Pre-Algebra Examples

$13000 = p {(1 + 0.07)}^{20}$

Step 1

Rewrite the equation as $p {(1 + 0.07)}^{20} = 13000$ .

$p {(1 + 0.07)}^{20} = 13000$

Step 2

Add $1$ and $0.07$ .

$p \cdot {1.07}^{20} = 13000$

Step 3

Divide each term in $p \cdot {1.07}^{20} = 13000$ by ${1.07}^{20}$ and simplify.

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Step 3.1

Divide each term in $p \cdot {1.07}^{20} = 13000$ by ${1.07}^{20}$ .

$\frac{p \cdot {1.07}^{20}}{{1.07}^{20}} = \frac{13000}{{1.07}^{20}}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of ${1.07}^{20}$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{p \cdot {1.07}^{20}}{{1.07}^{20}} = \frac{13000}{{1.07}^{20}}$

Step 3.2.1.2

Divide $p$ by $1$ .

$p = \frac{13000}{{1.07}^{20}}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Raise $1.07$ to the power of $20$ .

$p = \frac{13000}{3.86968446}$

Step 3.3.2

Divide $13000$ by $3.86968446$ .

$p = 3359.44703658$