Linear Algebra Examples

$5 a^{2} + 3 b^{2} + 3 d^{2} + 2 a b + 2 a d + 6 b d = 7 g^{2} + 4 h^{2}$

Step 1

Move all the expressions to the left side of the equation.

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Step 1.1

Subtract $7 g^{2}$ from both sides of the equation.

$5 a^{2} + 3 b^{2} + 3 d^{2} + 2 a b + 2 a d + 6 b d - 7 g^{2} = 4 h^{2}$

Step 1.2

Subtract $4 h^{2}$ from both sides of the equation.

$5 a^{2} + 3 b^{2} + 3 d^{2} + 2 a b + 2 a d + 6 b d - 7 g^{2} - 4 h^{2} = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 5$ , $b = 2 b + 2 d$ , and $c = 3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2}$ into the quadratic formula and solve for $a$ .

$\frac{- (2 b + 2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot (5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2}))}}{2 \cdot 5}$

Step 4

Simplify.

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Step 4.1

Simplify the numerator.

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Step 4.1.1

Apply the distributive property.

$a = \frac{- (2 b) - (2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 4.1.2

Multiply $2$ by $- 1$ .

$a = \frac{- 2 b - (2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 4.1.3

Multiply $2$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 4.1.4

Add parentheses.

$a = \frac{- 2 b - 2 d \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot (5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2}))}}{2 \cdot 5}$

Step 4.1.5

Let $u = 5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ . Substitute $u$ for all occurrences of $5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ .

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Step 4.1.5.1

Rewrite ${(2 b + 2 d)}^{2}$ as $(2 b + 2 d) (2 b + 2 d)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{(2 b + 2 d) (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.2

Expand $(2 b + 2 d) (2 b + 2 d)$ using the FOIL Method.

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Step 4.1.5.2.1

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b + 2 d) + 2 d (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.2.2

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b) + 2 b (2 d) + 2 d (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.2.3

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3

Simplify and combine like terms.

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Step 4.1.5.3.1

Simplify each term.

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Step 4.1.5.3.1.1

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 b \cdot b) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.2

Multiply $b$ by $b$ by adding the exponents.

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Step 4.1.5.3.1.2.1

Move $b$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 (b \cdot b)) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.2.2

Multiply $b$ by $b$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 b^{2}) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.3

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.4

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 2 \cdot (2 b d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.5

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.6

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 2 \cdot (2 d b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.7

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.8

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 d \cdot d) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.9

Multiply $d$ by $d$ by adding the exponents.

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Step 4.1.5.3.1.9.1

Move $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 (d \cdot d)) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.9.2

Multiply $d$ by $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 d^{2}) - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.1.10

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.2

Add $4 b d$ and $4 d b$ .

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Step 4.1.5.3.2.1

Move $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 b d + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

Step 4.1.5.3.2.2

Add $4 b d$ and $4 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 8 b d + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 8 b d + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 4.1.6

Factor $4$ out of $4 b^{2} + 8 b d + 4 d^{2} - 4 u$ .

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Step 4.1.6.1

Factor $4$ out of $4 b^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 8 b d + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 4.1.6.2

Factor $4$ out of $8 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 4.1.6.3

Factor $4$ out of $4 d^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 (d^{2}) - 4 u}}{2 \cdot 5}$

Step 4.1.6.4

Factor $4$ out of $- 4 u$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 (d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 4.1.6.5

Factor $4$ out of $4 (b^{2}) + 4 (2 b d)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d) + 4 (d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 4.1.6.6

Factor $4$ out of $4 (b^{2} + 2 b d) + 4 (d^{2})$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 4.1.6.7

Factor $4$ out of $4 (b^{2} + 2 b d + d^{2}) + 4 (- u)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - u)}}{2 \cdot 5}$

Step 4.1.7

Replace all occurrences of $u$ with $5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})))}}{2 \cdot 5}$

Step 4.1.8

Simplify.

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Step 4.1.8.1

Simplify each term.

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Step 4.1.8.1.1

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (5 (3 b^{2}) + 5 (3 d^{2}) + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 4.1.8.1.2

Simplify.

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Step 4.1.8.1.2.1

Multiply $3$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 5 (3 d^{2}) + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 4.1.8.1.2.2

Multiply $3$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 4.1.8.1.2.3

Multiply $6$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 4.1.8.1.2.4

Multiply $- 7$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) - 35 g^{2} + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 4.1.8.1.2.5

Multiply $- 4$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) - 35 g^{2} - 20 h^{2}))}}{2 \cdot 5}$

Step 4.1.8.1.3

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2}) - (15 d^{2}) - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 4.1.8.1.4

Simplify.

