Linear Algebra Examples

$i^{167}$

Step 1

Rewrite $i^{167}$ as ${(i^{4})}^{41} (i^{2} \cdot i)$ .

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Step 1.1

Factor out $i^{164}$ .

$i^{164} i^{3}$

Step 1.2

Rewrite $i^{164}$ as ${(i^{4})}^{41}$ .

${(i^{4})}^{41} i^{3}$

Step 1.3

Factor out $i^{2}$ .

${(i^{4})}^{41} (i^{2} \cdot i)$

Step 2

Rewrite $i^{4}$ as $1$ .

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Step 2.1

Rewrite $i^{4}$ as ${(i^{2})}^{2}$ .

${({(i^{2})}^{2})}^{41} (i^{2} \cdot i)$

Step 2.2

Rewrite $i^{2}$ as $- 1$ .

${({(- 1)}^{2})}^{41} (i^{2} \cdot i)$

Step 2.3

Raise $- 1$ to the power of $2$ .

$1^{41} (i^{2} \cdot i)$

Step 3

One to any power is one.

$1 (i^{2} \cdot i)$

Step 4

Multiply $i^{2} \cdot i$ by $1$ .

$i^{2} \cdot i$

Step 5

Rewrite $i^{2}$ as $- 1$ .

$- 1 \cdot i$

Step 6

Rewrite $- 1 i$ as $- i$ .

$- i$

Step 7

This is the trigonometric form of a complex number where $| z |$ is the modulus and $θ$ is the angle created on the complex plane.

$z = a + b i = | z | (\cos (θ) + i \sin (θ))$

Step 8

The modulus of a complex number is the distance from the origin on the complex plane.

$| z | = \sqrt{a^{2} + b^{2}}$ where $z = a + b i$

Step 9

Substitute the actual values of $a = 0$ and $b = - 1$ .

$| z | = \sqrt{{(- 1)}^{2}}$

Step 10

Find $| z |$ .

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Step 10.1

Raise $- 1$ to the power of $2$ .

$| z | = \sqrt{1}$

Step 10.2

Any root of $1$ is $1$ .

$| z | = 1$

Step 11

The angle of the point on the complex plane is the inverse tangent of the complex portion over the real portion.

$θ = \arctan (\frac{- 1}{0})$

Step 12

Since the argument is undefined and $b$ is negative, the angle of the point on the complex plane is $\frac{3 π}{2}$ .

$θ = \frac{3 π}{2}$

Step 13

Substitute the values of $θ = \frac{3 π}{2}$ and $| z | = 1$ .

$\cos (\frac{3 π}{2}) + i \sin (\frac{3 π}{2})$