Pre-Algebra Examples

$- 7 x + 4 (3 - 5 x) = 0$

Step 1

Simplify $- 7 x + 4 (3 - 5 x)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$- 7 x + 4 \cdot 3 + 4 (- 5 x) = 0$

Step 1.1.2

Multiply $4$ by $3$ .

$- 7 x + 12 + 4 (- 5 x) = 0$

Step 1.1.3

Multiply $- 5$ by $4$ .

$- 7 x + 12 - 20 x = 0$

$- 7 x + 12 - 20 x = 0$

Step 1.2

Subtract $20 x$ from $- 7 x$ .

$- 27 x + 12 = 0$

$- 27 x + 12 = 0$

Step 2

Subtract $12$ from both sides of the equation.

$- 27 x = - 12$

Step 3

Divide each term in $- 27 x = - 12$ by $- 27$ and simplify.

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Step 3.1

Divide each term in $- 27 x = - 12$ by $- 27$ .

$\frac{- 27 x}{- 27} = \frac{- 12}{- 27}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $- 27$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{- 27 x}{- 27} = \frac{- 12}{- 27}$

Step 3.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 12}{- 27}$

$x = \frac{- 12}{- 27}$

$x = \frac{- 12}{- 27}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Cancel the common factor of $- 12$ and $- 27$ .

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Step 3.3.1.1

Factor $- 3$ out of $- 12$ .

$x = \frac{- 3 (4)}{- 27}$

Step 3.3.1.2

Cancel the common factors.

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Step 3.3.1.2.1

Factor $- 3$ out of $- 27$ .

$x = \frac{- 3 \cdot 4}{- 3 \cdot 9}$

Step 3.3.1.2.2

Cancel the common factor.

$x = \frac{- 3 \cdot 4}{- 3 \cdot 9}$

Step 3.3.1.2.3

Rewrite the expression.

$x = \frac{4}{9}$

$x = \frac{4}{9}$

$x = \frac{4}{9}$

$x = \frac{4}{9}$

$x = \frac{4}{9}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{4}{9}$

Decimal Form:

$x = 0.\overline{4}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$