by $125$ .

$a = \frac{484}{375}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$a = \frac{484}{375}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$a = \frac{484}{375}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$a = \frac{484}{375}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$a = \frac{484}{375}$

$54 = 64 a + \frac{2}{3}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4

Replace all occurrences of $a$ with $\frac{484}{375}$ in each equation.

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Step 3.3.4.1

Replace all occurrences of $a$ in $54 = 64 a + \frac{2}{3}$ with $\frac{484}{375}$ .

$54 = 64 (\frac{484}{375}) + \frac{2}{3}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2

Simplify the right side.

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Step 3.3.4.2.1

Simplify $64 (\frac{484}{375}) + \frac{2}{3}$ .

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Step 3.3.4.2.1.1

Multiply $64 (\frac{484}{375})$ .

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Step 3.3.4.2.1.1.1

Combine $64$ and $\frac{484}{375}$ .

$54 = \frac{64 \cdot 484}{375} + \frac{2}{3}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.1.2

Multiply $64$ by $484$ .

$54 = \frac{30976}{375} + \frac{2}{3}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = \frac{30976}{375} + \frac{2}{3}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.2

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{125}{125}$ .

$54 = \frac{30976}{375} + \frac{2}{3} \cdot \frac{125}{125}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.3

Write each expression with a common denominator of $375$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.3.4.2.1.3.1

Multiply $\frac{2}{3}$ by $\frac{125}{125}$ .

$54 = \frac{30976}{375} + \frac{2 \cdot 125}{3 \cdot 125}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.3.2

Multiply $3$ by $125$ .

$54 = \frac{30976}{375} + \frac{2 \cdot 125}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = \frac{30976}{375} + \frac{2 \cdot 125}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.4

Combine the numerators over the common denominator.

$54 = \frac{30976 + 2 \cdot 125}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.5

Simplify the numerator.

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Step 3.3.4.2.1.5.1

Multiply $2$ by $125$ .

$54 = \frac{30976 + 250}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.2.1.5.2

Add $30976$ and $250$ .

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$18 = 27 a + \frac{2}{3}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.3

Replace all occurrences of $a$ in $18 = 27 a + \frac{2}{3}$ with $\frac{484}{375}$ .

$18 = 27 (\frac{484}{375}) + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4

Simplify the right side.

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Step 3.3.4.4.1

Simplify $27 (\frac{484}{375}) + \frac{2}{3}$ .

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Step 3.3.4.4.1.1

Simplify each term.

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Step 3.3.4.4.1.1.1

Cancel the common factor of $3$ .

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Step 3.3.4.4.1.1.1.1

Factor $3$ out of $27$ .

$18 = 3 (9) (\frac{484}{375}) + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.1.1.2

Factor $3$ out of $375$ .

$18 = 3 \cdot (9 (\frac{484}{3 \cdot 125})) + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.1.1.3

Cancel the common factor.

$18 = 3 \cdot (9 (\frac{484}{3 \cdot 125})) + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.1.1.4

Rewrite the expression.

$18 = 9 (\frac{484}{125}) + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = 9 (\frac{484}{125}) + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.1.2

Combine $9$ and $\frac{484}{125}$ .

$18 = \frac{9 \cdot 484}{125} + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.1.3

Multiply $9$ by $484$ .

$18 = \frac{4356}{125} + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = \frac{4356}{125} + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.2

To write $\frac{4356}{125}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$18 = \frac{4356}{125} \cdot \frac{3}{3} + \frac{2}{3}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.3

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{125}{125}$ .

$18 = \frac{4356}{125} \cdot \frac{3}{3} + \frac{2}{3} \cdot \frac{125}{125}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.4

Write each expression with a common denominator of $375$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.3.4.4.1.4.1

Multiply $\frac{4356}{125}$ by $\frac{3}{3}$ .

$18 = \frac{4356 \cdot 3}{125 \cdot 3} + \frac{2}{3} \cdot \frac{125}{125}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.4.2

Multiply $125$ by $3$ .

