Pre-Algebra Examples

$2 (u + 2) + u = 3 (u - 1) + 6$

Step 1

Simplify $2 (u + 2) + u$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$2 u + 2 \cdot 2 + u = 3 (u - 1) + 6$

Step 1.1.2

Multiply $2$ by $2$ .

$2 u + 4 + u = 3 (u - 1) + 6$

$2 u + 4 + u = 3 (u - 1) + 6$

Step 1.2

Add $2 u$ and $u$ .

$3 u + 4 = 3 (u - 1) + 6$

$3 u + 4 = 3 (u - 1) + 6$

Step 2

Simplify $3 (u - 1) + 6$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$3 u + 4 = 3 u + 3 \cdot - 1 + 6$

Step 2.1.2

Multiply $3$ by $- 1$ .

$3 u + 4 = 3 u - 3 + 6$

$3 u + 4 = 3 u - 3 + 6$

Step 2.2

Add $- 3$ and $6$ .

$3 u + 4 = 3 u + 3$

$3 u + 4 = 3 u + 3$

Step 3

Move all terms containing $u$ to the left side of the equation.

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Step 3.1

Subtract $3 u$ from both sides of the equation.

$3 u + 4 - 3 u = 3$

Step 3.2

Combine the opposite terms in $3 u + 4 - 3 u$ .

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Step 3.2.1

Subtract $3 u$ from $3 u$ .

$0 + 4 = 3$

Step 3.2.2

Add $0$ and $4$ .

$4 = 3$

$4 = 3$

$4 = 3$

Step 4

Since $4 \neq 3$ , there are no solutions.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$