Pre-Algebra Examples

$\frac{86 + 73 + 79 + 2 x}{5} = 80$

Step 1

Multiply both sides by $5$ .

$\frac{86 + 73 + 79 + 2 x}{5} \cdot 5 = 80 \cdot 5$

Step 2

Simplify.

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Step 2.1

Simplify the left side.

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Step 2.1.1

Simplify $\frac{86 + 73 + 79 + 2 x}{5} \cdot 5$ .

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Step 2.1.1.1

Simplify the numerator.

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Step 2.1.1.1.1

Add $86$ and $73$ .

$\frac{159 + 79 + 2 x}{5} \cdot 5 = 80 \cdot 5$

Step 2.1.1.1.2

Add $159$ and $79$ .

$\frac{238 + 2 x}{5} \cdot 5 = 80 \cdot 5$

Step 2.1.1.1.3

Factor $2$ out of $238 + 2 x$ .

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Step 2.1.1.1.3.1

Factor $2$ out of $238$ .

$\frac{2 \cdot 119 + 2 x}{5} \cdot 5 = 80 \cdot 5$

Step 2.1.1.1.3.2

Factor $2$ out of $2 \cdot 119 + 2 x$ .

$\frac{2 (119 + x)}{5} \cdot 5 = 80 \cdot 5$

Step 2.1.1.2

Simplify terms.

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Step 2.1.1.2.1

Cancel the common factor of $5$ .

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Step 2.1.1.2.1.1

Cancel the common factor.

$\frac{2 (119 + x)}{5} \cdot 5 = 80 \cdot 5$

Step 2.1.1.2.1.2

Rewrite the expression.

$2 (119 + x) = 80 \cdot 5$

Step 2.1.1.2.2

Apply the distributive property.

$2 \cdot 119 + 2 x = 80 \cdot 5$

Step 2.1.1.2.3

Simplify the expression.

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Step 2.1.1.2.3.1

Multiply $2$ by $119$ .

$238 + 2 x = 80 \cdot 5$

Step 2.1.1.2.3.2

Reorder $238$ and $2 x$ .

$2 x + 238 = 80 \cdot 5$

Step 2.2

Simplify the right side.

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Step 2.2.1

Multiply $80$ by $5$ .

$2 x + 238 = 400$

Step 3

Solve for $x$ .

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Step 3.1

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1.1

Subtract $238$ from both sides of the equation.

$2 x = 400 - 238$

Step 3.1.2

Subtract $238$ from $400$ .

$2 x = 162$

Step 3.2

Divide each term in $2 x = 162$ by $2$ and simplify.

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Step 3.2.1

Divide each term in $2 x = 162$ by $2$ .

$\frac{2 x}{2} = \frac{162}{2}$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $2$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{162}{2}$

Step 3.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{162}{2}$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Divide $162$ by $2$ .

$x = 81$