Pre-Algebra Examples

$| 5 - 2 x | > 11$

Step 1

Write $| 5 - 2 x | > 11$ as a piecewise.

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Step 1.1

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$5 - 2 x \geq 0$

Step 1.2

Solve the inequality.

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Step 1.2.1

Subtract $5$ from both sides of the inequality.

$- 2 x \geq - 5$

Step 1.2.2

Divide each term in $- 2 x \geq - 5$ by $- 2$ and simplify.

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Step 1.2.2.1

Divide each term in $- 2 x \geq - 5$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} \leq \frac{- 5}{- 2}$

Step 1.2.2.2

Simplify the left side.

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Step 1.2.2.2.1

Cancel the common factor of $- 2$ .

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Step 1.2.2.2.1.1

Cancel the common factor.

$\frac{- 2 x}{- 2} \leq \frac{- 5}{- 2}$

Step 1.2.2.2.1.2

Divide $x$ by $1$ .

$x \leq \frac{- 5}{- 2}$

Step 1.2.2.3

Simplify the right side.

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Step 1.2.2.3.1

Dividing two negative values results in a positive value.

$x \leq \frac{5}{2}$

Step 1.3

In the piece where $5 - 2 x$ is non-negative, remove the absolute value.

$5 - 2 x > 11$

Step 1.4

To find the interval for the second piece, find where the inside of the absolute value is negative.

$5 - 2 x < 0$

Step 1.5

Solve the inequality.

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Step 1.5.1

Subtract $5$ from both sides of the inequality.

$- 2 x < - 5$

Step 1.5.2

Divide each term in $- 2 x < - 5$ by $- 2$ and simplify.

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Step 1.5.2.1

Divide each term in $- 2 x < - 5$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} > \frac{- 5}{- 2}$

Step 1.5.2.2

Simplify the left side.

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Step 1.5.2.2.1

Cancel the common factor of $- 2$ .

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Step 1.5.2.2.1.1

Cancel the common factor.

$\frac{- 2 x}{- 2} > \frac{- 5}{- 2}$

Step 1.5.2.2.1.2

Divide $x$ by $1$ .

$x > \frac{- 5}{- 2}$

Step 1.5.2.3

Simplify the right side.

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Step 1.5.2.3.1

Dividing two negative values results in a positive value.

$x > \frac{5}{2}$

Step 1.6

In the piece where $5 - 2 x$ is negative, remove the absolute value and multiply by $- 1$ .

$- (5 - 2 x) > 11$

Step 1.7

Write as a piecewise.

${\begin{cases} 5 - 2 x > 11 & x \leq \frac{5}{2} \\ - (5 - 2 x) > 11 & x > \frac{5}{2} \end{cases}$

Step 1.8

Simplify $- (5 - 2 x) > 11$ .

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Step 1.8.1

Apply the distributive property.

${\begin{cases} 5 - 2 x > 11 & x \leq \frac{5}{2} \\ - 1 \cdot 5 - (- 2 x) > 11 & x > \frac{5}{2} \end{cases}$

Step 1.8.2

Multiply $- 1$ by $5$ .

${\begin{cases} 5 - 2 x > 11 & x \leq \frac{5}{2} \\ - 5 - (- 2 x) > 11 & x > \frac{5}{2} \end{cases}$

Step 1.8.3

Multiply $- 2$ by $- 1$ .

${\begin{cases} 5 - 2 x > 11 & x \leq \frac{5}{2} \\ - 5 + 2 x > 11 & x > \frac{5}{2} \end{cases}$

Step 2

Solve $5 - 2 x > 11$ for $x$ .

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Step 2.1

Move all terms not containing $x$ to the right side of the inequality.

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Step 2.1.1

Subtract $5$ from both sides of the inequality.

$- 2 x > 11 - 5$

Step 2.1.2

Subtract $5$ from $11$ .

$- 2 x > 6$

Step 2.2

Divide each term in $- 2 x > 6$ by $- 2$ and simplify.

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Step 2.2.1

Divide each term in $- 2 x > 6$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 x}{- 2} < \frac{6}{- 2}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of $- 2$ .

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Step 2.2.2.1.1

Cancel the common factor.

$\frac{- 2 x}{- 2} < \frac{6}{- 2}$

Step 2.2.2.1.2

Divide $x$ by $1$ .

$x < \frac{6}{- 2}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Divide $6$ by $- 2$ .

$x < - 3$

Step 3

Solve $- 5 + 2 x > 11$ for $x$ .

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Step 3.1

Move all terms not containing $x$ to the right side of the inequality.

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Step 3.1.1

Add $5$ to both sides of the inequality.

$2 x > 11 + 5$

Step 3.1.2

Add $11$ and $5$ .

$2 x > 16$

Step 3.2

Divide each term in $2 x > 16$ by $2$ and simplify.

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Step 3.2.1

Divide each term in $2 x > 16$ by $2$ .

$\frac{2 x}{2} > \frac{16}{2}$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $2$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{2 x}{2} > \frac{16}{2}$

Step 3.2.2.1.2

Divide $x$ by $1$ .

$x > \frac{16}{2}$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Divide $16$ by $2$ .

$x > 8$

Step 4

Find the union of the solutions.

$x < - 3$ or $x > 8$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$x < - 3 or x > 8$

Interval Notation:

$(- \infty, - 3) \cup (8, \infty)$

Step 6