Linear Algebra Examples

$(\frac{1}{0.18}) \cdot [\begin{array}{c} 0.6 & - 0.6 \\ - 0.5 & 0.8 \end{array}]$

Step 1

Divide $1$ by $0.18$ .

$5.\overline{5} \cdot [\begin{array}{c} 0.6 & - 0.6 \\ - 0.5 & 0.8 \end{array}]$

Step 2

Multiply $5.\overline{5}$ by each element of the matrix.

$[\begin{array}{c} 5.\overline{5} \cdot 0.6 & 5.\overline{5} \cdot - 0.6 \\ 5.\overline{5} \cdot - 0.5 & 5.\overline{5} \cdot 0.8 \end{array}]$

Step 3

Simplify each element in the matrix.

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Step 3.1

Multiply $5.\overline{5}$ by $0.6$ .

$[\begin{array}{c} 3.\overline{3} & 5.\overline{5} \cdot - 0.6 \\ 5.\overline{5} \cdot - 0.5 & 5.\overline{5} \cdot 0.8 \end{array}]$

Step 3.2

Multiply $5.\overline{5}$ by $- 0.6$ .

$[\begin{array}{c} 3.\overline{3} & - 3.\overline{3} \\ 5.\overline{5} \cdot - 0.5 & 5.\overline{5} \cdot 0.8 \end{array}]$

Step 3.3

Multiply $5.\overline{5}$ by $- 0.5$ .

$[\begin{array}{c} 3.\overline{3} & - 3.\overline{3} \\ - 2.\overline{7} & 5.\overline{5} \cdot 0.8 \end{array}]$

Step 3.4

Multiply $5.\overline{5}$ by $0.8$ .

$[\begin{array}{c} 3.\overline{3} & - 3.\overline{3} \\ - 2.\overline{7} & 4.\overline{4} \end{array}]$