Pre-Algebra Examples

 $\begin{array}{r} h = & 9 \\ r = & 1 \end{array}$

Step 1

The volume of a cone is equal to $\frac{1}{3}$ times the area of the base $π r^{2}$ times the height $h$ .

$\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)$

Step 2

Substitute the values of the radius $r = 1$ and height $h = 9$ into the formula to find the volume of the cone. Pi $π$ is approximately equal to $3.14$ .

$\frac{1}{3} \cdot π \cdot 1^{2} \cdot 9$

Step 3

Combine $\frac{1}{3}$ and $π$ .

$\frac{π}{3} \cdot 1^{2} \cdot 9$

Step 4

Simplify the expression.

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Step 4.1

One to any power is one.

$\frac{π}{3} \cdot 1 \cdot 9$

Step 4.2

Multiply $\frac{π}{3}$ by $1$ .

$\frac{π}{3} \cdot 9$

Step 5

Cancel the common factor of $3$ .

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Step 5.1

Factor $3$ out of $9$ .

$\frac{π}{3} \cdot (3 (3))$

Step 5.2

Cancel the common factor.

$\frac{π}{3} \cdot (3 \cdot 3)$

Step 5.3

Rewrite the expression.

$π \cdot 3$

Step 6

Move $3$ to the left of $π$ .

$3 π$

Step 7

The result can be shown in multiple forms.

Exact Form:

$3 π$

Decimal Form:

$9.42477796 \dots$