Linear Algebra Examples

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] - 3 [\begin{array}{c} 3 & - 1 & - 1 \\ - \frac{1}{3} & \frac{2}{3} & 0 \end{array}]$

Step 1

Simplify each term.

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Step 1.1

Multiply $- 3$ by each element of the matrix.

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 3 \cdot 3 & - 3 \cdot - 1 & - 3 \cdot - 1 \\ - 3 (- \frac{1}{3}) & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2

Simplify each element in the matrix.

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Step 1.2.1

Multiply $- 3$ by $3$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & - 3 \cdot - 1 & - 3 \cdot - 1 \\ - 3 (- \frac{1}{3}) & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.2

Multiply $- 3$ by $- 1$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & - 3 \cdot - 1 \\ - 3 (- \frac{1}{3}) & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.3

Multiply $- 3$ by $- 1$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ - 3 (- \frac{1}{3}) & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.4

Cancel the common factor of $3$ .

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Step 1.2.4.1

Move the leading negative in $- \frac{1}{3}$ into the numerator.

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ - 3 (\frac{- 1}{3}) & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.4.2

Factor $3$ out of $- 3$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 3 (- 1) \frac{- 1}{3} & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.4.3

Cancel the common factor.

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 3 \cdot - 1 \frac{- 1}{3} & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.4.4

Rewrite the expression.

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ - - 1 & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.5

Multiply $- 1$ by $- 1$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 1 & - 3 (\frac{2}{3}) & - 3 \cdot 0 \end{array}]$

Step 1.2.6

Cancel the common factor of $3$ .

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Step 1.2.6.1

Factor $3$ out of $- 3$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 1 & 3 (- 1) \frac{2}{3} & - 3 \cdot 0 \end{array}]$

Step 1.2.6.2

Cancel the common factor.

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 1 & 3 \cdot - 1 \frac{2}{3} & - 3 \cdot 0 \end{array}]$

Step 1.2.6.3

Rewrite the expression.

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 1 & - 1 \cdot 2 & - 3 \cdot 0 \end{array}]$

Step 1.2.7

Multiply $- 1$ by $2$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 1 & - 2 & - 3 \cdot 0 \end{array}]$

Step 1.2.8

Multiply $- 3$ by $0$ .

$[\begin{array}{c} 2 & 1 & 4 \\ 1 & 2 & 1 \end{array}] + [\begin{array}{c} - 9 & 3 & 3 \\ 1 & - 2 & 0 \end{array}]$

Step 2

Add the corresponding elements.

$[\begin{array}{c} 2 - 9 & 1 + 3 & 4 + 3 \\ 1 + 1 & 2 - 2 & 1 + 0 \end{array}]$

Step 3

Simplify each element.

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Step 3.1

Subtract $9$ from $2$ .

$[\begin{array}{c} - 7 & 1 + 3 & 4 + 3 \\ 1 + 1 & 2 - 2 & 1 + 0 \end{array}]$

Step 3.2

Add $1$ and $3$ .

$[\begin{array}{c} - 7 & 4 & 4 + 3 \\ 1 + 1 & 2 - 2 & 1 + 0 \end{array}]$

Step 3.3

Add $4$ and $3$ .

$[\begin{array}{c} - 7 & 4 & 7 \\ 1 + 1 & 2 - 2 & 1 + 0 \end{array}]$

Step 3.4

Add $1$ and $1$ .

$[\begin{array}{c} - 7 & 4 & 7 \\ 2 & 2 - 2 & 1 + 0 \end{array}]$

Step 3.5

Subtract $2$ from $2$ .

$[\begin{array}{c} - 7 & 4 & 7 \\ 2 & 0 & 1 + 0 \end{array}]$

Step 3.6

Add $1$ and $0$ .

$[\begin{array}{c} - 7 & 4 & 7 \\ 2 & 0 & 1 \end{array}]$