Pre-Algebra Examples

$\frac{| 6 - 2 | + 3}{8 + 2 \cdot 5}$

Step 1

Simplify the numerator.

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Step 1.1

Subtract $2$ from $6$ .

$\frac{| 4 | + 3}{8 + 2 \cdot 5}$

Step 1.2

The absolute value is the distance between a number and zero. The distance between $0$ and $4$ is $4$ .

$\frac{4 + 3}{8 + 2 \cdot 5}$

Step 1.3

Add $4$ and $3$ .

$\frac{7}{8 + 2 \cdot 5}$

Step 2

Simplify the denominator.

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Step 2.1

Multiply $2$ by $5$ .

$\frac{7}{8 + 10}$

Step 2.2

Add $8$ and $10$ .

$\frac{7}{18}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$\frac{7}{18}$

Decimal Form:

$0.3\overline{8}$