Pre-Algebra Examples

7 n + 2 = 4 n + 17

$7 n + 2 = 4 n + 17$

Step 1

Move all terms containing

n

$n$ to the left side of the equation.

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Step 1.1

Subtract

4 n

$4 n$ from both sides of the equation.

7 n + 2 - 4 n = 17

$7 n + 2 - 4 n = 17$

Step 1.2

Subtract

4 n

$4 n$ from

7 n

$7 n$ .

3 n + 2 = 17

$3 n + 2 = 17$

3 n + 2 = 17

$3 n + 2 = 17$

Step 2

Move all terms not containing

n

$n$ to the right side of the equation.

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Step 2.1

Subtract

2

$2$ from both sides of the equation.

3 n = 17 - 2

$3 n = 17 - 2$

Step 2.2

Subtract

2

$2$ from

17

$17$ .

3 n = 15

$3 n = 15$

3 n = 15

$3 n = 15$

Step 3

Divide each term in

3 n = 15

$3 n = 15$ by

3

$3$ and simplify.

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Step 3.1

Divide each term in

3 n = 15

$3 n = 15$ by

3

$3$ .

\frac{3 n}{3} = \frac{15}{3}

$\frac{3 n}{3} = \frac{15}{3}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of

3

$3$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{3 n}{3} = \frac{15}{3}$

Step 3.2.1.2

Divide

$n$ by

$1$ .

$n = \frac{15}{3}$

$n = \frac{15}{3}$

$n = \frac{15}{3}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide

$15$ by

$3$ .

$n = 5$

$n = 5$

$n = 5$

$7 n + 2 = 4 n + 17$

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