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Step 4.1.8.1.4.1

Multiply $15$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - (15 d^{2}) - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 4.1.8.1.4.2

Multiply $15$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 4.1.8.1.4.3

Multiply $30$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 4.1.8.1.4.4

Multiply $- 35$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) + 35 g^{2} - (- 20 h^{2}))}}{2 \cdot 5}$

Step 4.1.8.1.4.5

Multiply $- 20$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 4.1.8.2

Subtract $15 b^{2}$ from $b^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} + 2 b d + d^{2} - 15 d^{2} - 30 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 4.1.8.3

Subtract $30 b d$ from $2 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} + d^{2} - 15 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 4.1.8.4

Subtract $15 d^{2}$ from $d^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 4.1.9

Rewrite $4$ as $2^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2^{2} (- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 4.1.10

Pull terms out from under the radical.

$a = \frac{- 2 b - 2 d \pm 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{2 \cdot 5}$

Step 4.2

Multiply $2$ by $5$ .

$a = \frac{- 2 b - 2 d \pm 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 5

Simplify the expression to solve for the $+$ portion of the $\pm$ .

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Step 5.1

Simplify the numerator.

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Step 5.1.1

Apply the distributive property.

$a = \frac{- (2 b) - (2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 5.1.2

Multiply $2$ by $- 1$ .

$a = \frac{- 2 b - (2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 5.1.3

Multiply $2$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 5.1.4

Add parentheses.

$a = \frac{- 2 b - 2 d \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot (5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2}))}}{2 \cdot 5}$

Step 5.1.5

Let $u = 5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ . Substitute $u$ for all occurrences of $5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ .

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Step 5.1.5.1

Rewrite ${(2 b + 2 d)}^{2}$ as $(2 b + 2 d) (2 b + 2 d)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{(2 b + 2 d) (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.2

Expand $(2 b + 2 d) (2 b + 2 d)$ using the FOIL Method.

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Step 5.1.5.2.1

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b + 2 d) + 2 d (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.2.2

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b) + 2 b (2 d) + 2 d (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.2.3

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3

Simplify and combine like terms.

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Step 5.1.5.3.1

Simplify each term.

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Step 5.1.5.3.1.1

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 b \cdot b) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.2

Multiply $b$ by $b$ by adding the exponents.

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Step 5.1.5.3.1.2.1

Move $b$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 (b \cdot b)) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.2.2

Multiply $b$ by $b$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 b^{2}) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.3

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.4

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 2 \cdot (2 b d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.5

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.6

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 2 \cdot (2 d b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.7

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.8

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 d \cdot d) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.9

Multiply $d$ by $d$ by adding the exponents.

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Step 5.1.5.3.1.9.1

Move $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 (d \cdot d)) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.9.2

Multiply $d$ by $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 d^{2}) - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.1.10

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.2

Add $4 b d$ and $4 d b$ .

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Step 5.1.5.3.2.1

Move $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 b d + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

Step 5.1.5.3.2.2

Add $4 b d$ and $4 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 8 b d + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 8 b d + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 5.1.6

Factor $4$ out of $4 b^{2} + 8 b d + 4 d^{2} - 4 u$ .

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Step 5.1.6.1

Factor $4$ out of $4 b^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 8 b d + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 5.1.6.2

Factor $4$ out of $8 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 5.1.6.3

Factor $4$ out of $4 d^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 (d^{2}) - 4 u}}{2 \cdot 5}$

Step 5.1.6.4

Factor $4$ out of $- 4 u$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 (d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 5.1.6.5

Factor $4$ out of $4 (b^{2}) + 4 (2 b d)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d) + 4 (d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 5.1.6.6

Factor $4$ out of $4 (b^{2} + 2 b d) + 4 (d^{2})$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 5.1.6.7

Factor $4$ out of $4 (b^{2} + 2 b d + d^{2}) + 4 (- u)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - u)}}{2 \cdot 5}$

Step 5.1.7

Replace all occurrences of $u$ with $5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})))}}{2 \cdot 5}$

Step 5.1.8

Simplify.

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Step 5.1.8.1

Simplify each term.

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Step 5.1.8.1.1

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (5 (3 b^{2}) + 5 (3 d^{2}) + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 5.1.8.1.2

Simplify.

