Linear Algebra Examples

$F V = P V {(1 + 0.0043)}^{60}$

Step 1

Add $1$ and $0.0043$ .

$F V = P V \cdot {1.0043}^{60}$

Step 2

Divide each term in $F V = P V \cdot {1.0043}^{60}$ by $V$ and simplify.

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Step 2.1

Divide each term in $F V = P V \cdot {1.0043}^{60}$ by $V$ .

$\frac{F V}{V} = \frac{P V \cdot {1.0043}^{60}}{V}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $V$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{F V}{V} = \frac{P V \cdot {1.0043}^{60}}{V}$

Step 2.2.1.2

Divide $F$ by $1$ .

$F = \frac{P V \cdot {1.0043}^{60}}{V}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Cancel the common factor of $V$ .

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Step 2.3.1.1

Cancel the common factor.

$F = \frac{P V \cdot {1.0043}^{60}}{V}$

Step 2.3.1.2

Divide $P \cdot {1.0043}^{60}$ by $1$ .

$F = P \cdot {1.0043}^{60}$

Step 2.3.2

Simplify the expression.

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Step 2.3.2.1

Raise $1.0043$ to the power of $60$ .

$F = P \cdot 1.29362309$

Step 2.3.2.2

Move $1.29362309$ to the left of $P$ .

$F = 1.29362309 P$

Step 3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${x | x \in ℝ}$

Step 4