Pre-Algebra Examples

$y + 5 = - \frac{1}{3} \cdot (x - 5)$

Step 1

The standard form of a linear equation is $A x + B y = C$ .

Step 2

Multiply both sides by $3$ .

$3 (y + 5) = 3 (- \frac{1}{3} \cdot (x - 5))$

Step 3

Simplify the left side.

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Step 3.1

Simplify $3 (y + 5)$ .

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Step 3.1.1

Apply the distributive property.

$3 y + 3 \cdot 5 = 3 (- \frac{1}{3} \cdot (x - 5))$

Step 3.1.2

Multiply $3$ by $5$ .

$3 y + 15 = 3 (- \frac{1}{3} \cdot (x - 5))$

Step 4

Simplify the right side.

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Step 4.1

Simplify $3 (- \frac{1}{3} \cdot (x - 5))$ .

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Step 4.1.1

Apply the distributive property.

$3 y + 15 = 3 (- \frac{1}{3} x - \frac{1}{3} \cdot - 5)$

Step 4.1.2

Combine $x$ and $\frac{1}{3}$ .

$3 y + 15 = 3 (- \frac{x}{3} - \frac{1}{3} \cdot - 5)$

Step 4.1.3

Multiply $- \frac{1}{3} \cdot - 5$ .

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Step 4.1.3.1

Multiply $- 5$ by $- 1$ .

$3 y + 15 = 3 (- \frac{x}{3} + 5 (\frac{1}{3}))$

Step 4.1.3.2

Combine $5$ and $\frac{1}{3}$ .

$3 y + 15 = 3 (- \frac{x}{3} + \frac{5}{3})$

Step 4.1.4

Apply the distributive property.

$3 y + 15 = 3 (- \frac{x}{3}) + 3 (\frac{5}{3})$

Step 4.1.5

Cancel the common factor of $3$ .

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Step 4.1.5.1

Move the leading negative in $- \frac{x}{3}$ into the numerator.

$3 y + 15 = 3 \frac{- x}{3} + 3 (\frac{5}{3})$

Step 4.1.5.2

Cancel the common factor.

$3 y + 15 = 3 \frac{- x}{3} + 3 (\frac{5}{3})$

Step 4.1.5.3

Rewrite the expression.

$3 y + 15 = - x + 3 (\frac{5}{3})$

Step 4.1.6

Cancel the common factor of $3$ .

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Step 4.1.6.1

Cancel the common factor.

$3 y + 15 = - x + 3 (\frac{5}{3})$

Step 4.1.6.2

Rewrite the expression.

$3 y + 15 = - x + 5$

Step 5

Move all terms containing variables to the left side of the equation.

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Step 5.1

Add $x$ to both sides of the equation.

$3 y + 15 + x = 5$

Step 5.2

Move $15$ .

$3 y + x + 15 = 5$

Step 5.3

Reorder $3 y$ and $x$ .

$x + 3 y + 15 = 5$

Step 6

Move all terms not containing a variable to the right side of the equation.

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Step 6.1

Subtract $15$ from both sides of the equation.

$x + 3 y = 5 - 15$

Step 6.2

Subtract $15$ from $5$ .

$x + 3 y = - 10$

Step 7