Pre-Algebra Examples

4 (2 x + 5) - 8 = 36

$4 (2 x + 5) - 8 = 36$

Step 1

Simplify

4 (2 x + 5) - 8

$4 (2 x + 5) - 8$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

4 (2 x) + 4 \cdot 5 - 8 = 36

$4 (2 x) + 4 \cdot 5 - 8 = 36$

Step 1.1.2

Multiply

2

$2$ by

4

$4$ .

8 x + 4 \cdot 5 - 8 = 36

$8 x + 4 \cdot 5 - 8 = 36$

Step 1.1.3

Multiply

4

$4$ by

5

$5$ .

8 x + 20 - 8 = 36

$8 x + 20 - 8 = 36$

8 x + 20 - 8 = 36

$8 x + 20 - 8 = 36$

Step 1.2

Subtract

8

$8$ from

20

$20$ .

8 x + 12 = 36

$8 x + 12 = 36$

8 x + 12 = 36

$8 x + 12 = 36$

Step 2

Move all terms not containing

x

$x$ to the right side of the equation.

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Step 2.1

Subtract

12

$12$ from both sides of the equation.

8 x = 36 - 12

$8 x = 36 - 12$

Step 2.2

Subtract

12

$12$ from

36

$36$ .

8 x = 24

$8 x = 24$

8 x = 24

$8 x = 24$

Step 3

Divide each term in

8 x = 24

$8 x = 24$ by

8

$8$ and simplify.

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Step 3.1

Divide each term in

8 x = 24

$8 x = 24$ by

8

$8$ .

\frac{8 x}{8} = \frac{24}{8}

$\frac{8 x}{8} = \frac{24}{8}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of

8

$8$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{8 x}{8} = \frac{24}{8}$

Step 3.2.1.2

Divide

$x$ by

$1$ .

$x = \frac{24}{8}$

$x = \frac{24}{8}$

$x = \frac{24}{8}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide

$24$ by

$8$ .

$x = 3$

$x = 3$

$x = 3$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$