$18 = \frac{4356 \cdot 3}{375} + \frac{2}{3} \cdot \frac{125}{125}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.4.3

Multiply $\frac{2}{3}$ by $\frac{125}{125}$ .

$18 = \frac{4356 \cdot 3}{375} + \frac{2 \cdot 125}{3 \cdot 125}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.4.4

Multiply $3$ by $125$ .

$18 = \frac{4356 \cdot 3}{375} + \frac{2 \cdot 125}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = \frac{4356 \cdot 3}{375} + \frac{2 \cdot 125}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.5

Combine the numerators over the common denominator.

$18 = \frac{4356 \cdot 3 + 2 \cdot 125}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.6

Simplify the numerator.

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Step 3.3.4.4.1.6.1

Multiply $4356$ by $3$ .

$18 = \frac{13068 + 2 \cdot 125}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.6.2

Multiply $2$ by $125$ .

$18 = \frac{13068 + 250}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.4.1.6.3

Add $13068$ and $250$ .

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$6 = 8 a + \frac{2}{3}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.5

Replace all occurrences of $a$ in $6 = 8 a + \frac{2}{3}$ with $\frac{484}{375}$ .

$6 = 8 (\frac{484}{375}) + \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6

Simplify the right side.

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Step 3.3.4.6.1

Simplify $8 (\frac{484}{375}) + \frac{2}{3}$ .

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Step 3.3.4.6.1.1

Multiply $8 (\frac{484}{375})$ .

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Step 3.3.4.6.1.1.1

Combine $8$ and $\frac{484}{375}$ .

$6 = \frac{8 \cdot 484}{375} + \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.1.2

Multiply $8$ by $484$ .

$6 = \frac{3872}{375} + \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{3872}{375} + \frac{2}{3}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.2

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{125}{125}$ .

$6 = \frac{3872}{375} + \frac{2}{3} \cdot \frac{125}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.3

Write each expression with a common denominator of $375$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.3.4.6.1.3.1

Multiply $\frac{2}{3}$ by $\frac{125}{125}$ .

$6 = \frac{3872}{375} + \frac{2 \cdot 125}{3 \cdot 125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.3.2

Multiply $3$ by $125$ .

$6 = \frac{3872}{375} + \frac{2 \cdot 125}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{3872}{375} + \frac{2 \cdot 125}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.4

Combine the numerators over the common denominator.

$6 = \frac{3872 + 2 \cdot 125}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.5

Simplify the numerator.

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Step 3.3.4.6.1.5.1

Multiply $2$ by $125$ .

$6 = \frac{3872 + 250}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.5.2

Add $3872$ and $250$ .

$6 = \frac{4122}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{4122}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.6

Cancel the common factor of $4122$ and $375$ .

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Step 3.3.4.6.1.6.1

Factor $3$ out of $4122$ .

$6 = \frac{3 (1374)}{375}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.6.2

Cancel the common factors.

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Step 3.3.4.6.1.6.2.1

Factor $3$ out of $375$ .

$6 = \frac{3 \cdot 1374}{3 \cdot 125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.6.2.2

Cancel the common factor.

$6 = \frac{3 \cdot 1374}{3 \cdot 125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.6.1.6.2.3

Rewrite the expression.

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$2 = a + \frac{2}{3}$

$d = \frac{2}{3}$

Step 3.3.4.7

Replace all occurrences of $a$ in $2 = a + \frac{2}{3}$ with $\frac{484}{375}$ .

$2 = (\frac{484}{375}) + \frac{2}{3}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.4.8

Simplify the right side.

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Step 3.3.4.8.1

Simplify $(\frac{484}{375}) + \frac{2}{3}$ .

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Step 3.3.4.8.1.1

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{125}{125}$ .

$2 = \frac{484}{375} + \frac{2}{3} \cdot \frac{125}{125}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.4.8.1.2

Write each expression with a common denominator of $375$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.3.4.8.1.2.1

Multiply $\frac{2}{3}$ by $\frac{125}{125}$ .

