Linear Algebra Examples

$[\begin{array}{c} x & - 1 \\ 3 & 1 - x \end{array}] = [\begin{array}{c} 1 & 0 & - 3 \\ 2 & x & - 6 \\ 1 & 3 & x - 5 \end{array}]$

Step 1

Subtract $[\begin{array}{c} 1 & 0 & - 3 \\ 2 & x & - 6 \\ 1 & 3 & x - 5 \end{array}]$ from both sides of the equation.

$[\begin{array}{c} x & - 1 \\ 3 & 1 - x \end{array}] - [\begin{array}{c} 1 & 0 & - 3 \\ 2 & x & - 6 \\ 1 & 3 & x - 5 \end{array}] = 0$