Pre-Algebra Examples

$20 g^{2} = 16 g$

Step 1

Subtract $16 g$ from both sides of the equation.

$20 g^{2} - 16 g = 0$

Step 2

Factor $4 g$ out of $20 g^{2} - 16 g$ .

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Step 2.1

Factor $4 g$ out of $20 g^{2}$ .

$4 g (5 g) - 16 g = 0$

Step 2.2

Factor $4 g$ out of $- 16 g$ .

$4 g (5 g) + 4 g (- 4) = 0$

Step 2.3

Factor $4 g$ out of $4 g (5 g) + 4 g (- 4)$ .

$4 g (5 g - 4) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$g = 0$

$5 g - 4 = 0$

Step 4

Set $g$ equal to $0$ .

$g = 0$

Step 5

Set $5 g - 4$ equal to $0$ and solve for $g$ .

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Step 5.1

Set $5 g - 4$ equal to $0$ .

$5 g - 4 = 0$

Step 5.2

Solve $5 g - 4 = 0$ for $g$ .

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Step 5.2.1

Add $4$ to both sides of the equation.

$5 g = 4$

Step 5.2.2

Divide each term in $5 g = 4$ by $5$ and simplify.

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Step 5.2.2.1

Divide each term in $5 g = 4$ by $5$ .

$\frac{5 g}{5} = \frac{4}{5}$

Step 5.2.2.2

Simplify the left side.

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Step 5.2.2.2.1

Cancel the common factor of $5$ .

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Step 5.2.2.2.1.1

Cancel the common factor.

$\frac{5 g}{5} = \frac{4}{5}$

Step 5.2.2.2.1.2

Divide $g$ by $1$ .

$g = \frac{4}{5}$

Step 6

The final solution is all the values that make $4 g (5 g - 4) = 0$ true.

$g = 0, \frac{4}{5}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$g = 0, \frac{4}{5}$

Decimal Form:

$g = 0, 0.8$