Pre-Algebra Examples

$5 + 3 \cdot 18 \div 9 - 3$

Step 1

Multiply $3$ by $18$ .

$5 + 54 \div 9 - 3$

Step 2

Find the common denominator.

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Step 2.1

Write $5$ as a fraction with denominator $1$ .

$\frac{5}{1} + 54 \div 9 - 3$

Step 2.2

Multiply $\frac{5}{1}$ by $\frac{9}{9}$ .

$\frac{5}{1} \cdot \frac{9}{9} + 54 \div 9 - 3$

Step 2.3

Multiply $\frac{5}{1}$ by $\frac{9}{9}$ .

$\frac{5 \cdot 9}{9} + 54 \div 9 - 3$

Step 2.4

Write $- 3$ as a fraction with denominator $1$ .

$\frac{5 \cdot 9}{9} + 54 \div 9 + \frac{- 3}{1}$

Step 2.5

Multiply $\frac{- 3}{1}$ by $\frac{9}{9}$ .

$\frac{5 \cdot 9}{9} + 54 \div 9 + \frac{- 3}{1} \cdot \frac{9}{9}$

Step 2.6

Multiply $\frac{- 3}{1}$ by $\frac{9}{9}$ .

$\frac{5 \cdot 9}{9} + 54 \div 9 + \frac{- 3 \cdot 9}{9}$

Step 3

Combine the numerators over the common denominator.

$\frac{5 \cdot 9 + 54 - 3 \cdot 9}{9}$

Step 4

Simplify each term.

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Step 4.1

Multiply $5$ by $9$ .

$\frac{45 + 54 - 3 \cdot 9}{9}$

Step 4.2

Multiply $- 3$ by $9$ .

$\frac{45 + 54 - 27}{9}$

Step 5

Simplify the expression.

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Step 5.1

Add $45$ and $54$ .

$\frac{99 - 27}{9}$

Step 5.2

Subtract $27$ from $99$ .

$\frac{72}{9}$

Step 5.3

Divide $72$ by $9$ .

$8$