Pre-Algebra Examples

$5 (3 x - 4) = 16 x$

Step 1

Simplify $5 (3 x - 4)$ .

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Step 1.1

Rewrite.

$0 + 0 + 5 (3 x - 4) = 16 x$

Step 1.2

Simplify by adding zeros.

$5 (3 x - 4) = 16 x$

Step 1.3

Apply the distributive property.

$5 (3 x) + 5 \cdot - 4 = 16 x$

Step 1.4

Multiply.

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Step 1.4.1

Multiply $3$ by $5$ .

$15 x + 5 \cdot - 4 = 16 x$

Step 1.4.2

Multiply $5$ by $- 4$ .

$15 x - 20 = 16 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

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Step 2.1

Subtract $16 x$ from both sides of the equation.

$15 x - 20 - 16 x = 0$

Step 2.2

Subtract $16 x$ from $15 x$ .

$- x - 20 = 0$

Step 3

Add $20$ to both sides of the equation.

$- x = 20$

Step 4

Divide each term in $- x = 20$ by $- 1$ and simplify.

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Step 4.1

Divide each term in $- x = 20$ by $- 1$ .

$\frac{- x}{- 1} = \frac{20}{- 1}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{20}{- 1}$

Step 4.2.2

Divide $x$ by $1$ .

$x = \frac{20}{- 1}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $20$ by $- 1$ .

$x = - 20$