Linear Algebra Examples

axb $[\begin{array}{c} 2 & 0 & 1 \\ 3 & 0 & 0 \\ 5 & 1 & 1 \end{array}] b = [\begin{array}{c} 1 & 0 & 1 \\ 1 & 2 & 1 \\ 1 & 1 & 0 \end{array}]$

Step 1

Reorder factors in $[\begin{array}{c} 2 & 0 & 1 \\ 3 & 0 & 0 \\ 5 & 1 & 1 \end{array}] b = [\begin{array}{c} 1 & 0 & 1 \\ 1 & 2 & 1 \\ 1 & 1 & 0 \end{array}]$ .

$b [\begin{array}{c} 2 & 0 & 1 \\ 3 & 0 & 0 \\ 5 & 1 & 1 \end{array}] = [\begin{array}{c} 1 & 0 & 1 \\ 1 & 2 & 1 \\ 1 & 1 & 0 \end{array}]$

Step 2

Since $x = 0$ produces $y = 2$ and $y = 0$ , the table does not represent a function.

Not a function

Step 3

List all of the solutions.

Step 4

Nothing further can be done with this topic. Please check the expression entered or try another topic.

$[\begin{array}{c} 2 & 0 & 1 \\ 3 & 0 & 0 \\ 5 & 1 & 1 \end{array}] b = [\begin{array}{c} 1 & 0 & 1 \\ 1 & 2 & 1 \\ 1 & 1 & 0 \end{array}]$