Pre-Algebra Examples

$- x + 2 y = 6$

Step 1

Solve the equation for $y$ .

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Step 1.1

Add $x$ to both sides of the equation.

$2 y = 6 + x$

Step 1.2

Divide each term in $2 y = 6 + x$ by $2$ and simplify.

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Step 1.2.1

Divide each term in $2 y = 6 + x$ by $2$ .

$\frac{2 y}{2} = \frac{6}{2} + \frac{x}{2}$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $2$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{2 y}{2} = \frac{6}{2} + \frac{x}{2}$

Step 1.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{6}{2} + \frac{x}{2}$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Divide $6$ by $2$ .

$y = 3 + \frac{x}{2}$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

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Step 3.1

Remove parentheses.

$y = 3 + \frac{0}{2}$

Step 3.2

Simplify $3 + \frac{0}{2}$ .

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Step 3.2.1

Divide $0$ by $2$ .

$y = 3 + 0$

Step 3.2.2

Add $3$ and $0$ .

$y = 3$

Step 3.3

Use the $x$ and $y$ values to form the ordered pair.

$(0, 3)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Step 4.1

Remove parentheses.

$y = 3 + \frac{1}{2}$

Step 4.2

Simplify $3 + \frac{1}{2}$ .

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Step 4.2.1

To write $3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = 3 \cdot \frac{2}{2} + \frac{1}{2}$

Step 4.2.2

Combine $3$ and $\frac{2}{2}$ .

$y = \frac{3 \cdot 2}{2} + \frac{1}{2}$

Step 4.2.3

Combine the numerators over the common denominator.

$y = \frac{3 \cdot 2 + 1}{2}$

Step 4.2.4

Simplify the numerator.

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Step 4.2.4.1

Multiply $3$ by $2$ .

$y = \frac{6 + 1}{2}$

Step 4.2.4.2

Add $6$ and $1$ .

$y = \frac{7}{2}$

Step 4.3

Use the $x$ and $y$ values to form the ordered pair.

$(1, \frac{7}{2})$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

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Step 5.1

Remove parentheses.

$y = 3 + \frac{2}{2}$

Step 5.2

Simplify $3 + \frac{2}{2}$ .

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Step 5.2.1

Divide $2$ by $2$ .

$y = 3 + 1$

Step 5.2.2

Add $3$ and $1$ .

$y = 4$

Step 5.3

Use the $x$ and $y$ values to form the ordered pair.

$(2, 4)$

Step 6

These are three possible solutions to the equation.

$(0, 3), (1, \frac{7}{2}), (2, 4)$

Step 7