Linear Algebra Examples

$x^{2} - 14 x - 6$

Step 1

Write $x^{2} - 14 x - 6$ as a function.

$f (x) = x^{2} - 14 x - 6$

Step 2

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 3

Set up the integral to solve.

$F (x) = \int x^{2} - 14 x - 6 d x$

Step 4

Split the single integral into multiple integrals.

$\int x^{2} d x + \int - 14 x d x + \int - 6 d x$

Step 5

By the Power Rule, the integral of $x^{2}$ with respect to $x$ is $\frac{1}{3} x^{3}$ .

$\frac{1}{3} x^{3} + C + \int - 14 x d x + \int - 6 d x$

Step 6

Since $- 14$ is constant with respect to $x$ , move $- 14$ out of the integral.

$\frac{1}{3} x^{3} + C - 14 \int x d x + \int - 6 d x$

Step 7

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$\frac{1}{3} x^{3} + C - 14 (\frac{1}{2} x^{2} + C) + \int - 6 d x$

Step 8

Apply the constant rule.

$\frac{1}{3} x^{3} + C - 14 (\frac{1}{2} x^{2} + C) - 6 x + C$

Step 9

Simplify.

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Step 9.1

Combine $\frac{1}{2}$ and $x^{2}$ .

$\frac{1}{3} x^{3} + C - 14 (\frac{x^{2}}{2} + C) - 6 x + C$

Step 9.2

Simplify.

$\frac{x^{3}}{3} - 7 x^{2} - 6 x + C$

Step 9.3

Reorder terms.

$\frac{1}{3} x^{3} - 7 x^{2} - 6 x + C$

Step 10

The answer is the antiderivative of the function $f (x) = x^{2} - 14 x - 6$ .

$F (x) =$ $\frac{1}{3} x^{3} - 7 x^{2} - 6 x + C$