Pre-Algebra Examples

2 (x + 4) + 8 = 32

$2 (x + 4) + 8 = 32$

Step 1

Simplify

2 (x + 4) + 8

$2 (x + 4) + 8$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

2 x + 2 \cdot 4 + 8 = 32

$2 x + 2 \cdot 4 + 8 = 32$

Step 1.1.2

Multiply

2

$2$ by

4

$4$ .

2 x + 8 + 8 = 32

$2 x + 8 + 8 = 32$

2 x + 8 + 8 = 32

$2 x + 8 + 8 = 32$

Step 1.2

Add

8

$8$ and

8

$8$ .

2 x + 16 = 32

$2 x + 16 = 32$

2 x + 16 = 32

$2 x + 16 = 32$

Step 2

Move all terms not containing

x

$x$ to the right side of the equation.

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Step 2.1

Subtract

16

$16$ from both sides of the equation.

2 x = 32 - 16

$2 x = 32 - 16$

Step 2.2

Subtract

16

$16$ from

32

$32$ .

2 x = 16

$2 x = 16$

2 x = 16

$2 x = 16$

Step 3

Divide each term in

2 x = 16

$2 x = 16$ by

2

$2$ and simplify.

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Step 3.1

Divide each term in

2 x = 16

$2 x = 16$ by

2

$2$ .

\frac{2 x}{2} = \frac{16}{2}

$\frac{2 x}{2} = \frac{16}{2}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of

2

$2$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{16}{2}$

Step 3.2.1.2

Divide

$x$ by

$1$ .

$x = \frac{16}{2}$

$x = \frac{16}{2}$

$x = \frac{16}{2}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide

$16$ by

$2$ .

$x = 8$

$x = 8$

$x = 8$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$