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Step 5.1.8.1.2.1

Multiply $3$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 5 (3 d^{2}) + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 5.1.8.1.2.2

Multiply $3$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 5.1.8.1.2.3

Multiply $6$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 5.1.8.1.2.4

Multiply $- 7$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) - 35 g^{2} + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 5.1.8.1.2.5

Multiply $- 4$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) - 35 g^{2} - 20 h^{2}))}}{2 \cdot 5}$

Step 5.1.8.1.3

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2}) - (15 d^{2}) - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 5.1.8.1.4

Simplify.

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Step 5.1.8.1.4.1

Multiply $15$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - (15 d^{2}) - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 5.1.8.1.4.2

Multiply $15$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 5.1.8.1.4.3

Multiply $30$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 5.1.8.1.4.4

Multiply $- 35$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) + 35 g^{2} - (- 20 h^{2}))}}{2 \cdot 5}$

Step 5.1.8.1.4.5

Multiply $- 20$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 5.1.8.2

Subtract $15 b^{2}$ from $b^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} + 2 b d + d^{2} - 15 d^{2} - 30 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 5.1.8.3

Subtract $30 b d$ from $2 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} + d^{2} - 15 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 5.1.8.4

Subtract $15 d^{2}$ from $d^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 5.1.9

Rewrite $4$ as $2^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2^{2} (- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 5.1.10

Pull terms out from under the radical.

$a = \frac{- 2 b - 2 d \pm 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{2 \cdot 5}$

Step 5.2

Multiply $2$ by $5$ .

$a = \frac{- 2 b - 2 d \pm 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 5.3

Change the $\pm$ to $+$ .

$a = \frac{- 2 b - 2 d + 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 5.4

Cancel the common factor of $- 2 b - 2 d + 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ and $10$ .

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Step 5.4.1

Factor $2$ out of $- 2 b$ .

$a = \frac{2 (- b) - 2 d + 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 5.4.2

Factor $2$ out of $- 2 d$ .

$a = \frac{2 (- b) + 2 (- d) + 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 5.4.3

Factor $2$ out of $2 (- b) + 2 (- d)$ .

$a = \frac{2 (- b - d) + 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 5.4.4

Factor $2$ out of $2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ .

$a = \frac{2 (- b - d) + 2 (\sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{10}$

Step 5.4.5

Factor $2$ out of $2 (- b - d) + 2 (\sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ .

$a = \frac{2 (- b - d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{10}$

Step 5.4.6

Cancel the common factors.

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Step 5.4.6.1

Factor $2$ out of $10$ .

$a = \frac{2 (- b - d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{2 (5)}$

Step 5.4.6.2

Cancel the common factor.

$a = \frac{2 (- b - d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{2 \cdot 5}$

Step 5.4.6.3

Rewrite the expression.

$a = \frac{- b - d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 5.5

Factor $- 1$ out of $- b$ .

$a = \frac{- (b) - d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 5.6

Factor $- 1$ out of $- d$ .

$a = \frac{- (b) - (d) + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 5.7

Factor $- 1$ out of $- (b) - (d)$ .

$a = \frac{- (b + d) + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 5.8

Factor $- 1$ out of $\sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ .

$a = \frac{- (b + d) - 1 (- \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{5}$

Step 5.9

Factor $- 1$ out of $- (b + d) - 1 (- \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ .

$a = \frac{- (b + d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{5}$

Step 5.10

Rewrite $- (b + d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ as $- 1 (b + d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ .

$a = \frac{- 1 (b + d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{5}$

Step 5.11

Move the negative in front of the fraction.

$a = - \frac{b + d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 6

Simplify the expression to solve for the $-$ portion of the $\pm$ .

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Step 6.1

Simplify the numerator.

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Step 6.1.1

Apply the distributive property.

$a = \frac{- (2 b) - (2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 6.1.2

Multiply $2$ by $- 1$ .

$a = \frac{- 2 b - (2 d) \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 6.1.3

Multiply $2$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot 5 \cdot (3 b^{2} + 3 d^{2} + 6 b d - 7 g^{2} - 4 h^{2})}}{2 \cdot 5}$

Step 6.1.4

Add parentheses.

$a = \frac{- 2 b - 2 d \pm \sqrt{{(2 b + 2 d)}^{2} - 4 \cdot (5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2}))}}{2 \cdot 5}$

Step 6.1.5

Let $u = 5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ . Substitute $u$ for all occurrences of $5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ .

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Step 6.1.5.1

Rewrite ${(2 b + 2 d)}^{2}$ as $(2 b + 2 d) (2 b + 2 d)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{(2 b + 2 d) (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.2

Expand $(2 b + 2 d) (2 b + 2 d)$ using the FOIL Method.

