Pre-Algebra Examples

3 (n + 2) < 24

$3 (n + 2) < 24$

Step 1

Divide each term in

3 (n + 2) < 24

$3 (n + 2) < 24$ by

3

$3$ and simplify.

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Step 1.1

Divide each term in

3 (n + 2) < 24

$3 (n + 2) < 24$ by

3

$3$ .

\frac{3 (n + 2)}{3} < \frac{24}{3}

$\frac{3 (n + 2)}{3} < \frac{24}{3}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

3

$3$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{3 (n + 2)}{3} < \frac{24}{3}$

Step 1.2.1.2

Divide

$n + 2$ by

$1$ .

$n + 2 < \frac{24}{3}$

$n + 2 < \frac{24}{3}$

$n + 2 < \frac{24}{3}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide

$24$ by

$3$ .

$n + 2 < 8$

$n + 2 < 8$

$n + 2 < 8$

Step 2

Move all terms not containing

$n$ to the right side of the inequality.

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Step 2.1

Subtract

$2$ from both sides of the inequality.

$n < 8 - 2$

Step 2.2

Subtract

$2$ from

$8$ .

$n < 6$

$n < 6$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$n < 6$

Interval Notation:

$(- \infty, 6)$

$3 (n + 2) < 24$

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