Pre-Algebra Examples

$(2 x^{5} - 5 x^{3}) - (9 x^{2} - 7 x^{3})$

Step 1

Apply the distributive property.

$2 x^{5} - 5 x^{3} - (9 x^{2}) - (- 7 x^{3})$

Step 2

Multiply $9$ by $- 1$ .

$2 x^{5} - 5 x^{3} - 9 x^{2} - (- 7 x^{3})$

Step 3

Multiply $- 7$ by $- 1$ .

$2 x^{5} - 5 x^{3} - 9 x^{2} + 7 x^{3}$

Step 4

Add $- 5 x^{3}$ and $7 x^{3}$ .

$2 x^{5} + 2 x^{3} - 9 x^{2}$

Step 5

Factor $x^{2}$ out of $2 x^{5} + 2 x^{3} - 9 x^{2}$ .

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Step 5.1

Factor $x^{2}$ out of $2 x^{5}$ .

$x^{2} (2 x^{3}) + 2 x^{3} - 9 x^{2}$

Step 5.2

Factor $x^{2}$ out of $2 x^{3}$ .

$x^{2} (2 x^{3}) + x^{2} (2 x) - 9 x^{2}$

Step 5.3

Factor $x^{2}$ out of $- 9 x^{2}$ .

$x^{2} (2 x^{3}) + x^{2} (2 x) + x^{2} \cdot - 9$

Step 5.4

Factor $x^{2}$ out of $x^{2} (2 x^{3}) + x^{2} (2 x)$ .

$x^{2} (2 x^{3} + 2 x) + x^{2} \cdot - 9$

Step 5.5

Factor $x^{2}$ out of $x^{2} (2 x^{3} + 2 x) + x^{2} \cdot - 9$ .

$x^{2} (2 x^{3} + 2 x - 9)$