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Step 6.1.5.2.1

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b + 2 d) + 2 d (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.2.2

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b) + 2 b (2 d) + 2 d (2 b + 2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.2.3

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 b (2 b) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3

Simplify and combine like terms.

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Step 6.1.5.3.1

Simplify each term.

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Step 6.1.5.3.1.1

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 b \cdot b) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.2

Multiply $b$ by $b$ by adding the exponents.

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Step 6.1.5.3.1.2.1

Move $b$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 (b \cdot b)) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.2.2

Multiply $b$ by $b$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2 \cdot (2 b^{2}) + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.3

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 2 b (2 d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.4

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 2 \cdot (2 b d) + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.5

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 2 d (2 b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.6

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 2 \cdot (2 d b) + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.7

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 d (2 d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.8

Rewrite using the commutative property of multiplication.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 d \cdot d) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.9

Multiply $d$ by $d$ by adding the exponents.

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Step 6.1.5.3.1.9.1

Move $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 (d \cdot d)) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.9.2

Multiply $d$ by $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 2 \cdot (2 d^{2}) - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.1.10

Multiply $2$ by $2$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 d b + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.2

Add $4 b d$ and $4 d b$ .

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Step 6.1.5.3.2.1

Move $d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 4 b d + 4 b d + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

Step 6.1.5.3.2.2

Add $4 b d$ and $4 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 8 b d + 4 d^{2} - 4 \cdot u}}{2 \cdot 5}$

$a = \frac{- 2 b - 2 d \pm \sqrt{4 b^{2} + 8 b d + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 6.1.6

Factor $4$ out of $4 b^{2} + 8 b d + 4 d^{2} - 4 u$ .

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Step 6.1.6.1

Factor $4$ out of $4 b^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 8 b d + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 6.1.6.2

Factor $4$ out of $8 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 d^{2} - 4 u}}{2 \cdot 5}$

Step 6.1.6.3

Factor $4$ out of $4 d^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 (d^{2}) - 4 u}}{2 \cdot 5}$

Step 6.1.6.4

Factor $4$ out of $- 4 u$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2}) + 4 (2 b d) + 4 (d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 6.1.6.5

Factor $4$ out of $4 (b^{2}) + 4 (2 b d)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d) + 4 (d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 6.1.6.6

Factor $4$ out of $4 (b^{2} + 2 b d) + 4 (d^{2})$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2}) + 4 (- u)}}{2 \cdot 5}$

Step 6.1.6.7

Factor $4$ out of $4 (b^{2} + 2 b d + d^{2}) + 4 (- u)$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - u)}}{2 \cdot 5}$

Step 6.1.7

Replace all occurrences of $u$ with $5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (5 \cdot (3 b^{2} + 3 d^{2} + 6 (b d) - 7 g^{2} - 4 h^{2})))}}{2 \cdot 5}$

Step 6.1.8

Simplify.

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Step 6.1.8.1

Simplify each term.

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Step 6.1.8.1.1

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (5 (3 b^{2}) + 5 (3 d^{2}) + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 6.1.8.1.2

Simplify.

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Step 6.1.8.1.2.1

Multiply $3$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 5 (3 d^{2}) + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 6.1.8.1.2.2

Multiply $3$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 5 (6 b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 6.1.8.1.2.3

Multiply $6$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) + 5 (- 7 g^{2}) + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 6.1.8.1.2.4

Multiply $- 7$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) - 35 g^{2} + 5 (- 4 h^{2})))}}{2 \cdot 5}$

Step 6.1.8.1.2.5

Multiply $- 4$ by $5$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2} + 15 d^{2} + 30 (b d) - 35 g^{2} - 20 h^{2}))}}{2 \cdot 5}$

Step 6.1.8.1.3

Apply the distributive property.

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - (15 b^{2}) - (15 d^{2}) - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 6.1.8.1.4

Simplify.

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Step 6.1.8.1.4.1

Multiply $15$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - (15 d^{2}) - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 6.1.8.1.4.2

Multiply $15$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - (30 b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 6.1.8.1.4.3

Multiply $30$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) - (- 35 g^{2}) - (- 20 h^{2}))}}{2 \cdot 5}$

Step 6.1.8.1.4.4

Multiply $- 35$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) + 35 g^{2} - (- 20 h^{2}))}}{2 \cdot 5}$

Step 6.1.8.1.4.5

Multiply $- 20$ by $- 1$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 (b d) + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (b^{2} + 2 b d + d^{2} - 15 b^{2} - 15 d^{2} - 30 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 6.1.8.2

Subtract $15 b^{2}$ from $b^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} + 2 b d + d^{2} - 15 d^{2} - 30 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 6.1.8.3

Subtract $30 b d$ from $2 b d$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} + d^{2} - 15 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 6.1.8.4

Subtract $15 d^{2}$ from $d^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{4 (- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 6.1.9

Rewrite $4$ as $2^{2}$ .

