Pre-Algebra Examples

$7 x + 3 (2 x + 5) = 10 x + 17$

Step 1

Simplify $7 x + 3 (2 x + 5)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$7 x + 3 (2 x) + 3 \cdot 5 = 10 x + 17$

Step 1.1.2

Multiply $2$ by $3$ .

$7 x + 6 x + 3 \cdot 5 = 10 x + 17$

Step 1.1.3

Multiply $3$ by $5$ .

$7 x + 6 x + 15 = 10 x + 17$

Step 1.2

Add $7 x$ and $6 x$ .

$13 x + 15 = 10 x + 17$

Step 2

Move all terms containing $x$ to the left side of the equation.

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Step 2.1

Subtract $10 x$ from both sides of the equation.

$13 x + 15 - 10 x = 17$

Step 2.2

Subtract $10 x$ from $13 x$ .

$3 x + 15 = 17$

Step 3

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1

Subtract $15$ from both sides of the equation.

$3 x = 17 - 15$

Step 3.2

Subtract $15$ from $17$ .

$3 x = 2$

Step 4

Divide each term in $3 x = 2$ by $3$ and simplify.

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Step 4.1

Divide each term in $3 x = 2$ by $3$ .

$\frac{3 x}{3} = \frac{2}{3}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $3$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{2}{3}$

Step 4.2.1.2

Divide $x$ by $1$ .

$x = \frac{2}{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{2}{3}$

Decimal Form:

$x = 0.\overline{6}$