Pre-Algebra Examples

${(x - 3)}^{2} - 5 = 4$

Step 1

Add $5$ to both sides of the equation.

${(x - 3)}^{2} = 4 + 5$

Step 2

Add $4$ and $5$ .

${(x - 3)}^{2} = 9$

Step 3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 3 = \pm \sqrt{9}$

Step 4

Simplify $\pm \sqrt{9}$ .

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Step 4.1

Rewrite $9$ as $3^{2}$ .

$x - 3 = \pm \sqrt{3^{2}}$

Step 4.2

Pull terms out from under the radical, assuming positive real numbers.

$x - 3 = \pm 3$

Step 5

The complete solution is the result of both the positive and negative portions of the solution.

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Step 5.1

First, use the positive value of the $\pm$ to find the first solution.

$x - 3 = 3$

Step 5.2

Move all terms not containing $x$ to the right side of the equation.

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Step 5.2.1

Add $3$ to both sides of the equation.

$x = 3 + 3$

Step 5.2.2

Add $3$ and $3$ .

$x = 6$

Step 5.3

Next, use the negative value of the $\pm$ to find the second solution.

$x - 3 = - 3$

Step 5.4

Move all terms not containing $x$ to the right side of the equation.

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Step 5.4.1

Add $3$ to both sides of the equation.

$x = - 3 + 3$

Step 5.4.2

Add $- 3$ and $3$ .

$x = 0$

Step 5.5

The complete solution is the result of both the positive and negative portions of the solution.

$x = 6, 0$