$a = \frac{- 2 b - 2 d \pm \sqrt{2^{2} (- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2})}}{2 \cdot 5}$

Step 6.1.10

Pull terms out from under the radical.

$a = \frac{- 2 b - 2 d \pm 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{2 \cdot 5}$

Step 6.2

Multiply $2$ by $5$ .

$a = \frac{- 2 b - 2 d \pm 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 6.3

Change the $\pm$ to $-$ .

$a = \frac{- 2 b - 2 d - 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 6.4

Cancel the common factor of $- 2 b - 2 d - 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ and $10$ .

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Step 6.4.1

Factor $2$ out of $- 2 b$ .

$a = \frac{2 (- b) - 2 d - 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 6.4.2

Factor $2$ out of $- 2 d$ .

$a = \frac{2 (- b) + 2 (- d) - 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 6.4.3

Factor $2$ out of $2 (- b) + 2 (- d)$ .

$a = \frac{2 (- b - d) - 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{10}$

Step 6.4.4

Factor $2$ out of $- 2 \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ .

$a = \frac{2 (- b - d) + 2 (- \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{10}$

Step 6.4.5

Factor $2$ out of $2 (- b - d) + 2 (- \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ .

$a = \frac{2 (- b - d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{10}$

Step 6.4.6

Cancel the common factors.

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Step 6.4.6.1

Factor $2$ out of $10$ .

$a = \frac{2 (- b - d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{2 (5)}$

Step 6.4.6.2

Cancel the common factor.

$a = \frac{2 (- b - d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{2 \cdot 5}$

Step 6.4.6.3

Rewrite the expression.

$a = \frac{- b - d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 6.5

Factor $- 1$ out of $- b$ .

$a = \frac{- (b) - d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 6.6

Factor $- 1$ out of $- d$ .

$a = \frac{- (b) - (d) - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 6.7

Factor $- 1$ out of $- (b) - (d)$ .

$a = \frac{- (b + d) - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 6.8

Factor $- 1$ out of $- \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ .

$a = \frac{- (b + d) - (\sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{5}$

Step 6.9

Factor $- 1$ out of $- (b + d) - (\sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ .

$a = \frac{- (b + d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{5}$

Step 6.10

Rewrite $- (b + d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ as $- 1 (b + d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})$ .

$a = \frac{- 1 (b + d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}})}{5}$

Step 6.11

Move the negative in front of the fraction.

$a = - \frac{b + d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 7

The final answer is the combination of both solutions.

$a = - \frac{b + d - \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

$a = - \frac{b + d + \sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}}{5}$

Step 8

Set the radicand in $\sqrt{- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2}}$ greater than or equal to $0$ to find where the expression is defined.

$- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2} \geq 0$

Step 9

Solve for $b$ .

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Step 9.1

Convert the inequality to an equation.

$- 14 b^{2} - 14 d^{2} - 28 b d + 35 g^{2} + 20 h^{2} = 0$

Step 9.2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 9.3

Substitute the values $a = - 14$ , $b = - 28 d$ , and $c = - 14 d^{2} + 35 g^{2} + 20 h^{2}$ into the quadratic formula and solve for $b$ .

$\frac{28 d \pm \sqrt{{(- 28 d)}^{2} - 4 \cdot (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2}))}}{2 \cdot - 14}$

Step 9.4

Simplify.

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Step 9.4.1

Simplify the numerator.

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Step 9.4.1.1

Add parentheses.

$b = \frac{28 d \pm \sqrt{{(- 28 d)}^{2} - 4 \cdot (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.2

Let $u = - 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ . Substitute $u$ for all occurrences of $- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ .

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Step 9.4.1.2.1

Apply the product rule to $- 28 d$ .

$b = \frac{28 d \pm \sqrt{{(- 28)}^{2} d^{2} - 4 \cdot u}}{2 \cdot - 14}$

Step 9.4.1.2.2

Raise $- 28$ to the power of $2$ .

$b = \frac{28 d \pm \sqrt{784 d^{2} - 4 u}}{2 \cdot - 14}$

Step 9.4.1.3

Factor $4$ out of $784 d^{2} - 4 u$ .

