Pre-Algebra Examples

 $\begin{array}{r} h = & 16 \\ l = & 16 \\ w = & 16 \end{array}$

Step 1

The surface area of a box is equal to the sum of the areas of each side of the box.

$2 \cdot (l e n g t h) \cdot (w i d t h) + 2 \cdot (l e n g t h) \cdot (h e i g h t) + 2 \cdot (w i d t h) \cdot (h e i g h t)$

Step 2

Substitute the values of the length $l = 16$ , the width $w = 16$ , and the height $h = 16$ into the formula.

$2 \cdot 16 \cdot 16 + 2 \cdot 16 \cdot 16 + 2 \cdot 16 \cdot 16$

Step 3

Simplify each term.

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Step 3.1

Multiply $2 \cdot 16 \cdot 16$ .

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Step 3.1.1

Multiply $2$ by $16$ .

$32 \cdot 16 + 2 \cdot 16 \cdot 16 + 2 \cdot 16 \cdot 16$

Step 3.1.2

Multiply $32$ by $16$ .

$512 + 2 \cdot 16 \cdot 16 + 2 \cdot 16 \cdot 16$

Step 3.2

Multiply $2 \cdot 16 \cdot 16$ .

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Step 3.2.1

Multiply $2$ by $16$ .

$512 + 32 \cdot 16 + 2 \cdot 16 \cdot 16$

Step 3.2.2

Multiply $32$ by $16$ .

$512 + 512 + 2 \cdot 16 \cdot 16$

Step 3.3

Multiply $2 \cdot 16 \cdot 16$ .

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Step 3.3.1

Multiply $2$ by $16$ .

$512 + 512 + 32 \cdot 16$

Step 3.3.2

Multiply $32$ by $16$ .

$512 + 512 + 512$

Step 4

Simplify by adding numbers.

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Step 4.1

Add $512$ and $512$ .

$1024 + 512$

Step 4.2

Add $1024$ and $512$ .

$1536$