Pre-Algebra Examples

$a = \frac{1}{2} \cdot ((b + b) h)$

Step 1

Rewrite the equation as $\frac{1}{2} \cdot ((b + b) h) = a$ .

$\frac{1}{2} \cdot ((b + b) h) = a$

Step 2

Multiply both sides of the equation by $2$ .

$2 (\frac{1}{2} \cdot ((b + b) h)) = 2 a$

Step 3

Simplify the left side.

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Step 3.1

Simplify $2 (\frac{1}{2} \cdot ((b + b) h))$ .

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Step 3.1.1

Add $b$ and $b$ .

$2 (\frac{1}{2} \cdot (2 b h)) = 2 a$

Step 3.1.2

Cancel the common factor of $2$ .

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Step 3.1.2.1

Factor $2$ out of $2 b h$ .

$2 (\frac{1}{2} \cdot (2 (b h))) = 2 a$

Step 3.1.2.2

Cancel the common factor.

$2 (\frac{1}{2} \cdot (2 (b h))) = 2 a$

Step 3.1.2.3

Rewrite the expression.

$2 (b h) = 2 a$

$2 b h = 2 a$

$2 b h = 2 a$

$2 b h = 2 a$

Step 4

Divide each term in $2 b h = 2 a$ by $2 h$ and simplify.

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Step 4.1

Divide each term in $2 b h = 2 a$ by $2 h$ .

$\frac{2 b h}{2 h} = \frac{2 a}{2 h}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $2$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{2 b h}{2 h} = \frac{2 a}{2 h}$

Step 4.2.1.2

Rewrite the expression.

$\frac{b h}{h} = \frac{2 a}{2 h}$

$\frac{b h}{h} = \frac{2 a}{2 h}$

Step 4.2.2

Cancel the common factor of $h$ .

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Step 4.2.2.1

Cancel the common factor.

$\frac{b h}{h} = \frac{2 a}{2 h}$

Step 4.2.2.2

Divide $b$ by $1$ .

$b = \frac{2 a}{2 h}$

$b = \frac{2 a}{2 h}$

$b = \frac{2 a}{2 h}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Cancel the common factor of $2$ .

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Step 4.3.1.1

Cancel the common factor.

$b = \frac{2 a}{2 h}$

Step 4.3.1.2

Rewrite the expression.

$b = \frac{a}{h}$

$b = \frac{a}{h}$

$b = \frac{a}{h}$

$b = \frac{a}{h}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$