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Step 9.4.1.3.1

Factor $4$ out of $784 d^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2}) - 4 u}}{2 \cdot - 14}$

Step 9.4.1.3.2

Factor $4$ out of $- 4 u$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2}) + 4 (- u)}}{2 \cdot - 14}$

Step 9.4.1.3.3

Factor $4$ out of $4 (196 d^{2}) + 4 (- u)$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - u)}}{2 \cdot - 14}$

Step 9.4.1.4

Replace all occurrences of $u$ with $- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})))}}{2 \cdot - 14}$

Step 9.4.1.5

Simplify.

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Step 9.4.1.5.1

Simplify each term.

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Step 9.4.1.5.1.1

Apply the distributive property.

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (- 14 (- 14 d^{2}) - 14 (35 g^{2}) - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.4.1.5.1.2

Simplify.

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Step 9.4.1.5.1.2.1

Multiply $- 14$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 14 (35 g^{2}) - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.4.1.5.1.2.2

Multiply $35$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 490 g^{2} - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.4.1.5.1.2.3

Multiply $20$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 490 g^{2} - 280 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.5.1.3

Apply the distributive property.

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2}) - (- 490 g^{2}) - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.5.1.4

Simplify.

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Step 9.4.1.5.1.4.1

Multiply $196$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} - (- 490 g^{2}) - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.5.1.4.2

Multiply $- 490$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} + 490 g^{2} - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.5.1.4.3

Multiply $- 280$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} + 490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.4.1.5.2

Subtract $196 d^{2}$ from $196 d^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (0 + 490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.4.1.5.3

Add $0$ and $490 g^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.4.1.6

Factor $70$ out of $490 g^{2} + 280 h^{2}$ .

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Step 9.4.1.6.1

Factor $70$ out of $490 g^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2}) + 280 h^{2})}}{2 \cdot - 14}$

Step 9.4.1.6.2

Factor $70$ out of $280 h^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2}) + 70 (4 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.6.3

Factor $70$ out of $70 (7 g^{2}) + 70 (4 h^{2})$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

$b = \frac{28 d \pm \sqrt{4 \cdot (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.7

Multiply $4$ by $70$ .

$b = \frac{28 d \pm \sqrt{280 (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.4.1.8

Rewrite $280 (7 g^{2} + 4 h^{2})$ as $2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))$ .

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Step 9.4.1.8.1

Factor $4$ out of $280$ .

$b = \frac{28 d \pm \sqrt{4 (70) (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.4.1.8.2

Rewrite $4$ as $2^{2}$ .

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

Step 9.4.1.8.3

Rewrite $4 h^{2}$ as ${(2 h)}^{2}$ .

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))}}{2 \cdot - 14}$

Step 9.4.1.8.4

Add parentheses.

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))}}{2 \cdot - 14}$

Step 9.4.1.9

Pull terms out from under the radical.

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + {(2 h)}^{2})}}{2 \cdot - 14}$

Step 9.4.1.10

Apply the product rule to $2 h$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 2^{2} h^{2})}}{2 \cdot - 14}$

Step 9.4.1.11

Raise $2$ to the power of $2$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.4.2

Multiply $2$ by $- 14$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 28}$

Step 9.4.3

Simplify $\frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 28}$ .

$b = \frac{14 d \pm \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 14}$

Step 9.4.4

Move the negative in front of the fraction.

$b = - \frac{14 d \pm \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

Step 9.5

Simplify the expression to solve for the $+$ portion of the $\pm$ .

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Step 9.5.1

Simplify the numerator.

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Step 9.5.1.1

Add parentheses.

$b = \frac{28 d \pm \sqrt{{(- 28 d)}^{2} - 4 \cdot (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.2

Let $u = - 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ . Substitute $u$ for all occurrences of $- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ .

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Step 9.5.1.2.1

Apply the product rule to $- 28 d$ .

$b = \frac{28 d \pm \sqrt{{(- 28)}^{2} d^{2} - 4 \cdot u}}{2 \cdot - 14}$

Step 9.5.1.2.2

Raise $- 28$ to the power of $2$ .

$b = \frac{28 d \pm \sqrt{784 d^{2} - 4 u}}{2 \cdot - 14}$

Step 9.5.1.3

Factor $4$ out of $784 d^{2} - 4 u$ .

