Pre-Algebra Examples

Solve for a a=1/2*(h(b(1+b*2)))
a=12(h(b(1+b2)))a=12(h(b(1+b2)))
Step 1
Remove parentheses.
a=12(hb(1+b2))a=12(hb(1+b2))
Step 2
Remove parentheses.
a=12((hb)(1+b2))a=12((hb)(1+b2))
Step 3
Remove parentheses.
a=12(hb(1+b2))a=12(hb(1+b2))
Step 4
Simplify 12(hb(1+b2))12(hb(1+b2)).
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Step 4.1
Move 22 to the left of bb.
a=12(hb(1+2b))a=12(hb(1+2b))
Step 4.2
Simplify by multiplying through.
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Step 4.2.1
Apply the distributive property.
a=12(hb1+hb(2b))a=12(hb1+hb(2b))
Step 4.2.2
Simplify the expression.
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Step 4.2.2.1
Multiply hh by 11.
a=12(bh+hb(2b))a=12(bh+hb(2b))
Step 4.2.2.2
Rewrite using the commutative property of multiplication.
a=12(bh+2hbb)a=12(bh+2hbb)
a=12(bh+2hbb)a=12(bh+2hbb)
a=12(bh+2hbb)a=12(bh+2hbb)
Step 4.3
Multiply bb by bb by adding the exponents.
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Step 4.3.1
Move bb.
a=12(bh+2h(bb))a=12(bh+2h(bb))
Step 4.3.2
Multiply bb by bb.
a=12(bh+2hb2)a=12(bh+2hb2)
a=12(bh+2hb2)a=12(bh+2hb2)
Step 4.4
Apply the distributive property.
a=12(bh)+12(2hb2)a=12(bh)+12(2hb2)
Step 4.5
Multiply 12(bh)12(bh).
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Step 4.5.1
Combine bb and 1212.
a=b2h+12(2hb2)a=b2h+12(2hb2)
Step 4.5.2
Combine b2b2 and hh.
a=bh2+12(2hb2)a=bh2+12(2hb2)
a=bh2+12(2hb2)
Step 4.6
Cancel the common factor of 2.
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Step 4.6.1
Factor 2 out of 2hb2.
a=bh2+12(2(hb2))
Step 4.6.2
Cancel the common factor.
a=bh2+12(2(hb2))
Step 4.6.3
Rewrite the expression.
a=bh2+hb2
a=bh2+hb2
Step 4.7
Simplify with commuting.
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Step 4.7.1
Reorder h and b2.
a=bh2+b2h
Step 4.7.2
Reorder bh2 and b2h.
a=b2h+bh2
a=b2h+bh2
a=b2h+bh2
 [x2  12  π  xdx ]