Pre-Algebra Examples

$(14, 6)$ , $(26, - 9)$ , $(14, 7)$ , $(60, 7)$

Step 1

Every rectangle has three different pairs that have the same length. One pair contains the length $l$ , another pair contains the width $w$ , and the last pair contains the diagonal $d$ .

The distance between:

$(14, 6)$ and $(26, - 9)$ is $3 \sqrt{41}$

$(14, 6)$ and $(14, 7)$ is $1$

$(14, 6)$ and $(60, 7)$ is $\sqrt{2117}$

$(26, - 9)$ and $(14, 7)$ is $20$

$(14, 7)$ and $(60, 7)$ is $46$

$(26, - 9)$ and $(60, 7)$ is $2 \sqrt{353}$

Step 2

The distances between the points show that there are no three different pairs that contain the length, width, and diagonal and have the same length, so the shape is not a rectangle.

Not a rectangle

Step 3