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Step 9.5.1.3.1

Factor $4$ out of $784 d^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2}) - 4 u}}{2 \cdot - 14}$

Step 9.5.1.3.2

Factor $4$ out of $- 4 u$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2}) + 4 (- u)}}{2 \cdot - 14}$

Step 9.5.1.3.3

Factor $4$ out of $4 (196 d^{2}) + 4 (- u)$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - u)}}{2 \cdot - 14}$

Step 9.5.1.4

Replace all occurrences of $u$ with $- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})))}}{2 \cdot - 14}$

Step 9.5.1.5

Simplify.

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Step 9.5.1.5.1

Simplify each term.

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Step 9.5.1.5.1.1

Apply the distributive property.

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (- 14 (- 14 d^{2}) - 14 (35 g^{2}) - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.5.1.5.1.2

Simplify.

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Step 9.5.1.5.1.2.1

Multiply $- 14$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 14 (35 g^{2}) - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.5.1.5.1.2.2

Multiply $35$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 490 g^{2} - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.5.1.5.1.2.3

Multiply $20$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 490 g^{2} - 280 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.5.1.3

Apply the distributive property.

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2}) - (- 490 g^{2}) - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.5.1.4

Simplify.

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Step 9.5.1.5.1.4.1

Multiply $196$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} - (- 490 g^{2}) - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.5.1.4.2

Multiply $- 490$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} + 490 g^{2} - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.5.1.4.3

Multiply $- 280$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} + 490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.5.1.5.2

Subtract $196 d^{2}$ from $196 d^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (0 + 490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.5.1.5.3

Add $0$ and $490 g^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.5.1.6

Factor $70$ out of $490 g^{2} + 280 h^{2}$ .

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Step 9.5.1.6.1

Factor $70$ out of $490 g^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2}) + 280 h^{2})}}{2 \cdot - 14}$

Step 9.5.1.6.2

Factor $70$ out of $280 h^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2}) + 70 (4 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.6.3

Factor $70$ out of $70 (7 g^{2}) + 70 (4 h^{2})$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

$b = \frac{28 d \pm \sqrt{4 \cdot (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.7

Multiply $4$ by $70$ .

$b = \frac{28 d \pm \sqrt{280 (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.5.1.8

Rewrite $280 (7 g^{2} + 4 h^{2})$ as $2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))$ .

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Step 9.5.1.8.1

Factor $4$ out of $280$ .

$b = \frac{28 d \pm \sqrt{4 (70) (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.5.1.8.2

Rewrite $4$ as $2^{2}$ .

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

Step 9.5.1.8.3

Rewrite $4 h^{2}$ as ${(2 h)}^{2}$ .

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))}}{2 \cdot - 14}$

Step 9.5.1.8.4

Add parentheses.

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))}}{2 \cdot - 14}$

Step 9.5.1.9

Pull terms out from under the radical.

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + {(2 h)}^{2})}}{2 \cdot - 14}$

Step 9.5.1.10

Apply the product rule to $2 h$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 2^{2} h^{2})}}{2 \cdot - 14}$

Step 9.5.1.11

Raise $2$ to the power of $2$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.5.2

Multiply $2$ by $- 14$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 28}$

Step 9.5.3

Simplify $\frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 28}$ .

$b = \frac{14 d \pm \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 14}$

Step 9.5.4

Move the negative in front of the fraction.

$b = - \frac{14 d \pm \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

Step 9.5.5

Change the $\pm$ to $+$ .

$b = - \frac{14 d + \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

Step 9.6

Simplify the expression to solve for the $-$ portion of the $\pm$ .

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Step 9.6.1

Simplify the numerator.

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Step 9.6.1.1

Add parentheses.

$b = \frac{28 d \pm \sqrt{{(- 28 d)}^{2} - 4 \cdot (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.2

Let $u = - 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ . Substitute $u$ for all occurrences of $- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ .

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Step 9.6.1.2.1

Apply the product rule to $- 28 d$ .

$b = \frac{28 d \pm \sqrt{{(- 28)}^{2} d^{2} - 4 \cdot u}}{2 \cdot - 14}$

Step 9.6.1.2.2

Raise $- 28$ to the power of $2$ .

$b = \frac{28 d \pm \sqrt{784 d^{2} - 4 u}}{2 \cdot - 14}$

Step 9.6.1.3

Factor $4$ out of $784 d^{2} - 4 u$ .

