Pre-Algebra Examples

$4 x + 3 y = - 8$

Step 1

Subtract $4 x$ from both sides of the equation.

$3 y = - 8 - 4 x$

Step 2

Divide each term in $3 y = - 8 - 4 x$ by $3$ and simplify.

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Step 2.1

Divide each term in $3 y = - 8 - 4 x$ by $3$ .

$\frac{3 y}{3} = \frac{- 8}{3} + \frac{- 4 x}{3}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $3$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 8}{3} + \frac{- 4 x}{3}$

Step 2.2.1.2

Divide $y$ by $1$ .

$y = \frac{- 8}{3} + \frac{- 4 x}{3}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Move the negative in front of the fraction.

$y = - \frac{8}{3} + \frac{- 4 x}{3}$

Step 2.3.1.2

Move the negative in front of the fraction.

$y = - \frac{8}{3} - \frac{4 x}{3}$

Step 3

The given equation $y = - \frac{8}{3} - \frac{4 x}{3}$ can not be written as $y = k x^{2}$ , so $y$ doesn't vary directly with $x^{2}$ .

$y$ doesn't vary directly with $x$