Pre-Algebra Examples

$7.8$ , $8.4$ , $8.4$ , $9.8$ , $5.9$ , $9.3$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{7.8 + 8.4 + 8.4 + 9.8 + 5.9 + 9.3}{6}$

Step 2

Simplify the numerator.

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Step 2.1

Add $7.8$ and $8.4$ .

$\frac{16.2 + 8.4 + 9.8 + 5.9 + 9.3}{6}$

Step 2.2

Add $16.2$ and $8.4$ .

$\frac{24.6 + 9.8 + 5.9 + 9.3}{6}$

Step 2.3

Add $24.6$ and $9.8$ .

$\frac{34.4 + 5.9 + 9.3}{6}$

Step 2.4

Add $34.4$ and $5.9$ .

$\frac{40.3 + 9.3}{6}$

Step 2.5

Add $40.3$ and $9.3$ .

$\frac{49.6}{6}$

Step 3

Divide $49.6$ by $6$ .

$8.2\overline{6}$

Step 4

Divide.

$8.2\overline{6}$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$8.27$