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Step 9.6.1.3.1

Factor $4$ out of $784 d^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2}) - 4 u}}{2 \cdot - 14}$

Step 9.6.1.3.2

Factor $4$ out of $- 4 u$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2}) + 4 (- u)}}{2 \cdot - 14}$

Step 9.6.1.3.3

Factor $4$ out of $4 (196 d^{2}) + 4 (- u)$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - u)}}{2 \cdot - 14}$

Step 9.6.1.4

Replace all occurrences of $u$ with $- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (- 14 \cdot (- 14 d^{2} + 35 g^{2} + 20 h^{2})))}}{2 \cdot - 14}$

Step 9.6.1.5

Simplify.

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Step 9.6.1.5.1

Simplify each term.

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Step 9.6.1.5.1.1

Apply the distributive property.

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (- 14 (- 14 d^{2}) - 14 (35 g^{2}) - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.6.1.5.1.2

Simplify.

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Step 9.6.1.5.1.2.1

Multiply $- 14$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 14 (35 g^{2}) - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.6.1.5.1.2.2

Multiply $35$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 490 g^{2} - 14 (20 h^{2})))}}{2 \cdot - 14}$

Step 9.6.1.5.1.2.3

Multiply $20$ by $- 14$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2} - 490 g^{2} - 280 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.5.1.3

Apply the distributive property.

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - (196 d^{2}) - (- 490 g^{2}) - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.5.1.4

Simplify.

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Step 9.6.1.5.1.4.1

Multiply $196$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} - (- 490 g^{2}) - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.5.1.4.2

Multiply $- 490$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} + 490 g^{2} - (- 280 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.5.1.4.3

Multiply $- 280$ by $- 1$ .

$b = \frac{28 d \pm \sqrt{4 (196 d^{2} - 196 d^{2} + 490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.6.1.5.2

Subtract $196 d^{2}$ from $196 d^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (0 + 490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.6.1.5.3

Add $0$ and $490 g^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (490 g^{2} + 280 h^{2})}}{2 \cdot - 14}$

Step 9.6.1.6

Factor $70$ out of $490 g^{2} + 280 h^{2}$ .

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Step 9.6.1.6.1

Factor $70$ out of $490 g^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2}) + 280 h^{2})}}{2 \cdot - 14}$

Step 9.6.1.6.2

Factor $70$ out of $280 h^{2}$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2}) + 70 (4 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.6.3

Factor $70$ out of $70 (7 g^{2}) + 70 (4 h^{2})$ .

$b = \frac{28 d \pm \sqrt{4 (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

$b = \frac{28 d \pm \sqrt{4 \cdot (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.7

Multiply $4$ by $70$ .

$b = \frac{28 d \pm \sqrt{280 (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.6.1.8

Rewrite $280 (7 g^{2} + 4 h^{2})$ as $2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))$ .

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Step 9.6.1.8.1

Factor $4$ out of $280$ .

$b = \frac{28 d \pm \sqrt{4 (70) (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.6.1.8.2

Rewrite $4$ as $2^{2}$ .

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + 4 h^{2}))}}{2 \cdot - 14}$

Step 9.6.1.8.3

Rewrite $4 h^{2}$ as ${(2 h)}^{2}$ .

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))}}{2 \cdot - 14}$

Step 9.6.1.8.4

Add parentheses.

$b = \frac{28 d \pm \sqrt{2^{2} \cdot (70 (7 g^{2} + {(2 h)}^{2}))}}{2 \cdot - 14}$

Step 9.6.1.9

Pull terms out from under the radical.

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + {(2 h)}^{2})}}{2 \cdot - 14}$

Step 9.6.1.10

Apply the product rule to $2 h$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 2^{2} h^{2})}}{2 \cdot - 14}$

Step 9.6.1.11

Raise $2$ to the power of $2$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{2 \cdot - 14}$

Step 9.6.2

Multiply $2$ by $- 14$ .

$b = \frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 28}$

Step 9.6.3

Simplify $\frac{28 d \pm 2 \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 28}$ .

$b = \frac{14 d \pm \sqrt{70 (7 g^{2} + 4 h^{2})}}{- 14}$

Step 9.6.4

Move the negative in front of the fraction.

$b = - \frac{14 d \pm \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

Step 9.6.5

Change the $\pm$ to $-$ .

$b = - \frac{14 d - \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

Step 9.7

Consolidate the solutions.

$b = - \frac{14 d + \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

$b = - \frac{14 d - \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

$b = - \frac{14 d + \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

$b = - \frac{14 d - \sqrt{70 (7 g^{2} + 4 h^{2})}}{14}$

Step 10

The domain is all real numbers.

Interval Notation:

$(- \infty, \infty)$

Set-Builder Notation:

${b | b \in ℝ}$