Linear Algebra Examples

$\sqrt{7 x} = 35$

Step 1

Set the radicand in $\sqrt{7 x}$ greater than or equal to $0$ to find where the expression is defined.

$7 x \geq 0$

Step 2

Divide each term in $7 x \geq 0$ by $7$ and simplify.

Tap for more steps...

Step 2.1

Divide each term in $7 x \geq 0$ by $7$ .

$\frac{7 x}{7} \geq \frac{0}{7}$

Step 2.2

Simplify the left side.

Tap for more steps...

Step 2.2.1

Cancel the common factor of $7$ .

Tap for more steps...

Step 2.2.1.1

Cancel the common factor.

$\frac{7 x}{7} \geq \frac{0}{7}$

Step 2.2.1.2

Divide $x$ by $1$ .

$x \geq \frac{0}{7}$

Step 2.3

Simplify the right side.

Tap for more steps...

Step 2.3.1

Divide $0$ by $7$ .

$x \geq 0$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[0, \infty)$

Set-Builder Notation:

${x | x \geq 0}$

Step 4