Pre-Algebra Examples

$28 + 6 t = 7 (t + 4)$

Step 1

Simplify $7 (t + 4)$ .

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Step 1.1

Rewrite.

$28 + 6 t = 0 + 0 + 7 (t + 4)$

Step 1.2

Simplify by adding zeros.

$28 + 6 t = 7 (t + 4)$

Step 1.3

Apply the distributive property.

$28 + 6 t = 7 t + 7 \cdot 4$

Step 1.4

Multiply $7$ by $4$ .

$28 + 6 t = 7 t + 28$

Step 2

Move all terms containing $t$ to the left side of the equation.

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Step 2.1

Subtract $7 t$ from both sides of the equation.

$28 + 6 t - 7 t = 28$

Step 2.2

Subtract $7 t$ from $6 t$ .

$28 - t = 28$

Step 3

Move all terms not containing $t$ to the right side of the equation.

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Step 3.1

Subtract $28$ from both sides of the equation.

$- t = 28 - 28$

Step 3.2

Subtract $28$ from $28$ .

$- t = 0$

Step 4

Divide each term in $- t = 0$ by $- 1$ and simplify.

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Step 4.1

Divide each term in $- t = 0$ by $- 1$ .

$\frac{- t}{- 1} = \frac{0}{- 1}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Dividing two negative values results in a positive value.

$\frac{t}{1} = \frac{0}{- 1}$

Step 4.2.2

Divide $t$ by $1$ .

$t = \frac{0}{- 1}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $0$ by $- 1$ .

$t = 0$