Pre-Algebra Examples

$3 (w + 2) - w = 2 (w - 1) + 5$

Step 1

Simplify $3 (w + 2) - w$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$3 w + 3 \cdot 2 - w = 2 (w - 1) + 5$

Step 1.1.2

Multiply $3$ by $2$ .

$3 w + 6 - w = 2 (w - 1) + 5$

$3 w + 6 - w = 2 (w - 1) + 5$

Step 1.2

Subtract $w$ from $3 w$ .

$2 w + 6 = 2 (w - 1) + 5$

$2 w + 6 = 2 (w - 1) + 5$

Step 2

Simplify $2 (w - 1) + 5$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$2 w + 6 = 2 w + 2 \cdot - 1 + 5$

Step 2.1.2

Multiply $2$ by $- 1$ .

$2 w + 6 = 2 w - 2 + 5$

$2 w + 6 = 2 w - 2 + 5$

Step 2.2

Add $- 2$ and $5$ .

$2 w + 6 = 2 w + 3$

$2 w + 6 = 2 w + 3$

Step 3

Move all terms containing $w$ to the left side of the equation.

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Step 3.1

Subtract $2 w$ from both sides of the equation.

$2 w + 6 - 2 w = 3$

Step 3.2

Combine the opposite terms in $2 w + 6 - 2 w$ .

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Step 3.2.1

Subtract $2 w$ from $2 w$ .

$0 + 6 = 3$

Step 3.2.2

Add $0$ and $6$ .

$6 = 3$

$6 = 3$

$6 = 3$

Step 4

Since $6 \neq 3$ , there are no solutions.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$