Pre-Algebra Examples

$\frac{16 + 28 \div 2 - 6}{10 - 4 \cdot 2}$

Step 1

Reduce the expression by cancelling the common factors.

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Step 1.1

Cancel the common factor of $28$ and $2$ .

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Step 1.1.1

Factor $2$ out of $28$ .

$\frac{16 + 2 \cdot 14 \div 2 - 6}{10 - 4 \cdot 2}$

Step 1.1.2

Cancel the common factors.

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Step 1.1.2.1

Factor $2$ out of $2$ .

$\frac{16 + 2 \cdot 14 \div 2 (1) - 6}{10 - 4 \cdot 2}$

Step 1.1.2.2

Cancel the common factor.

$\frac{16 + 2 \cdot 14 \div 2 \cdot 1 - 6}{10 - 4 \cdot 2}$

Step 1.1.2.3

Rewrite the expression.

$\frac{16 + \frac{14}{1} - 6}{10 - 4 \cdot 2}$

Step 1.1.2.4

Divide $14$ by $1$ .

$\frac{16 + 14 - 6}{10 - 4 \cdot 2}$

Step 1.2

Cancel the common factor of $16 + 14 - 6$ and $10 - 4 \cdot 2$ .

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Step 1.2.1

Factor $2$ out of $16$ .

$\frac{2 (8) + 14 - 6}{10 - 4 \cdot 2}$

Step 1.2.2

Factor $2$ out of $14$ .

$\frac{2 \cdot 8 + 2 \cdot 7 - 6}{10 - 4 \cdot 2}$

Step 1.2.3

Factor $2$ out of $2 \cdot 8 + 2 \cdot 7$ .

$\frac{2 \cdot (8 + 7) - 6}{10 - 4 \cdot 2}$

Step 1.2.4

Factor $2$ out of $- 6$ .

$\frac{2 \cdot (8 + 7) + 2 (- 3)}{10 - 4 \cdot 2}$

Step 1.2.5

Factor $2$ out of $2 \cdot (8 + 7) + 2 (- 3)$ .

$\frac{2 \cdot (8 + 7 - 3)}{10 - 4 \cdot 2}$

Step 1.2.6

Cancel the common factors.

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Step 1.2.6.1

Factor $2$ out of $10$ .

$\frac{2 \cdot (8 + 7 - 3)}{2 (5) - 4 \cdot 2}$

Step 1.2.6.2

Factor $2$ out of $- 4 \cdot 2$ .

$\frac{2 \cdot (8 + 7 - 3)}{2 (5) + 2 (- 2 \cdot 2)}$

Step 1.2.6.3

Factor $2$ out of $2 (5) + 2 (- 2 \cdot 2)$ .

$\frac{2 \cdot (8 + 7 - 3)}{2 (5 - 2 \cdot 2)}$

Step 1.2.6.4

Cancel the common factor.

$\frac{2 \cdot (8 + 7 - 3)}{2 (5 - 2 \cdot 2)}$

Step 1.2.6.5

Rewrite the expression.

$\frac{8 + 7 - 3}{5 - 2 \cdot 2}$

Step 2

Simplify the numerator.

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Step 2.1

Add $8$ and $7$ .

$\frac{15 - 3}{5 - 2 \cdot 2}$

Step 2.2

Subtract $3$ from $15$ .

$\frac{12}{5 - 2 \cdot 2}$

Step 3

Simplify the denominator.

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Step 3.1

Multiply $- 2$ by $2$ .

$\frac{12}{5 - 4}$

Step 3.2

Subtract $4$ from $5$ .

$\frac{12}{1}$

Step 4

Divide $12$ by $1$ .

$12$