$2 = \frac{484}{375} + \frac{2 \cdot 125}{3 \cdot 125}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.4.8.1.2.2

Multiply $3$ by $125$ .

$2 = \frac{484}{375} + \frac{2 \cdot 125}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

$2 = \frac{484}{375} + \frac{2 \cdot 125}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.4.8.1.3

Combine the numerators over the common denominator.

$2 = \frac{484 + 2 \cdot 125}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.4.8.1.4

Simplify the numerator.

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Step 3.3.4.8.1.4.1

Multiply $2$ by $125$ .

$2 = \frac{484 + 250}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.4.8.1.4.2

Add $484$ and $250$ .

$2 = \frac{734}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

$2 = \frac{734}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

$2 = \frac{734}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

$2 = \frac{734}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

$2 = \frac{734}{375}$

$6 = \frac{1374}{125}$

$18 = \frac{13318}{375}$

$54 = \frac{31226}{375}$

$a = \frac{484}{375}$

$d = \frac{2}{3}$

Step 3.3.5

Since $2 = \frac{734}{375}$ is not true, there is no solution.

No solution

Step 3.4

Calculate the value of $y$ using each $x$ value in the table and compare this value to the given $y$ value in the table.

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Step 3.4.1

Calculate the value of $y$ such that $y = a x^{3} + b$ when $a = 0$ , $b = 0$ , $c = 0$ , $d = 0$ , and $x = 0$ .

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Step 3.4.1.1

Simplify each term.

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Step 3.4.1.1.1

Multiply $0$ by ${(0)}^{3}$ by adding the exponents.

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Step 3.4.1.1.1.1

Multiply $0$ by ${(0)}^{3}$ .

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Step 3.4.1.1.1.1.1

Raise $0$ to the power of $1$ .

$y = 0 \cdot {(0)}^{3} + (0) \cdot (0^{2}) + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = 0^{1 + 3} + (0) \cdot (0^{2}) + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.1.2

Add $1$ and $3$ .

$y = 0^{4} + (0) \cdot (0^{2}) + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.2

Raising $0$ to any positive power yields $0$ .

$y = 0 + (0) \cdot (0^{2}) + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.3

Multiply $0$ by $0^{2}$ by adding the exponents.

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Step 3.4.1.1.3.1

Multiply $0$ by $0^{2}$ .

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Step 3.4.1.1.3.1.1

Raise $0$ to the power of $1$ .

$y = 0 + 0 \cdot 0^{2} + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.3.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = 0 + 0^{1 + 2} + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.3.2

Add $1$ and $2$ .

$y = 0 + 0^{3} + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.4

Raising $0$ to any positive power yields $0$ .

$y = 0 + 0 + (0) \cdot ((0) \cdot 0)$

Step 3.4.1.1.5

Multiply $(0) ((0) \cdot 0)$ .

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Step 3.4.1.1.5.1

Multiply $0$ by $0$ .

$y = 0 + 0 + 0 \cdot 0$

Step 3.4.1.1.5.2

Multiply $0$ by $0$ .

$y = 0 + 0 + 0$

Step 3.4.1.2

Simplify by adding numbers.

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Step 3.4.1.2.1

Add $0$ and $0$ .

$y = 0 + 0$

Step 3.4.1.2.2

Add $0$ and $0$ .

$y = 0$

Step 3.4.2

If the table has a cubic function rule, $y = y$ for the corresponding $x$ value, $x = 0$ . This check does not pass, since $y = 0$ and $y = \frac{2}{3}$ . The function rule can't be cubic.

$0 \neq \frac{2}{3}$

Step 3.4.3

Since $y \neq y$ for the corresponding $x$ values, the function is not cubic.

The function is not cubic

Step 4

There are no values for $a$ , $b$ , $c$ , and $d$ in the equations $y = a x + b$ , $y = a x^{2} + b x + c$ , and $y = a x^{3} + b x^{2} + c x + d$ that work for every pair of $x$ and $y$ .

The table does not have a function rule that is linear, quadratic, or cubic.