Pre-Algebra Examples

 $\begin{array}{r} b_{1} = & 12 \\ b_{2} = & h \\ h = & 22 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 22$ and bases ( $b_{1} = 12$ and $b_{2} = h$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 22 \cdot (12 + h)$

Step 3

Cancel the common factor of $2$ .

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Step 3.1

Factor $2$ out of $22$ .

$\frac{1}{2} \cdot (2 (11)) \cdot (12 + h)$

Step 3.2

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 11) \cdot (12 + h)$

Step 3.3

Rewrite the expression.

$11 \cdot (12 + h)$

Step 4

Apply the distributive property.

$11 \cdot 12 + 11 h$

Step 5

Multiply $11$ by $12$ .

$132 + 11 h$