Pre-Algebra Examples

$- 4 x + \frac{1}{3} = \frac{8}{3}$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Tap for more steps...

Step 1.1

Subtract $\frac{1}{3}$ from both sides of the equation.

$- 4 x = \frac{8}{3} - \frac{1}{3}$

Step 1.2

Combine the numerators over the common denominator.

$- 4 x = \frac{8 - 1}{3}$

Step 1.3

Subtract $1$ from $8$ .

$- 4 x = \frac{7}{3}$

Step 2

Divide each term in $- 4 x = \frac{7}{3}$ by $- 4$ and simplify.

Tap for more steps...

Step 2.1

Divide each term in $- 4 x = \frac{7}{3}$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{\frac{7}{3}}{- 4}$

Step 2.2

Simplify the left side.

Tap for more steps...

Step 2.2.1

Cancel the common factor of $- 4$ .

Tap for more steps...

Step 2.2.1.1

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{\frac{7}{3}}{- 4}$

Step 2.2.1.2

Divide $x$ by $1$ .

$x = \frac{\frac{7}{3}}{- 4}$

Step 2.3

Simplify the right side.

Tap for more steps...

Step 2.3.1

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{7}{3} \cdot \frac{1}{- 4}$

Step 2.3.2

Move the negative in front of the fraction.

$x = \frac{7}{3} (- \frac{1}{4})$

Step 2.3.3

Multiply $\frac{7}{3} (- \frac{1}{4})$ .

Tap for more steps...

Step 2.3.3.1

Multiply $\frac{7}{3}$ by $\frac{1}{4}$ .

$x = - \frac{7}{3 \cdot 4}$

Step 2.3.3.2

Multiply $3$ by $4$ .

$x = - \frac{7}{12}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{7}{12}$

Decimal Form:

$x = - 0.58\overline{3}$